| Equations balanced on the previous day |
MnO4 + 8 HCl = MnCl2 + 4 H2O + 2 Cl3
H2O + C4H6O2 = C4H8O3 =>
H2O + C4H6O2 = C4H8O3
Fe(ClO2)3 + NaOH = Fe(OH)3 + NaClO2 =>
Fe(ClO2)3 + 3 NaOH = Fe(OH)3 + 3 NaClO2
C4H9OH + PCl5 = C4H9Cl + HCl + POCl3 =>
C4H9OH + PCl5 = C4H9Cl + HCl + POCl3
C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
HBr + HNO3 = HBrO3 + NO2 + H2O =>
HBr + 6 HNO3 = HBrO3 + 6 NO2 + 3 H2O
C2H5OH + O2 = C2O4OH + H2 =>
2 C2H5OH + 4 O2 = 2 C2O4OH + 5 H2
(COOH)2 + NH4OH = (NH4)2C2O4 + H2O =>
(COOH)2 + 2 NH4OH = (NH4)2C2O4 + 2 H2O
CH2(COOH)2 + MnSO4 = CH2SO4 + Mn(COOH)2 =>
CH2(COOH)2 + MnSO4 = CH2SO4 + Mn(COOH)2
I2 + Ag3PO4 = I3(PO4)2 + Ag =>
3 I2 + 4 Ag3PO4 = 2 I3(PO4)2 + 12 Ag
Pb(C2H3O2)2(aq) + LiCl(aq) = Li(C2H3O2) + PbCl2 =>
Pb(C2H3O2)2(aq) + 2 LiCl(aq) = 2 Li(C2H3O2) + PbCl2
MgF2 + Li2CO3 = LiF + MgCO3 =>
MgF2 + Li2CO3 = 2 LiF + MgCO3
C8H18 + O2 = CO + H2O =>
2 C8H18 + 17 O2 = 16 CO + 18 H2O
CrO2{-} + OH{-} = CrO42{-} + H2O + e =>
CrO2{-} + 80 OH{-} = CrO42{-} + 40 H2O + 80e
NH3 + CS2 = H2S + NH4SCN =>
2 NH3 + CS2 = H2S + NH4SCN
Fe(NH4)2(SO4)2*6H2O + H2C2O4 + K2C2O4 + H2O2 = KFe(C2O4)2*2H2O + (NH4)2SO4 + H2SO4 + H2O =>
2 Fe(NH4)2(SO4)2*6H2O + 3 H2C2O4 + K2C2O4 + H2O2 = 2 KFe(C2O4)2*2H2O + 2(NH4)2SO4 + 2 H2SO4 + 10 H2O
Cl2O7 + H2O = HClO4 =>
Cl2O7 + H2O = 2 HClO4
Li + H2O = LiOH + H2 =>
2 Li + 2 H2O = 2 LiOH + H2
Mn(NO3)2 + CH3COOH + {-} = Mn(CH3COO)2 + HNO4 + H2{+} + N2{-3} =>
4 Mn(NO3)2 + 8 CH3COOH + 2e = 4 Mn(CH3COO)2 + 6 HNO4 + H2{+} + N2{-3}
Fe(s) + HClO4(aq) = Fe(ClO4)3 + H2 =>
2 Fe(s) + 6 HClO4(aq) = 2 Fe(ClO4)3 + 3 H2
Li3(PO)4 + Ca(OH)2 = Li3(OH)2 + Ca(PO)4 =>
Li3(PO)4 + Ca(OH)2 = Li3(OH)2 + Ca(PO)4
Ca10F2(PO4)6 + H2SO4 = Ca(H2PO4)2 + CaSO4 + HF =>
Ca10F2(PO4)6 + 7 H2SO4 = 3 Ca(H2PO4)2 + 7 CaSO4 + 2 HF
SO3{2-} + MnO4 + H{+} = SO4{2-} + Mn{2+} + H2O =>
3 SO3{2-} + MnO4 + 2 H{+} = 3 SO4{2-} + Mn{2+} + H2O
H3BO3 + OH = H2O + BO3 =>
H3BO3 + 3 OH = 3 H2O + BO3
C18H19O9N + O2 + NH3 = C10H14O4N2 + C4H4O4 =>
2 C18H19O9N + 3 O2 + 2 NH3 = 2 C10H14O4N2 + 4 C4H4O4
Ag2CrO4 + NaCl = Ag2Cl + NaCrO4 =>
Ag2CrO4 + NaCl = Ag2Cl + NaCrO4
Cu(OH)2 + (NH4)2SO4 + NH4OH = (Cu(NH3)4)SO4 + H2O =>
Cu(OH)2 + (NH4)2SO4 + 2 NH4OH = (Cu(NH3)4)SO4 + 4 H2O
CH3OH + Na2CO3 = NaOCH3 + H2O + CO2 =>
2 CH3OH + Na2CO3 = 2 NaOCH3 + H2O + CO2
FeCl3 + Na2Co3 = FeCl3Na2Co3 =>
FeCl3 + Na2Co3 = FeCl3Na2Co3
Au2O3 + NaOH + H2O = NaAu(OH)4 =>
Au2O3 + 2 NaOH + 3 H2O = 2 NaAu(OH)4
Cr(OH)6 + H3(PO4) = H2O + Cr3(PO4)6 =>
3 Cr(OH)6 + 6 H3(PO4) = 18 H2O + Cr3(PO4)6
HNO3 + OH{-} = NO3{-} + H2O =>
HNO3 + OH{-} = NO3{-} + H2O
H2SeO3 + Pb(OH)2 = Pb(HSeO3)2 + H2O =>
2 H2SeO3 + Pb(OH)2 = Pb(HSeO3)2 + 2 H2O
O2 + H{-} + Cl2 = H2O + Cl{-} =>
O2 + 4 H{-} + 2 Cl2 = 2 H2O + 4 Cl{-}
NCl + Ca(OH)2 = CaCl2 + NOH =>
2 NCl + Ca(OH)2 = CaCl2 + 2 NOH
NaOCl + C3H6O = CHCl3 + NaOH + NaCH3COO =>
3 NaOCl + C3H6O = CHCl3 + 2 NaOH + NaCH3COO
NaNO3 + AgCl = Ag(NO3) + NaCl =>
NaNO3 + AgCl = Ag(NO3) + NaCl
C6H4OHCOOCH4 + NaOH = C7H4Na2O3 + CH3OH + H2O =>
14 C6H4OHCOOCH4 + 26 NaOH = 13 C7H4Na2O3 + 21 CH3OH + 8 H2O
C3H6ClCOOH + O2 = CO2 + H2O + Cl2 =>
4 C3H6ClCOOH + 19 O2 = 16 CO2 + 14 H2O + 2 Cl2
KMnO4 + HCl + H2SO4 = Cl2 + MnSO4 + K2SO4 + H2O =>
2 KMnO4 + 10 HCl + 3 H2SO4 = 5 Cl2 + 2 MnSO4 + K2SO4 + 8 H2O
C2H4 + NaOH = C2H5ONa =>
C2H4 + NaOH = C2H5ONa
H{+} + As2S5 + NO3{-} = H3AsO4{2-} + HSO4{-} + NO2 + H2O =>
27 H{+} + As2S5 + 36 NO3{-} = 2 H3AsO4{2-} + 5 HSO4{-} + 36 NO2 + 8 H2O
Na3PO4 + BaCl = Ba3PO4 + NaCl =>
Na3PO4 + 3 BaCl = Ba3PO4 + 3 NaCl
CO2 + H2O = C6H12 + O2 =>
6 CO2 + 6 H2O = C6H12 + 9 O2
(NH4)3P + S = (NH4)2S + P =>
2(NH4)3P + 3 S = 3(NH4)2S + 2 P
Mg + H2O + NH3 = Mg(OH)2 + NH4 =>
Mg + 2 H2O + 2 NH3 = Mg(OH)2 + 2 NH4
Na2O + CrO3 = Cr(NaO2)2 =>
Na2O + CrO3 = Cr(NaO2)2
Cr2(SO4)3 + Br2 + NaOH = Na2CrO4 + NaBr + Na2SO4 + H2O =>
Cr2(SO4)3 + 3 Br2 + 16 NaOH = 2 Na2CrO4 + 6 NaBr + 3 Na2SO4 + 8 H2O
K2MnO4 + HNO3 = KMnO4 + NO2 + KNO3 + H2O =>
K2MnO4 + 2 HNO3 = KMnO4 + NO2 + KNO3 + H2O
Pb(Cl)2 = Pb + Cl =>
Pb(Cl)2 = Pb + 2 Cl
Balance the equation of any chemical reaction
| Equations balanced on the previous day |
Equations balanced on 10/24/24
Equations balanced on 11/23/23
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