Equations balanced on the previous day |
4 Al + 4(OH)3 + 3 H4SiO4 = Al4(SiO4)3 + 12 H2O
HNO3 + KCl = HCl + KNO3 =>
HNO3 + KCl = HCl + KNO3
SO3 + HCl = SO3HCl =>
SO3 + HCl = SO3HCl
Cu + AgNO3 = Cu(NO3)2 + Ag =>
Cu + 2 AgNO3 = Cu(NO3)2 + 2 Ag
Na3PO4 + MgCl2 + NH4 = MgNH4PO4 + Na3Cl2 =>
Na3PO4 + MgCl2 + NH4 = MgNH4PO4 + Na3Cl2
C6H5COOH + O2 = CO2 + H2O =>
2 C6H5COOH + 15 O2 = 14 CO2 + 6 H2O
Ba(OH)2 + HCl = BaCl2 + H2O =>
Ba(OH)2 + 2 HCl = BaCl2 + 2 H2O
CH3OC(CH3)3 = C + H + O =>
CH3OC(CH3)3 = 5 C + 12 H + O
Cu + HNO3 = Cu(NO3)2 + NO2 + H2O =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O
CoBr3 = Co + Br2 =>
2 CoBr3 = 2 Co + 3 Br2
MgO2H2 + Mg2Al4Si5O18 + H2O = Mg5Al2Si3O18H8 + Al2SiO5 =>
11 MgO2H2 + 2 Mg2Al4Si5O18 + H2O = 3 Mg5Al2Si3O18H8 + Al2SiO5
K4Fe(CN)6 + H2SO4 + H2O = K2SO4 + FeSO4 + (NH4)2SO4 + CO =>
K4Fe(CN)6 + 6 H2SO4 + 6 H2O = 2 K2SO4 + FeSO4 + 3(NH4)2SO4 + 6 CO
Ba + HBr = BaBr2 + H2 =>
Ba + 2 HBr = BaBr2 + H2
Cr + O2 = Cr0O3 =>
2 Cr + 3 O2 = 2 Cr0O3
C5H11OH + (CH3CO)2O = CH3COOC5H11 + CH3COOH =>
C5H11OH + (CH3CO)2O = CH3COOC5H11 + CH3COOH
Li3PO4 + CaCl2 = Ca3(PO4)2 + Li2Cl2 =>
2 Li3PO4 + 3 CaCl2 = Ca3(PO4)2 + 3 Li2Cl2
H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O
BaS2O3 + HCl = BaCl2 + S + SO2 + H2O =>
BaS2O3 + 2 HCl = BaCl2 + S + SO2 + H2O
(NH4)2C2O4 + Pb(NO3)2 = (NH4)(NO3) + PbC2O4 =>
(NH4)2C2O4 + Pb(NO3)2 = 2(NH4)(NO3) + PbC2O4
H2SO4 + K4Fe(CN)6 + KMnO4 = CO2 + Fe2(SO4)3 + H2O + HNO3 + KHSO4 + MnSO4 =>
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122 MnSO4
K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O
NaCl + Co(NO3)2 = CoCl2 + NaNO3 =>
2 NaCl + Co(NO3)2 = CoCl2 + 2 NaNO3
CoCl2*6H2O + HNO3 = Co(NO3)2 + HCl + H2O =>
CoCl2*6H2O + 2 HNO3 = Co(NO3)2 + 2 HCl + 6 H2O
IRON(III)TRICHLORIDE + COBALT(II)DICHLORIDE = IRON(III)DICHLORIDE + COBALT(II)TRICHLORIDE =>
IRON(III)TRICHLORIDE + COBALT(II)DICHLORIDE = IRON(III)DICHLORIDE + COBALT(II)TRICHLORIDE
CoO(s) + C(s) = Co + CO2 =>
2 CoO(s) + C(s) = 2 Co + CO2
PhCH3 + KMnO4 + H2SO4 = PhCOOH + K2SO4 + MnSO4 + H2O =>
5 PhCH3 + 6 KMnO4 + 9 H2SO4 = 5 PhCOOH + 3 K2SO4 + 6 MnSO4 + 14 H2O
C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O
C12H19Cl2O8 + O2 = CO2 + H2O + HCl =>
4 C12H19Cl2O8 + 49 O2 = 48 CO2 + 34 H2O + 8 HCl
H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O
C2H2 + Ca(OH)2 = CaC2 + H2 + O2 =>
C2H2 + Ca(OH)2 = CaC2 + 2 H2 + O2
Pb{+2}{+} + Cl{-} = PbCl2 =>
Pb{+2}{+} + 2 Cl{-} = PbCl2
Ca2CO3 + H2O = Ca(OH)2 + CO =>
Ca2CO3 + 2 H2O = 2 Ca(OH)2 + CO
Zn + Ni(NO3)3 = Ni + Zn(NO3) =>
3 Zn + Ni(NO3)3 = Ni + 3 Zn(NO3)
HAuCl4 + FeCl2 + H2O = Au + FeO + HCl2 =>
HAuCl4 + FeCl2 + H2O = Au + FeO + 3 HCl2
Co(NO3)2 + NH4(SCN) = Co(SCN)2 + NH4NO3 =>
Co(NO3)2 + 2 NH4(SCN) = Co(SCN)2 + 2 NH4NO3
AlCl3 + Cs = CsCl + Al =>
AlCl3 + 3 Cs = 3 CsCl + Al
C6H5OH + HNO3 = NO2 + H2O + HOOC(CH2)2COOH =>
2 C6H5OH + 14 HNO3 = 14 NO2 + 4 H2O + 3 HOOC(CH2)2COOH
N4 + F = NF4 =>
N4 + 16 F = 4 NF4
K2Cr2O7 + BaSO3 + H2SO4 = Cr2(SO4)3 + BaSO4 + K2SO4 + H2O =>
K2Cr2O7 + 3 BaSO3 + 4 H2SO4 = Cr2(SO4)3 + 3 BaSO4 + K2SO4 + 4 H2O
NH4 + H2O = H3O + NH =>
NH4 + 3 H2O = 3 H3O + NH
KN + C2 = KCN =>
2 KN + C2 = 2 KCN
C2H6O + MnO2 + HClO4 = MnClO4 + H2O + CO2 =>
C2H6O + 4 MnO2 + 4 HClO4 = 4 MnClO4 + 5 H2O + 2 CO2
NaBr + H2SO4 = HBr + Na + SO4 =>
2 NaBr + H2SO4 = 2 HBr + 2 Na + SO4
P2O5 + H2O = H3PO4 =>
P2O5 + 3 H2O = 2 H3PO4
AlBr3 + NaOH = AlOH + Br3Na =>
AlBr3 + NaOH = AlOH + Br3Na
MgCl2 + Ca(OH)2 = Mg(OH)2 + CaCl2 =>
MgCl2 + Ca(OH)2 = Mg(OH)2 + CaCl2
HCl + K2Cr2O7 + H2SO4 = K2SO4 + Cr2(SO4)3 + H2O + Cl2 =>
6 HCl + K2Cr2O7 + 4 H2SO4 = K2SO4 + Cr2(SO4)3 + 7 H2O + 3 Cl2
CaCO3 + HCl = CO2 + CaCl2 + H2O =>
CaCO3 + 2 HCl = CO2 + CaCl2 + H2O
(NH4NO3) = (N2) + (O2) + (H2O) =>
2(NH4NO3) = 2(N2) + (O2) + 4(H2O)
CaCO3 + HCl = CO2 + CaCl2 + H2O =>
CaCO3 + 2 HCl = CO2 + CaCl2 + H2O
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 02/17/25
Equations balanced on 03/19/24
Please let us know how we can improve this web app.