Equations balanced on the previous day |
Na2CO3 + 2 HNO3 = 2 NaNO3 + H2CO3
C4H8O2 + KMnO4 + H2SO4 = C2H2O4 + MnSO4 + K2SO4 + H2O =>
5 C4H8O2 + 16 KMnO4 + 24 H2SO4 = 10 C2H2O4 + 16 MnSO4 + 8 K2SO4 + 34 H2O
NH3 + H2O2 = NH4NO3 + H2O =>
2 NH3 + 4 H2O2 = NH4NO3 + 5 H2O
K2CrO4 + HCl = KCl + Cl2 + CrCl3 + H2O =>
2 K2CrO4 + 16 HCl = 4 KCl + 3 Cl2 + 2 CrCl3 + 8 H2O
HCl + Na(OH) = NaCl + H2O =>
HCl + Na(OH) = NaCl + H2O
Na2CO3 + HNO3 = NaNO3 + H2CO3 =>
Na2CO3 + 2 HNO3 = 2 NaNO3 + H2CO3
KHSO4 + Ba(HS)2 = K2S + BaSO4 + H2SO4 =>
4 KHSO4 + Ba(HS)2 = 2 K2S + BaSO4 + 3 H2SO4
Zn + NaOH = Zn(OH)2 + Na =>
Zn + 2 NaOH = Zn(OH)2 + 2 Na
S + SO4{2-} + OH{-} = SO3{2-} + H2O =>
S + 2 SO4{2-} + 2 OH{-} = 3 SO3{2-} + H2O
CO2 + H + CNH4 = C2H5NO2 =>
CO2 + H + CNH4 = C2H5NO2
K2Cr2O7 + KI + HCl = CrCl3 + I2 + KCl + H2O =>
K2Cr2O7 + 6 KI + 14 HCl = 2 CrCl3 + 3 I2 + 8 KCl + 7 H2O
C2H5OH = CH4 + CO2 =>
2 C2H5OH = 3 CH4 + CO2
Na2CO3 + HNO3 = NaNO3 + H2CO3 =>
Na2CO3 + 2 HNO3 = 2 NaNO3 + H2CO3
Mg + H2SO4 = MgSO4 + H2S + H2O =>
4 Mg + 5 H2SO4 = 4 MgSO4 + H2S + 4 H2O
Ag(I)NO3 + NaCl = Ag(I)Cl + NaNO3 =>
Ag(I)NO3 + NaCl = Ag(I)Cl + NaNO3
FeCl3 + KOH = Fe(OH)3 + KCl =>
FeCl3 + 3 KOH = Fe(OH)3 + 3 KCl
CrO2{-} + H2O2 = CrO4{2-} + H2O + H{+} =>
2 CrO2{-} + 3 H2O2 = 2 CrO4{2-} + 2 H2O + 2 H{+}
CrO4{2-} + H3O{+} = Cr2O7{2-} + H2O =>
2 CrO4{2-} + 2 H3O{+} = Cr2O7{2-} + 3 H2O
Na2S + Al(NO3)2 = SAl + NaNO3 =>
Na2S + Al(NO3)2 = SAl + 2 NaNO3
H3(PO4) = H4(P2O7) + H2O =>
2 H3(PO4) = H4(P2O7) + H2O
Zn(NO3)2 + Na3PO4 = ZnPO4 + Na3(NO3)2 =>
Zn(NO3)2 + Na3PO4 = ZnPO4 + Na3(NO3)2
K2CrO4 + H2SO4 + Na2S = Cr2SO4 + K2SO4 + Na2SO4 + H2O =>
8 K2CrO4 + 12 H2SO4 + 5 Na2S = 4 Cr2SO4 + 8 K2SO4 + 5 Na2SO4 + 12 H2O
NaCl + Ca = CaCl + Na =>
NaCl + Ca = CaCl + Na
NaBr + CuCl2 = NaCl + CuBr2 =>
2 NaBr + CuCl2 = 2 NaCl + CuBr2
Copper(II)Sulfate(aq)Iron(s) = Copper(s)Iron(II)Sulfate(aq) =>
Copper(II)Sulfate(aq)Iron(s) = Copper(s)Iron(II)Sulfate(aq)
MnSO4 + Cl2 + NaOH = Na2MnO4 + NaCl + Na2SO4 + H2O =>
MnSO4 + 2 Cl2 + 8 NaOH = Na2MnO4 + 4 NaCl + Na2SO4 + 4 H2O
HNO3 + Al(OH)3 = Al(NO3)3 + H2O =>
3 HNO3 + Al(OH)3 = Al(NO3)3 + 3 H2O
FeCl3 + K4Fe(CN)6 = KCl + Fe4[Fe(CN)6]3 =>
4 FeCl3 + 3 K4Fe(CN)6 = 12 KCl + Fe4[Fe(CN)6]3
(CH3(CH2)4CH3) + O2 = CO2 + H2O =>
2(CH3(CH2)4CH3) + 19 O2 = 12 CO2 + 14 H2O
Mg + FeC13 = MgC12 + Fe =>
13 Mg + 12 FeC13 = 13 MgC12 + 12 Fe
NaOH + BaCl2 = NaCl + BaO + HCl =>
NaOH + BaCl2 = NaCl + BaO + HCl
H2SO4 + HCl = Cl2SO4 + H2H =>
3 H2SO4 + 6 HCl = 3 Cl2SO4 + 4 H2H
VO{2+} + MnO4{-} + H2O = HVO3 + Mn{2+} + H{+} =>
5 VO{2+} + MnO4{-} + 6 H2O = 5 HVO3 + Mn{2+} + 7 H{+}
ClO3(aq) + H2O(l) + I2(s) = IO3(aq) + HCl(aq) =>
12 ClO3(aq) + 6 H2O(l) + 7 I2(s) = 14 IO3(aq) + 12 HCl(aq)
MnO4{-} + H2O + e = MnO2 + OH{-} =>
MnO4{-} + 2 H2O + 3e = MnO2 + 4 OH{-}
KNo2 + KMnO4 + H2O = KNo3 + MnO2 + KOH =>
9 KNo2 + KMnO4 + 2 H2O = 6 KNo3 + MnO2 + 4 KOH
Zn + MnO2 + NH4Cl = ZnCl + Mn2O3 + NH3 + H2O =>
2 Zn + 2 MnO2 + 2 NH4Cl = 2 ZnCl + Mn2O3 + 2 NH3 + H2O
K3(Cr(OH)6) + H2SO4 = Cr2(SO4)3 + K2SO4 + H2O =>
2 K3(Cr(OH)6) + 6 H2SO4 = Cr2(SO4)3 + 3 K2SO4 + 12 H2O
Ca(OH)2 + HNO3 = Ca(NO3)2 + H2O =>
Ca(OH)2 + 2 HNO3 = Ca(NO3)2 + 2 H2O
Rb2CO3 + H2SO4 = Rb2SO4 + H2CO3 =>
Rb2CO3 + H2SO4 = Rb2SO4 + H2CO3
Cd(NO3)2 + NH4OH = [Cd(NH3)4] + H2O + NO3 =>
Cd(NO3)2 + 4 NH4OH = [Cd(NH3)4] + 4 H2O + 2 NO3
NaH2PO4 + Ba(OH)2 = BaH2PO4 + Na(OH)2 =>
NaH2PO4 + Ba(OH)2 = BaH2PO4 + Na(OH)2
H2SO4 + NaOH = Na2SO4 + H2O =>
H2SO4 + 2 NaOH = Na2SO4 + 2 H2O
AlBr + Cl = AlCl3 + Br =>
AlBr + 3 Cl = AlCl3 + Br
NH4Cl + HCl = NH4H + Cl =>
NH4Cl + HCl = NH4H + 2 Cl
AgNo3 + AlCl3 = AgCl + Al(No3)3 =>
3 AgNo3 + AlCl3 = 3 AgCl + Al(No3)3
CH4(g) + O2(g) = C(s) + H2O(i) =>
CH4(g) + O2(g) = C(s) + 2 H2O(i)
Cr2(SO4)3 + NaOH = Cr(OH)3 + SO4(Na)2 =>
Cr2(SO4)3 + 6 NaOH = 2 Cr(OH)3 + 3 SO4(Na)2
PbN2O6 + NH4OH = PbO2H2 + NH4NO3 =>
PbN2O6 + 2 NH4OH = PbO2H2 + 2 NH4NO3
FeCl3(s) + NaOH(aq) = Fe(OH)3 + NaCl(s) =>
FeCl3(s) + 3 NaOH(aq) = Fe(OH)3 + 3 NaCl(s)
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 01/12/25
Equations balanced on 02/11/24
Please let us know how we can improve this web app.