| Equations balanced on the previous day |
4 C + S8 = 4 CS2
Ammoniumdichromate = chromium(iii)oxide + nitrogen + water =>
(NH4)2Cr2O7 = Cr2O3 + N2 + 4 H2O
FeBr3 + Ba(OH)2 = BaBr2 + Fe(OH)3 =>
2 FeBr3 + 3 Ba(OH)2 = 3 BaBr2 + 2 Fe(OH)3
Au + S2O3{2-} + O2 + H2O = [Au(S2O3)2]{3-} + OH{-} =>
4 Au + 8 S2O3{2-} + O2 + 2 H2O = 4[Au(S2O3)2]{3-} + 4 OH{-}
KOH + CH3CH2COOH = KCH3CH2 + COOH + OH =>
KOH + CH3CH2COOH = KCH3CH2 + COOH + OH
C8H7Br + O2 = CO2 + H2O + Br2 =>
4 C8H7Br + 39 O2 = 32 CO2 + 14 H2O + 2 Br2
Ca{2+} + O2CCO2{2-} + H2O = CaC2O4*H2O =>
Ca{2+} + O2CCO2{2-} + H2O = CaC2O4*H2O
SO2 + KMnO4 + H2O = K2SO4 + MnSO2 + H2SO4 =>
9 SO2 + 2 KMnO4 + 6 H2O = K2SO4 + 2 MnSO2 + 6 H2SO4
(CH3OH*C2H5OH) + O2 = CO2 + H2O =>
2(CH3OH*C2H5OH) + 9 O2 = 6 CO2 + 10 H2O
NH4Br + AgNO3 = AgBr + NH4NO3 =>
NH4Br + AgNO3 = AgBr + NH4NO3
PdCl3 + I2 = PdI3 + Cl2 =>
2 PdCl3 + 3 I2 = 2 PdI3 + 3 Cl2
C11H20O10 + O2 = H2O + CO2 =>
C11H20O10 + 11 O2 = 10 H2O + 11 CO2
HClO + Fe(OH)2 = Fe(ClO)2 + H2O =>
2 HClO + Fe(OH)2 = Fe(ClO)2 + 2 H2O
Sn + Na3PO4 = Sn3(PO4)4 + Na =>
3 Sn + 4 Na3PO4 = Sn3(PO4)4 + 12 Na
BaCO3() = BaO() + CO2() =>
BaCO3() = BaO() + CO2()
(NH2)2CO + KNO3 + H2O = NO2 + KOH + CO2 =>
(NH2)2CO + 14 KNO3 + 5 H2O = 16 NO2 + 14 KOH + CO2
Na + O2 = Na2O =>
4 Na + O2 = 2 Na2O
Hg2NO3(g) = Hg2O2(s) + N2O(g) + O2(g) =>
4 Hg2NO3(g) = 4 Hg2O2(s) + 2 N2O(g) + O2(g)
Cr2(SO4)3 + NaBiO3 + HNO3 = NaCrO4 + Bi2(SO4)3 + H2O + NO =>
3 Cr2(SO4)3 + 6 NaBiO3 + 4 HNO3 = 6 NaCrO4 + 3 Bi2(SO4)3 + 2 H2O + 4 NO
AsH3 + KMnO4 + KOH = K3AsO4 + MnO2 + H2O =>
3 AsH3 + 8 KMnO4 + KOH = 3 K3AsO4 + 8 MnO2 + 5 H2O
Cu + NO3 + NH4 = Cu(NH3)4 + H2O =>
5 Cu + 2 NO3 + 18 NH4 = 5 Cu(NH3)4 + 6 H2O
K2Cr2O7(aq) + BaCl2(aq) = BaCr2O7(s) + KCl(aq) =>
K2Cr2O7(aq) + BaCl2(aq) = BaCr2O7(s) + 2 KCl(aq)
Cu + CrO3 + H2SO4 = CuSO4 + Cr2O3 + H2O =>
3 Cu + 2 CrO3 + 3 H2SO4 = 3 CuSO4 + Cr2O3 + 3 H2O
Cu(NO3)2*3H2O + Fe(NO3)3*9H2O + C2H5NO2 = CuFe2O4 + H2O + CO2 + N2 =>
9 Cu(NO3)2*3H2O + 18 Fe(NO3)3*9H2O + 40 C2H5NO2 = 9 CuFe2O4 + 289 H2O + 80 CO2 + 56 N2
C19H16 + Br2 = C19H15 + HBr =>
2 C19H16 + Br2 = 2 C19H15 + 2 HBr
(NH4)2(SO4) + Al(OH)3 = NH3 + H2O + Al2(SO4)3 =>
3(NH4)2(SO4) + 2 Al(OH)3 = 6 NH3 + 6 H2O + Al2(SO4)3
SmCo5 + O2 = SmCoO3 + Co3O4 =>
6 SmCo5 + 25 O2 = 6 SmCoO3 + 8 Co3O4
Sb + NaOH = Sb(NaOH)2 =>
Sb + 2 NaOH = Sb(NaOH)2
NiCl2 + Pb(SO4)2 = NiSO4 + PbCl4 =>
2 NiCl2 + Pb(SO4)2 = 2 NiSO4 + PbCl4
HNO3 + Na2HPO4 + (NH4)2MoO4 = (NH4)3PO4*12MoO3 + NH3NO + H2O + NaNO3 =>
127 HNO3 + 11 Na2HPO4 + 132(NH4)2MoO4 = 11(NH4)3PO4*12MoO3 + 168 NH3NO + 279 H2O + 22 NaNO3
(NH4)2SO4(aq) + CuCl2 = NH4Cl + CuSO4 =>
(NH4)2SO4(aq) + CuCl2 = 2 NH4Cl + CuSO4
PhCH3 + KMnO4 + H2SO4 = PhCOOH + K2SO4 + MnSO4 + H2O =>
5 PhCH3 + 6 KMnO4 + 9 H2SO4 = 5 PhCOOH + 3 K2SO4 + 6 MnSO4 + 14 H2O
Co(OH)3 + NHO3 = Co(NO3)3 + H2O =>
Co(OH)3 + 3 NHO3 = Co(NO3)3 + 3 H2O
FeCu2S3 + HNO3 = Fe(NO3)3 + Cu(NO3)2 + H2SO4 + NO + H2O =>
3 FeCu2S3 + 46 HNO3 = 3 Fe(NO3)3 + 6 Cu(NO3)2 + 9 H2SO4 + 25 NO + 14 H2O
COCrO4 + NaOH = CO(OH)2 + Na2CrO4 =>
COCrO4 + 2 NaOH = CO(OH)2 + Na2CrO4
N(CH3)4I + I2 = N(CH3)4I5 =>
N(CH3)4I + 2 I2 = N(CH3)4I5
KBr + KMnO4 + H2O = Br2 + MnBr2 + KOH =>
14 KBr + 2 KMnO4 + 8 H2O = 5 Br2 + 2 MnBr2 + 16 KOH
Ba + HNO3 = BaNO3 + NO + H2O =>
3 Ba + 4 HNO3 = 3 BaNO3 + NO + 2 H2O
CuS(aq) + Zn = ZnS(aq) + Cu =>
CuS(aq) + Zn = ZnS(aq) + Cu
C57H102O6(aq) + CH4O(l) = C19H36O2(aq) + C3H8O3 =>
2 C57H102O6(aq) + 9 CH4O(l) = 6 C19H36O2(aq) + 3 C3H8O3
Mg(s) + HBr(l) = H(g) + MgBr2(ag) =>
Mg(s) + 2 HBr(l) = 2 H(g) + MgBr2(ag)
C8H18O + O2 = C02 + H2O =>
C8H18O + 4 O2 = 4 C02 + 9 H2O
NaOH + H(ClO4) = Na(ClO4) + H2O =>
NaOH + H(ClO4) = Na(ClO4) + H2O
HNO3 + KI = HIO3 + NO2 + H2O + KNO3 =>
7 HNO3 + KI = HIO3 + 6 NO2 + 3 H2O + KNO3
Mg + HCH3COO = MgHCH3COO =>
Mg + HCH3COO = MgHCH3COO
K2CrO4 + Pb(C2H3O2)4 = KC2H3O2 + Pb2(CrO4)4 =>
4 K2CrO4 + 2 Pb(C2H3O2)4 = 8 KC2H3O2 + Pb2(CrO4)4
TiCO3 = TiO + CO2 =>
TiCO3 = TiO + CO2
CH3(CH2)4CH3(l) + O2(g) = CO2 + H2O =>
2 CH3(CH2)4CH3(l) + 19 O2(g) = 12 CO2 + 14 H2O
O2 + NH3 = NO2 + H =>
O2 + NH3 = NO2 + 3 H
TiCO3 = TiO + CO2 =>
TiCO3 = TiO + CO2
Balance the equation of any chemical reaction
| Equations balanced on the previous day |
Equations balanced on 02/17/25
Equations balanced on 03/19/24
Please let us know how we can improve this web app.
