Equations balanced on the previous day |
CuOCl2 = CuCl2O
AuF3 + H2SO4 + NaMnO4 = MnSO4 + Na + Au2(SO4)3 + F2 + H2O =>
2 AuF3 + 4 H2SO4 + NaMnO4 = MnSO4 + Na + Au2(SO4)3 + 3 F2 + 4 H2O
C6H15S + O2 = CO2 + H2O + SO2 =>
4 C6H15S + 43 O2 = 24 CO2 + 30 H2O + 4 SO2
H2SO3(aq) + CaCO3(s) = CaSO3(aq) + H2CO3(aq) =>
H2SO3(aq) + CaCO3(s) = CaSO3(aq) + H2CO3(aq)
Hg(NO3)2 + KCl = HgCl2 + KNO3 =>
Hg(NO3)2 + 2 KCl = HgCl2 + 2 KNO3
Ba(NO3)2 + NH2SO3H + H2O = BaSO4 + NH4NO3 + HNO3 =>
Ba(NO3)2 + NH2SO3H + H2O = BaSO4 + NH4NO3 + HNO3
Cr2O7{-2} + H{+} + {-} = Cr{+3} + H2O =>
Cr2O7{-2} + 14 H{+} + 6e = 2 Cr{+3} + 7 H2O
H + NF = N3 + HF =>
3 H + 3 NF = N3 + 3 HF
K2Cr2O7 + H2SO4 + KCl = K2SO4 + H2O + CrO2Cl2 =>
K2Cr2O7 + 3 H2SO4 + 4 KCl = 3 K2SO4 + 3 H2O + 2 CrO2Cl2
Co(H2O)6 + Cl2 = Co(H2O)3Cl3 + H2O =>
2 Co(H2O)6 + 3 Cl2 = 2 Co(H2O)3Cl3 + 6 H2O
Ca(s) + AlCl3(aq) = CaCl2(aq) + Al(s) =>
3 Ca(s) + 2 AlCl3(aq) = 3 CaCl2(aq) + 2 Al(s)
H2SO4 + K4Fe(CN)6 + KMnO4 = CO2 + Fe2(SO4)3 + H2O + HNO3 + KHSO4 + MnSO4 =>
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122 MnSO4
Hg2(NO3)2 + HNO3 = Hg(NO3)2 + H2O + NO2 =>
Hg2(NO3)2 + 4 HNO3 = 2 Hg(NO3)2 + 2 H2O + 2 NO2
NH3(g) + I2(g) = NI2(g) + H2(g) =>
2 NH3(g) + 2 I2(g) = 2 NI2(g) + 3 H2(g)
COOH{-}CH2{-}COOH + KOH = COOK{-}CH2{-}COOK + H2O =>
COOH{-}CH2{-}COOH + KOH = COOK{-}CH2{-}COOK + H2O
KCl + AgN3 = KN3 + AgCl =>
KCl + AgN3 = KN3 + AgCl
Cu + NO3{-} + H{+} = Cu{2{+}+NO+H2O(l) =>
3 Cu + 2 NO3{-} + 8 H{+} = 3 Cu{2{+}+2NO+4H2O(l)
HC2H3O2 + Na(CO3)2 = NaC2H3O + H2O + CO2 =>
13 HC2H3O2 + 8 Na(CO3)2 = 8 NaC2H3O + 14 H2O + 26 CO2
HC2H3O2(aq) + K2CO3(aq) = H20(l) + CO2(l) + KC2H3O2(aq) =>
25 HC2H3O2(aq) + 10 K2CO3(aq) = 2 H20(l) + 20 CO2(l) + 20 KC2H3O2(aq)
HCn + HCl = HCnCl + H2 =>
2 HCn + 2 HCl = 2 HCnCl + H2
[Cu(NH3)4]Cl2 + KSCN = K2[Cu(SCN)4] + NH3 + KCl =>
[Cu(NH3)4]Cl2 + 4 KSCN = K2[Cu(SCN)4] + 4 NH3 + 2 KCl
K2CO3 + MnO2 = CO + K2MnO4 =>
K2CO3 + MnO2 = CO + K2MnO4
Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3
(NH4)2SO4 + BaF2 = BaSO4 + (NH4)F =>
(NH4)2SO4 + BaF2 = BaSO4 + 2(NH4)F
H2SO4 + HaOH = Ha2SO4 + H2O =>
H2SO4 + 2 HaOH = Ha2SO4 + 2 H2O
KNO6 = KNO + O2 =>
2 KNO6 = 2 KNO + 5 O2
Ca100C100O300 + Co300O400 + Ce100O200 + Si100O200 + O200 = Ca290Ce10Co400Si2O900 + C100O200 =>
870 Ca100C100O300 + 400 Co300O400 + 30 Ce100O200 + 6 Si100O200 + 79 O200 = 300 Ca290Ce10Co400Si2O900 + 870 C100O200
BaCl2 + NH4Cl = Cl2 + NH4Ba =>
2 BaCl2 + 2 NH4Cl = 3 Cl2 + 2 NH4Ba
NaHCO3(s) = NaOH(s) + CO2(g) =>
NaHCO3(s) = NaOH(s) + CO2(g)
Cs + O2 = Cs2O2 =>
2 Cs + O2 = Cs2O2
Cu(C2H3O2) + Al2(SO4)3 = Al(C2H3O2)3 + Cu2(SO4) =>
6 Cu(C2H3O2) + Al2(SO4)3 = 2 Al(C2H3O2)3 + 3 Cu2(SO4)
SrCO3 + Ba = Sr + BaCO3 =>
SrCO3 + Ba = Sr + BaCO3
Ba(OH)2 + Ca3(PO4)2 = Ba3(PO4)2 + Ca(OH)2 =>
3 Ba(OH)2 + Ca3(PO4)2 = Ba3(PO4)2 + 3 Ca(OH)2
Fe(aq) + CuSO4(aq) = FeSO4(aq) + Cu(aq) =>
Fe(aq) + CuSO4(aq) = FeSO4(aq) + Cu(aq)
KBr + AlI3 = AlBr3 + KI =>
3 KBr + AlI3 = AlBr3 + 3 KI
NaHCO3 + Ba(NO3)2 = BaCO3 + NaNO3 + H2O + CO2 =>
2 NaHCO3 + Ba(NO3)2 = BaCO3 + 2 NaNO3 + H2O + CO2
CoCl2 + KOH + KClO2 = CoO3 + KCl + H2O =>
CoCl2 + 2 KOH + KClO2 = CoO3 + 3 KCl + H2O
KSCN + Cu(NO3)2 = Cu(CN)2 + KSNO3 =>
2 KSCN + Cu(NO3)2 = Cu(CN)2 + 2 KSNO3
H2O + P2Cl5 = H3PO4 + HCl + H2 =>
16 H2O + 2 P2Cl5 = 4 H3PO4 + 10 HCl + 5 H2
XBr3 + Na = X + NaBr =>
XBr3 + 3 Na = X + 3 NaBr
Al(HCO3)3(aq) + AlPO4(aq) = Al2(CO3)3(aq) + H3PO4(aq) =>
Al(HCO3)3(aq) + AlPO4(aq) = Al2(CO3)3(aq) + H3PO4(aq)
KClO4 + C6H5COONa = KCl + Na + CO2 + H2O =>
29 KClO4 + 8 C6H5COONa = 29 KCl + 8 Na + 56 CO2 + 20 H2O
Ba(NO3)2 + H2SO4 = BaSO4 + HNO3 =>
Ba(NO3)2 + H2SO4 = BaSO4 + 2 HNO3
HCl + Au = AuCl{-} + H{+} =>
HCl + Au = AuCl{-} + H{+}
FeS2 + NO3 = N2 + Fe + SO4 =>
3 FeS2 + 8 NO3 = 4 N2 + 3 Fe + 6 SO4
K2MnO4 = K2MnO3 + O2 =>
2 K2MnO4 = 2 K2MnO3 + O2
K2Cr2O7 + H2SO4 + KNO2 = Cr2(SO4)3 + KNO3 + K2SO4 + H2O =>
K2Cr2O7 + 4 H2SO4 + 3 KNO2 = Cr2(SO4)3 + 3 KNO3 + K2SO4 + 4 H2O
VO(OH)2 + KMnO4 + HCl = VOCl3 + KCl + MnCl2 + H2O =>
5 VO(OH)2 + KMnO4 + 18 HCl = 5 VOCl3 + KCl + MnCl2 + 14 H2O
K2Cr2O7 + Fe(ClO4)2 + HClO4 = Fe(ClO4)3 + Cr(ClO4)3 + KClO4 + H2O =>
K2Cr2O7 + 6 Fe(ClO4)2 + 14 HClO4 = 6 Fe(ClO4)3 + 2 Cr(ClO4)3 + 2 KClO4 + 7 H2O
HCl + Mo = MoCl5 + H =>
5 HCl + Mo = MoCl5 + 5 H
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 01/23/25
Equations balanced on 02/22/24
Please let us know how we can improve this web app.