Equations balanced on the previous day |
H2O2 + KAsO3 = KAsO4 + H2O
NaOH(l) + FeCl3(l) = Fe(OH)3(s) + NaCl(aq) =>
3 NaOH(l) + FeCl3(l) = Fe(OH)3(s) + 3 NaCl(aq)
Hg(ClO4)2 + Na2S = Na2Hg + S(ClO4)2 =>
Hg(ClO4)2 + Na2S = Na2Hg + S(ClO4)2
PbSO4 + Na2S = PbS + Na2SO4 =>
PbSO4 + Na2S = PbS + Na2SO4
Sn + NaNO3 + H2SO4 = NO2 + H2O + Sn5O5(OH)10 + Na2SO4 =>
5 Sn + 20 NaNO3 + 10 H2SO4 = 20 NO2 + 5 H2O + Sn5O5(OH)10 + 10 Na2SO4
Ca(NO3)2 + FeCI3 = CaCI3 + Fe(NO3)2 =>
Ca(NO3)2 + FeCI3 = CaCI3 + Fe(NO3)2
KC6H5CO2 + H2O = KOH + C6H5COOH =>
KC6H5CO2 + H2O = KOH + C6H5COOH
HNO3 + Al = NO + H2O + Al(NO3)3 =>
4 HNO3 + Al = NO + 2 H2O + Al(NO3)3
Pb(CH3COO)2 + NH4OH = CH3COONH4 + Pb(OH)2 =>
Pb(CH3COO)2 + 2 NH4OH = 2 CH3COONH4 + Pb(OH)2
NH4VO3 + Zn + HCl = VCl2 + ZnCl2 + NH4Cl + H2O =>
2 NH4VO3 + 3 Zn + 12 HCl = 2 VCl2 + 3 ZnCl2 + 2 NH4Cl + 6 H2O
LiOH + SnCl2 = Sn(OH)2 + LiCl =>
2 LiOH + SnCl2 = Sn(OH)2 + 2 LiCl
KBr + Na2CO3 = Na2Br + KCO3 =>
KBr + Na2CO3 = Na2Br + KCO3
ZnO(s) + C(s) = CO(g) + Zn(s) =>
ZnO(s) + C(s) = CO(g) + Zn(s)
Ag2SO4 + Pb(BrO3)4 = Pb(SO4)2 + AgBrO3 =>
2 Ag2SO4 + Pb(BrO3)4 = Pb(SO4)2 + 4 AgBrO3
NH3 + HBrO = N2 + HBr + H2O =>
2 NH3 + 3 HBrO = N2 + 3 HBr + 3 H2O
S5 + O2 = SO2 =>
S5 + 5 O2 = 5 SO2
C2H6S + N2O5 = CO2 + H2O + N2O + SO2 =>
4 C2H6S + 9 N2O5 = 8 CO2 + 12 H2O + 9 N2O + 4 SO2
Na2S + Be(NO3)2 = BeS + NaNO3 =>
Na2S + Be(NO3)2 = BeS + 2 NaNO3
Mg3(PO4)2 + BaCl2 = MgCl2 + Ba3(PO4)2 =>
Mg3(PO4)2 + 3 BaCl2 = 3 MgCl2 + Ba3(PO4)2
RuCl3(H2O)3 + PPh3 + C2H6O + CH2O = RuHCl(CO)(PPh3)3 + H2O + HCl =>
4 RuCl3(H2O)3 + 12 PPh3 + C2H6O + 2 CH2O = 4 RuHCl(CO)(PPh3)3 + 11 H2O + 8 HCl
KOH + CH3CHOHCOOH = H2O + KCH3CHOHCOO =>
KOH + CH3CHOHCOOH = H2O + KCH3CHOHCOO
CuI2 + K2S = CuS + KI =>
CuI2 + K2S = CuS + 2 KI
K2S(aq) + Pb(NO3)2(aq) = K(NO3) + PbS =>
K2S(aq) + Pb(NO3)2(aq) = 2 K(NO3) + PbS
CuO + C = Cu + CO2 =>
2 CuO + C = 2 Cu + CO2
C2H6O + O2 = CO2H20 + CO2 =>
10 C2H6O + 15 O2 = 3 CO2H20 + 17 CO2
Na3PO4 + AgNO3 = Na3NO3 + (PO4)11 + Ag =>
11 Na3PO4 + 11 AgNO3 = 11 Na3NO3 + (PO4)11 + 11 Ag
K2MnO4 + HCl = KMnO4 + Mn02 + KCl + H2O =>
14 K2MnO4 + 16 HCl = 12 KMnO4 + Mn02 + 16 KCl + 8 H2O
FeS2 + H2 = Fe + H2S =>
FeS2 + 2 H2 = Fe + 2 H2S
Cu(aq) + OH(aq) = Cu(OH)2(s) =>
Cu(aq) + 2 OH(aq) = Cu(OH)2(s)
FeO + K2Cr2O7 + HCl = FeCl3 + KCl + CrCl3 + H2O =>
6 FeO + K2Cr2O7 + 26 HCl = 6 FeCl3 + 2 KCl + 2 CrCl3 + 13 H2O
Mo2V2AlC3 = AlMo3 + Al8Mo3 + C + V6C5 =>
21 Mo2V2AlC3 = 13 AlMo3 + Al8Mo3 + 28 C + 7 V6C5
N2O2 + CO = N2 + CO2 =>
N2O2 + 2 CO = N2 + 2 CO2
HF + NH4Br = HBr + FNH4 =>
HF + NH4Br = HBr + FNH4
Zn(OH)2 + Al2(SO4)3 = ZnSO4 + Al(OH)3 =>
3 Zn(OH)2 + Al2(SO4)3 = 3 ZnSO4 + 2 Al(OH)3
(VO2)Cl + FeSO4 + H2SO4 = Fe2(SO4)3 + VO2 + HCl =>
2(VO2)Cl + 2 FeSO4 + H2SO4 = Fe2(SO4)3 + 2 VO2 + 2 HCl
Ni2ClO3 = Ni2Cl + O =>
Ni2ClO3 = Ni2Cl + 3 O
AgNO3(aq) + NH4I(aq) = AgI(s) + NH4NO3 =>
AgNO3(aq) + NH4I(aq) = AgI(s) + NH4NO3
Ca(CH3COO)2 + (NH4)3PO4 = Ca3(PO4)2 + NH4CH3COO =>
3 Ca(CH3COO)2 + 2(NH4)3PO4 = Ca3(PO4)2 + 6 NH4CH3COO
Cu(OH)2 + CO2 = Cu2CO3(OH)2 + H2O =>
2 Cu(OH)2 + CO2 = Cu2CO3(OH)2 + H2O
C3H6Br2 + KOH = C3H6(OH)2 + KBr =>
C3H6Br2 + 2 KOH = C3H6(OH)2 + 2 KBr
BaO2 + Al = Ba + AlO2 =>
BaO2 + Al = Ba + AlO2
[ReO4]{-} + Cl2 + H2O = Re + [ClO2]{-} + H{+} =>
6[ReO4]{-} + 7 Cl2 + 4 H2O = 6 Re + 14[ClO2]{-} + 8 H{+}
KC1O3 + KI + H2O = KC1 + I2 + KOH =>
KC1O3 + 6 KI + 3 H2O = KC1 + 3 I2 + 6 KOH
HgS + HNO3 = Hg(NO3)2 + H2S =>
HgS + 2 HNO3 = Hg(NO3)2 + H2S
C3H8O2 + Cu(OH)2 = CH3COOH + Cu2O + H2O =>
2 C3H8O2 + 8 Cu(OH)2 = 3 CH3COOH + 4 Cu2O + 10 H2O
CuNO3(aq) + Na2CO3(aq) = Cu2CO3(aq) + NaNO3(aq) =>
2 CuNO3(aq) + Na2CO3(aq) = Cu2CO3(aq) + 2 NaNO3(aq)
CH3CHCHCH2(OH) + KMnO4 + H2SO4 = CH3COOH + H2O + MnSO4 + K2SO4 =>
5 CH3CHCHCH2(OH) + 6 KMnO4 + 9 H2SO4 = 10 CH3COOH + 9 H2O + 6 MnSO4 + 3 K2SO4
Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 H2O
Hg2I2 + O2 = Hg2O2 + I2 =>
Hg2I2 + O2 = Hg2O2 + I2
UO2(H2O)5 + O2 = UO2(H2O)3O2 + H2O =>
UO2(H2O)5 + O2 = UO2(H2O)3O2 + 2 H2O
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 01/23/25
Equations balanced on 02/22/24
Please let us know how we can improve this web app.