| Equations balanced on the previous day |
4 HCl + Co2 = 2 CoCl2 + 2 H2
Ca(OH)2 + H3(PO4) = Ca10(PO4)6(OH)2 + H2O =>
10 Ca(OH)2 + 6 H3(PO4) = Ca10(PO4)6(OH)2 + 18 H2O
Ba + S2 = BaS2 =>
Ba + S2 = BaS2
K4Fe(CN)6 + KMnO4 + H2OSO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
18 K4Fe(CN)6 + 100 KMnO4 + 299 H2OSO4 = 172 KHSO4 + 9 Fe2(SO4)3 + 100 MnSO4 + 108 HNO3 + 108 CO2 + 159 H2O
SO2 + O2 = SO3 =>
2 SO2 + O2 = 2 SO3
KHO + HP = KP + H2O =>
KHO + HP = KP + H2O
Cu + H{+} + NO3{-} = H2O + NO2 + Cu{+2} =>
Cu + 4 H{+} + 2 NO3{-} = 2 H2O + 2 NO2 + Cu{+2}
NaNO3(aq) + FeCl3(aq) = Fe(NO3)3(s) + NaCl(aq) =>
3 NaNO3(aq) + FeCl3(aq) = Fe(NO3)3(s) + 3 NaCl(aq)
Na3PO4 + (NH4)6Mo7O24 + HNO3 = (NH4)3(PMo12O40) + NaNO3 + (NH4)2NO4 + H2O =>
35 Na3PO4 + 60(NH4)6Mo7O24 + 258 HNO3 = 35(NH4)3(PMo12O40) + 105 NaNO3 + 136(NH4)2NO4 + 95 H2O
KL + Cu(NO3)2 = KNO3 + CuL2 =>
2 KL + Cu(NO3)2 = 2 KNO3 + CuL2
CaC2 + H2O = C2H2 + Ca(OH)2 =>
CaC2 + 2 H2O = C2H2 + Ca(OH)2
FeAsS1998 + H{+} + H2O + {-} = Fe{2+} + H3AsO3 + HS{-} =>
FeAsS1998 + 1995 H{+} + 2.9999999999998H2O + 3991e = Fe{2+} + H3AsO3 + 1998 HS{-}
NaHCO3(s) + CH3COOH(aq) = CH3COONa(s) + CO2(g) + H2O(l) =>
NaHCO3(s) + CH3COOH(aq) = CH3COONa(s) + CO2(g) + H2O(l)
NH2OH + H2O = NH4 + OH =>
NH2OH + 2 H2O = NH4 + 3 OH
Na2CO3*IOH2O = Na2CO3 + IOH2O =>
Na2CO3*IOH2O = Na2CO3 + IOH2O
(NH4)2S + Cu = Cu2S + NH4 =>
(NH4)2S + 2 Cu = Cu2S + 2 NH4
NaCl + AgNO3 = Cl(NO3) + AgNa =>
NaCl + AgNO3 = Cl(NO3) + AgNa
LiOH + BaCl2 = LiCl + Ba(OH)2 =>
2 LiOH + BaCl2 = 2 LiCl + Ba(OH)2
KAlO2 + K2O = K3AlO3 =>
KAlO2 + K2O = K3AlO3
Br2(g) + I2(g) = IBr3(g) =>
3 Br2(g) + I2(g) = 2 IBr3(g)
C3H5N3O9 = CO2 + H2O + N + O =>
2 C3H5N3O9 = 6 CO2 + 5 H2O + 6 N + O
YbSO4 + HNO3 = Yb2(SO4)3 + Yb(NO3)3 + NH4NO3 + H2O =>
24 YbSO4 + 30 HNO3 = 8 Yb2(SO4)3 + 8 Yb(NO3)3 + 3 NH4NO3 + 9 H2O
Fe + P + O = Fe3(PO4)2 =>
3 Fe + 2 P + 8 O = Fe3(PO4)2
Al(NO3)3(aq) + H2SO4(as) = Al2(SO4)3(aq) + HNO3(aq) =>
2 Al(NO3)3(aq) + 3 H2SO4(as) = Al2(SO4)3(aq) + 6 HNO3(aq)
Hg + HOH = HgHOH =>
Hg + HOH = HgHOH
HI + CI2 = HCI + I2 =>
HI + CI2 = HCI + I2
O2 + CH4 = CO2 + H2O =>
2 O2 + CH4 = CO2 + 2 H2O
Fe4S2 + O2 = Fe3O4 + SO2 =>
3 Fe4S2 + 14 O2 = 4 Fe3O4 + 6 SO2
calciumhydroxide + carbondioxide = calciumcarbonate + water =>
Ca(OH)2 + CO2 = CaCO3 + H2O
BaH18O10 + NH4SCN = Ba(SCN)2 + H2O + NH3 =>
BaH18O10 + 2 NH4SCN = Ba(SCN)2 + 10 H2O + 2 NH3
Zn(OH)2 + Na = Na(OH) + Zn =>
Zn(OH)2 + 2 Na = 2 Na(OH) + Zn
Cu2S + HNO3 = Cu(NO3)2 + CuSO4 + NO2 + H2O =>
Cu2S + 12 HNO3 = Cu(NO3)2 + CuSO4 + 10 NO2 + 6 H2O
NaClO + Na2S2O3 + H2O = NaCl + NaOH + Na2S4O6 =>
NaClO + 2 Na2S2O3 + H2O = NaCl + 2 NaOH + Na2S4O6
Sr + KClO4 = KCl + SrO =>
4 Sr + KClO4 = KCl + 4 SrO
Al(s) + PbSO4(aq) = AlSO4 + Pb =>
Al(s) + PbSO4(aq) = AlSO4 + Pb
C4H10O2 + HCl = C4H8Cl2 + H2O =>
C4H10O2 + 2 HCl = C4H8Cl2 + 2 H2O
Mg(s) + HC2H3O2(aq) = Mg(C2H3O2)(aq) + H2(g) =>
2 Mg(s) + 2 HC2H3O2(aq) = 2 Mg(C2H3O2)(aq) + H2(g)
TiCl3 + H2SO4 = TiOSO4 + SO2 + HCl =>
2 TiCl3 + 3 H2SO4 = 2 TiOSO4 + SO2 + 6 HCl
C106H263O110N16P1 = CH4 + CO2 + NH3 + C56H101O70N2P =>
C106H263O110N16P1 = 30 CH4 + 20 CO2 + 14 NH3 + C56H101O70N2P
OH{-} + ClO{-} + CrO2 = Cl{-} + CrO4{-2} + H2O =>
2 OH{-} + ClO{-} + CrO2 = Cl{-} + CrO4{-2} + H2O
Cu + Fe + HS = CuFe2S + H =>
Cu + 2 Fe + HS = CuFe2S + H
Pb(NO3)2 + HCl = Pb(Cl2) + HNO3 =>
Pb(NO3)2 + 2 HCl = Pb(Cl2) + 2 HNO3
Na + HOH = NaH + OH =>
Na + HOH = NaH + OH
H2SO4(aq) + CaCO3(s) = CO2(g)*CaSO4(aq) + H2O(l) =>
H2SO4(aq) + CaCO3(s) = CO2(g)*CaSO4(aq) + H2O(l)
NaHCO3 + O2 = H2O + CO2 + NaO =>
4 NaHCO3 + O2 = 2 H2O + 4 CO2 + 4 NaO
K2CrO4 + H2O + Fe(OH)2 = Cr(OH)4 + KOH + Fe(OH)3 =>
K2CrO4 + 4 H2O + 2 Fe(OH)2 = Cr(OH)4 + 2 KOH + 2 Fe(OH)3
Au + O5 = Au5O =>
25 Au + O5 = 5 Au5O
HNO3 + KI = KI3 + NO + H2O + KNO3 =>
8 HNO3 + 9 KI = 3 KI3 + 2 NO + 4 H2O + 6 KNO3
Cu + H(NO3) = CuNO3 + NO + H2O =>
3 Cu + 4 H(NO3) = 3 CuNO3 + NO + 2 H2O
HCOOH + CuCO3 = CHCuO2 + H2O + CO2 =>
3 HCOOH + 2 CuCO3 = 2 CHCuO2 + 2 H2O + 3 CO2
Balance the equation of any chemical reaction
| Equations balanced on the previous day |
Equations balanced on 01/23/25
Equations balanced on 02/22/24
Please let us know how we can improve this web app.
