Equations balanced on the previous day |
N2 + 3 H2 = 2 NH3
BF3 + Li2SO3 = B2(SO3)3 + LiF =>
2 BF3 + 3 Li2SO3 = B2(SO3)3 + 6 LiF
Ai2(SO4)3 + NaHCO3 = Ai(OH)3 + Na2SO4 + CO2 =>
Ai2(SO4)3 + 6 NaHCO3 = 2 Ai(OH)3 + 3 Na2SO4 + 6 CO2
KI + PbO2 + HNO3 = I2 + Pb(NO3)2 + KOH =>
2 KI + PbO2 + 2 HNO3 = I2 + Pb(NO3)2 + 2 KOH
PotassiumPhosphate + Tin(II)Nitrate = PotassiumNitrate + Tin(II)Phosphate =>
PotassiumPhosphate + Tin(II)Nitrate = PotassiumNitrate + Tin(II)Phosphate
PotassiumPhosphate + Tin(IV)Nitrate = PotassiumNitrate + Tin(IV)Phosphate =>
PotassiumPhosphate + Tin(IV)Nitrate = PotassiumNitrate + Tin(IV)Phosphate
PotassiumPhosphate + Tin(II)Nitrate = PotassiumNitrate + Tin(II)Phosphate =>
PotassiumPhosphate + Tin(II)Nitrate = PotassiumNitrate + Tin(II)Phosphate
C7H6O2 + CaCO3 = CaC7H5O2 + CO2 + H2O =>
31 C7H6O2 + 30 CaCO3 = 30 CaC7H5O2 + 37 CO2 + 18 H2O
PotassiumPhosphate + Tin(II)Nitrate = PotassiumNitrate + Tin(II)Phosphate =>
PotassiumPhosphate + Tin(II)Nitrate = PotassiumNitrate + Tin(II)Phosphate
MnOH + H2PO3 = MnHPO3 + H2O =>
MnOH + H2PO3 = MnHPO3 + H2O
GaC6H15 + O2 = Ga2O3 + H2O + CO2 =>
2 GaC6H15 + 21 O2 = Ga2O3 + 15 H2O + 12 CO2
Ca3(PO4)2 + SiO4 + C = CaSiO3 + P4 + CO =>
2 Ca3(PO4)2 + 6 SiO4 + 22 C = 6 CaSiO3 + P4 + 22 CO
CaCO3 = CaO + CO2 =>
CaCO3 = CaO + CO2
Np3NpO4 + O3 + NaOH = NaNpO4 + H2O =>
3 Np3NpO4 + 10 O3 + 12 NaOH = 12 NaNpO4 + 6 H2O
(C3H3NaO2)1 + H2O = (C3H3NaO2H2O)1 =>
(C3H3NaO2)1 + H2O = (C3H3NaO2H2O)1
Ca3(PO4)2(s) + SiO2(s) + C(a) = CaSiO3(s) + CO(g) + P4(s) =>
2 Ca3(PO4)2(s) + 6 SiO2(s) + 10 C(a) = 6 CaSiO3(s) + 10 CO(g) + P4(s)
H2S + O2 = SO2 + H2O =>
2 H2S + 3 O2 = 2 SO2 + 2 H2O
CH3CH2OH + HCl = CH3CH2Cl + H2O =>
CH3CH2OH + HCl = CH3CH2Cl + H2O
CuO + BrF3 = CuF3 + Br2 + O2 =>
2 CuO + 2 BrF3 = 2 CuF3 + Br2 + O2
KHPO4 + KOH = K2PO4 + H2O =>
KHPO4 + KOH = K2PO4 + H2O
NH4CO3 + H2SO4 = (NH4)2SO4 + HCO3 =>
2 NH4CO3 + H2SO4 = (NH4)2SO4 + 2 HCO3
HCl + K = H + KCl =>
HCl + K = H + KCl
SO3(g) + H2O(q) = H2SO4(aq) =>
SO3(g) + H2O(q) = H2SO4(aq)
Zi2 + HCl = ZiCl + H2 =>
Zi2 + 2 HCl = 2 ZiCl + H2
C5H8 + KMnO4 + H2O = C5H8(OH)4 + KOH + MnO2 =>
3 C5H8 + 4 KMnO4 + 8 H2O = 3 C5H8(OH)4 + 4 KOH + 4 MnO2
CH3COOAg + H2S = Ag2S + CH3COOH =>
2 CH3COOAg + H2S = Ag2S + 2 CH3COOH
C + S8 = CS2 =>
4 C + S8 = 4 CS2
CuS + H2O = Cu + H2 + SO =>
CuS + H2O = Cu + H2 + SO
I + Br = IBr =>
I + Br = IBr
MgSO4 + FeCl3*6H2O = Fe2(SO4)3 + MgCl2 + H2O =>
3 MgSO4 + 2 FeCl3*6H2O = Fe2(SO4)3 + 3 MgCl2 + 12 H2O
Cr + CdCl2 = CrCl2 + Cd =>
Cr + CdCl2 = CrCl2 + Cd
NaAlO2 + Na2SiO3*9H2O = Na12[(AlO2)12(SiO2)12]*27H2O + H2O + NaOH =>
12 NaAlO2 + 12 Na2SiO3*9H2O = Na12[(AlO2)12(SiO2)12]*27H2O + 69 H2O + 24 NaOH
SO3 + H2O = H2SO4 =>
SO3 + H2O = H2SO4
Sr(NO3)2 + Al(NO3)3*9H2O + CO(NH2)2 = SrAl2O4 + H2O + N2 + CO2 =>
3 Sr(NO3)2 + 6 Al(NO3)3*9H2O + 20 CO(NH2)2 = 3 SrAl2O4 + 94 H2O + 32 N2 + 20 CO2
FeSO4(aq) + K2Cr2O7(aq) + H2SO4(aq) = Cr2(SO4)3(aq) + Fe2(SO4)3(aq) + K2SO4(aq) + H2O(l) =>
6 FeSO4(aq) + K2Cr2O7(aq) + 7 H2SO4(aq) = Cr2(SO4)3(aq) + 3 Fe2(SO4)3(aq) + K2SO4(aq) + 7 H2O(l)
Na4Si + H2O = NaOH + SiH4 =>
Na4Si + 4 H2O = 4 NaOH + SiH4
H3AsO4 = As2O5 + H2O =>
2 H3AsO4 = As2O5 + 3 H2O
PbO = Pb + O2 =>
2 PbO = 2 Pb + O2
Na2O2 + Fe(OH)2 + H2O = Na3[Fe(OH)6] + Fe(OH)3 =>
3 Na2O2 + 6 Fe(OH)2 + 6 H2O = 2 Na3[Fe(OH)6] + 4 Fe(OH)3
Li + O2 = LiO2 =>
Li + O2 = LiO2
ZnBr2 + Cl2 = ZnCl + Br =>
2 ZnBr2 + Cl2 = 2 ZnCl + 4 Br
ZnO + Mn = Zn + MnO2 =>
2 ZnO + Mn = 2 Zn + MnO2
Al(NO2)3 + Na2CO3 = Al2(CO3)3 + NaNO2 =>
2 Al(NO2)3 + 3 Na2CO3 = Al2(CO3)3 + 6 NaNO2
KOH + NH4Br = KBr + H2O + NH3 =>
KOH + NH4Br = KBr + H2O + NH3
C2H4O + C2H6O2 = C4H10O3 =>
C2H4O + C2H6O2 = C4H10O3
N2 + C2H6 = N2H4 + C2H2 =>
N2 + C2H6 = N2H4 + C2H2
HC2H3O2 + OH = H2O + C2H3O2 =>
HC2H3O2 + OH = H2O + C2H3O2
K + MgI2 = Mg2 + KI =>
4 K + 2 MgI2 = Mg2 + 4 KI
CaCl2 + Na3PO4 = Ca3(PO4)2 + NaCl =>
3 CaCl2 + 2 Na3PO4 = Ca3(PO4)2 + 6 NaCl
Fe + H2O + NaCl = FeCl2 + H2 + NaOH =>
Fe + 2 H2O + 2 NaCl = FeCl2 + H2 + 2 NaOH
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 01/12/25
Equations balanced on 02/11/24
Please let us know how we can improve this web app.