Equations balanced on the previous day |
C7H14 + 21 F2 = 7 CF4 + 14 HF
CH2Cl2 + H2O = CH2(OH)2 + HCl =>
CH2Cl2 + 2 H2O = CH2(OH)2 + 2 HCl
C6H12O6(aq) + I2(aq) = C6H6O6(aq) + HI(aq) =>
C6H12O6(aq) + 3 I2(aq) = C6H6O6(aq) + 6 HI(aq)
Cr2O7{2-} + H{+} + e = Cr{3+} + H2O =>
Cr2O7{2-} + 14 H{+} + 6e = 2 Cr{3+} + 7 H2O
CopperIINitrate + SodiumHydroxide = CopperIIHydroxide + SodiumNitrate =>
CopperIINitrate + SodiumHydroxide = CopperIIHydroxide + SodiumNitrate
RbCl + Br = Rb + BrCl =>
RbCl + Br = Rb + BrCl
C2H2 + O3 = CO2 + H2O =>
3 C2H2 + 5 O3 = 6 CO2 + 3 H2O
C6H10O5 + C3H8O3 + HCl + NaOH = C9H20O9ClNa =>
C6H10O5 + C3H8O3 + HCl + NaOH = C9H20O9ClNa
KHSO4 + Na2CO3 = Na2SO4 + K2SO4 + CO2 + H2O =>
2 KHSO4 + Na2CO3 = Na2SO4 + K2SO4 + CO2 + H2O
Zn + NH4Cl = ZnCl2 + NH3 + H2 =>
Zn + 2 NH4Cl = ZnCl2 + 2 NH3 + H2
NH4ReO4 + HCl = NH4Cl + ReO4H =>
NH4ReO4 + HCl = NH4Cl + ReO4H
Hydrogen + Br2 = HBr2 =>
H2 + 2 Br2 = 2 HBr2
CH3CH2OH + PCl3 = CH3CH2Cl + H3PO3 =>
3 CH3CH2OH + PCl3 = 3 CH3CH2Cl + H3PO3
CaO + H2O = Ca(OH)2 =>
CaO + H2O = Ca(OH)2
Cu(s) + H2SO4 = SO2(g) + CuO(s) + H2O(l) =>
Cu(s) + H2SO4 = SO2(g) + CuO(s) + H2O(l)
NH4Cl + NaOH = NaCl + H2O + NH3 =>
NH4Cl + NaOH = NaCl + H2O + NH3
XCCH + H2O = XCOCH3 =>
XCCH + H2O = XCOCH3
HCO3 + H2SO4 = CO2 + SO4 + H2O =>
2 HCO3 + H2SO4 = 2 CO2 + SO4 + 2 H2O
CuSO4 + NaOH = Cu(OH)2 + Na2SO4 =>
CuSO4 + 2 NaOH = Cu(OH)2 + Na2SO4
Fe + HNO3 = Fe(NO3)3 + NO + H2O =>
Fe + 4 HNO3 = Fe(NO3)3 + NO + 2 H2O
RbOH + H2SO4 = H2O + Rb2SO4 =>
2 RbOH + H2SO4 = 2 H2O + Rb2SO4
ZnOHCl + H2SO4 = HCl + H2O + ZnSO4 =>
ZnOHCl + H2SO4 = HCl + H2O + ZnSO4
NaCl + H2SO4 + KMnO4 = MnSO4 + H2O + Cl2 + K2SO4 + Na2SO4 =>
10 NaCl + 8 H2SO4 + 2 KMnO4 = 2 MnSO4 + 8 H2O + 5 Cl2 + K2SO4 + 5 Na2SO4
CH4S(g) + O2(g) = CO2(g) + H2O(l) + SO(g) =>
2 CH4S(g) + 5 O2(g) = 2 CO2(g) + 4 H2O(l) + 2 SO(g)
Ce(NO3)3 + SrCl2 = Sr(NO3)2 + CeCl3 =>
2 Ce(NO3)3 + 3 SrCl2 = 3 Sr(NO3)2 + 2 CeCl3
CaCl2 + NaHSO4 = CaSO4 + NaHCl2 =>
CaCl2 + NaHSO4 = CaSO4 + NaHCl2
K2Cr2O7 + K2S2O3 + H2SO4 = Cr2(SO4)3 + K2SO4 + H2O =>
4 K2Cr2O7 + 3 K2S2O3 + 13 H2SO4 = 4 Cr2(SO4)3 + 7 K2SO4 + 13 H2O
C4H11NO2 + SOCl2 = C4H10NCl3 + HCl + SO2 =>
C4H11NO2 + 2 SOCl2 = C4H10NCl3 + HCl + 2 SO2
Mg{2+}{+} + H2O = Mg(H2O)4{2+} =>
Mg{2+}{+} + 4 H2O = Mg(H2O)4{2+}
Fe3O2 + H2SO4 = Fe3(SO4)2 + H2O =>
Fe3O2 + 2 H2SO4 = Fe3(SO4)2 + 2 H2O
KI + KMnO4 + H2SO4 = I2 + K2SO4 + MnO2 + H2O =>
6 KI + 2 KMnO4 + 4 H2SO4 = 3 I2 + 4 K2SO4 + 2 MnO2 + 4 H2O
S(s) + Cu(s) = CuS =>
S(s) + Cu(s) = CuS
iron + sodiumhydroxide = ironoxide + sodiumhydride =>
2 Fe + 3 NaOH = Fe2O3 + 3 NaH
C6H6S + O2 = CO2 + H2SO4 + H2O =>
C6H6S + 9 O2 = 6 CO2 + H2SO4 + 2 H2O
K2Cr2O7 + HI + H2SO4 = Cr2(SO4)3 + K2SO4 + I2 + H2O =>
K2Cr2O7 + 6 HI + 4 H2SO4 = Cr2(SO4)3 + K2SO4 + 3 I2 + 7 H2O
Cr2O7{-2} + H{+} + {-} = Cr{+3} + H2O =>
Cr2O7{-2} + 14 H{+} + 6e = 2 Cr{+3} + 7 H2O
C6H5COOH + O2 = CO2 + H2O =>
2 C6H5COOH + 15 O2 = 14 CO2 + 6 H2O
Cu + HNO3 = Cu(NO3)2 + NO2 + H2O =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O
CuSO4*5H2O + NH4OH = [Cu(NH3)4]SO4 + H2O =>
CuSO4*5H2O + 4 NH4OH = [Cu(NH3)4]SO4 + 9 H2O
C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O
K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O
KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2
Cu + HNO3 = Cu(NO3)2 + NO2 + H2O =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O
KCl + Br2 = KBr + Cl2 =>
2 KCl + Br2 = 2 KBr + Cl2
CuSO4*5H2O = CuSO4 + H2O =>
CuSO4*5H2O = CuSO4 + 5 H2O
KCrO2 + HCl = CrCl3 + KCl + H2O =>
KCrO2 + 4 HCl = CrCl3 + KCl + 2 H2O
PhCH3 + KMnO4 + H2SO4 = PhCOOH + K2SO4 + MnSO4 + H2O =>
5 PhCH3 + 6 KMnO4 + 9 H2SO4 = 5 PhCOOH + 3 K2SO4 + 6 MnSO4 + 14 H2O
C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O
Na2S2O3 + I2 = Na2S4O6 + NaI =>
2 Na2S2O3 + I2 = Na2S4O6 + 2 NaI
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 01/12/25
Equations balanced on 02/11/24
Please let us know how we can improve this web app.