Equations balanced on the previous day |
2 AgNO3(aq) + K2CrO4 = Ag2CrO4(s) + 2 KNO3(aq)
Ni{2+} + NH4OH = Ni(NH3)6{2+} + H2O =>
Ni{2+} + 6 NH4OH = Ni(NH3)6{2+} + 6 H2O
Ba(NO3)2 + CO = N2 + CO2 + BaO =>
Ba(NO3)2 + 5 CO = N2 + 5 CO2 + BaO
IO4{-} + Mn{2+} + H2O = MnO4{-} + H{+} + MnI2 =>
10 IO4{-} + 21 Mn{2+} + 24 H2O = 16 MnO4{-} + 48 H{+} + 5 MnI2
KI + CCl4 + Br2 = KBr + Cl2 + CCl2I2 =>
2 KI + CCl4 + Br2 = 2 KBr + Cl2 + CCl2I2
Ta + H2O = Ta2O5 + H2 =>
2 Ta + 5 H2O = Ta2O5 + 5 H2
(NH4)2Fe(SO4)2 + K3[Fe(CN)6] = Fe3[Fe(CN)6]2 + (NH4)2SO4 + K2SO4 =>
3(NH4)2Fe(SO4)2 + 2 K3[Fe(CN)6] = Fe3[Fe(CN)6]2 + 3(NH4)2SO4 + 3 K2SO4
InN3O9 + C12H28O4Ti + C5H8O2 = In12Ti2O22 + CO2 + H2O + N2 =>
24 InN3O9 + 4 C12H28O4Ti + 3 C5H8O2 = 2 In12Ti2O22 + 63 CO2 + 68 H2O + 36 N2
Fe2O3 + Ti2O3 + TiCl3 = TiFeO2Cl2 =>
3 Fe2O3 + Ti2O3 + 4 TiCl3 = 6 TiFeO2Cl2
NH4Cl + Ca(OH)2 = CaCl2 + NH3 + H2O = NH4Cl + Ca(OH)2 = NH3 + H2O + CaCl2 =>
2 NH4Cl + Ca(OH)2 = CaCl2 + 2 NH3 + 2 H2O
CaCl2(ac) + Na3Po4(ac) = Ca3(Po4)2 + NaCl =>
3 CaCl2(ac) + 2 Na3Po4(ac) = Ca3(Po4)2 + 6 NaCl
K2S + O2 = SO2 + K2O =>
2 K2S + 3 O2 = 2 SO2 + 2 K2O
KMnO4 + K2HPO3 + H2SO4 = MnSO4 + H3PO4 + K2SO4 + H2O =>
2 KMnO4 + 5 K2HPO3 + 8 H2SO4 = 2 MnSO4 + 5 H3PO4 + 6 K2SO4 + 3 H2O
Mg + Ni2(SO4)3 = Ni + MgSO4 =>
3 Mg + Ni2(SO4)3 = 2 Ni + 3 MgSO4
CH3SH + CO = CH3CO(SCH3) + H2S =>
2 CH3SH + CO = CH3CO(SCH3) + H2S
FeTiO3 + H2SO4 + H2O = FeSO4*7H2O + TiOSO4 =>
FeTiO3 + 2 H2SO4 + 5 H2O = FeSO4*7H2O + TiOSO4
MgCl{-2} + KOH = Mg(OH){-2} + KCl =>
MgCl{-2} + KOH = Mg(OH){-2} + KCl
HNO3 + H30 = H2O + NO2 =>
30 HNO3 + H30 = 30 H2O + 30 NO2
Pb(NO3)2(aq) + Al2(SO4)3(aq) = PbSO4 + Al(NO3)3(aq) =>
3 Pb(NO3)2(aq) + Al2(SO4)3(aq) = 3 PbSO4 + 2 Al(NO3)3(aq)
POCl3 + H2O = H3PO4 + HCl =>
POCl3 + 3 H2O = H3PO4 + 3 HCl
Al(OH)3 + KBrO4 = Al(BrO4)3 + KOH =>
Al(OH)3 + 3 KBrO4 = Al(BrO4)3 + 3 KOH
Al(s) + Cl2 = AlCl3(g) =>
2 Al(s) + 3 Cl2 = 2 AlCl3(g)
B + NaOH + O2 = Na2B4O7 + H2O =>
4 B + 2 NaOH + 3 O2 = Na2B4O7 + H2O
Zn = Zn{2+} + e =>
Zn = Zn{2+} + 2e
OF2 + H2O = HF + O2 =>
OF2 + H2O = 2 HF + O2
HIO3 + CO = CO2 + I + H2O =>
2 HIO3 + 5 CO = 5 CO2 + 2 I + H2O
Ag2SO4 + Ba(NO3)2 = Ag2SO4Ba(NO3)2 =>
Ag2SO4 + Ba(NO3)2 = Ag2SO4Ba(NO3)2
Na3PO4(aq) + ZnSO4(aq) = Na2SO4 + Zn3(PO4)2 =>
2 Na3PO4(aq) + 3 ZnSO4(aq) = 3 Na2SO4 + Zn3(PO4)2
MnS + HClO = MnSO4 + HCl =>
MnS + 4 HClO = MnSO4 + 4 HCl
N(CH3)3 + H2O = OH + HN(CH3)3 =>
N(CH3)3 + H2O = OH + HN(CH3)3
POCl3 + H2O = H3PO4 + HCl =>
POCl3 + 3 H2O = H3PO4 + 3 HCl
B + HClO3 + H2O = H2BO3 + HCl =>
3 B + 2 HClO3 + 3 H2O = 3 H2BO3 + 2 HCl
Ni(OH)2 + Cl2 + H2O = Ni(OH)3 + HCl =>
2 Ni(OH)2 + Cl2 + 2 H2O = 2 Ni(OH)3 + 2 HCl
H2SO4 + H2O = H3O + SO4 =>
H2SO4 + 2 H2O = 2 H3O + SO4
Zn + HCe = H2 + ZnCe =>
2 Zn + 2 HCe = H2 + 2 ZnCe
H2SiO3 + Ba(OH)2 = H2O + Ba(HSiO3)2 =>
2 H2SiO3 + Ba(OH)2 = 2 H2O + Ba(HSiO3)2
HI(aq) + H2O2(aq) = I2(s) + H2O(l) =>
2 HI(aq) + H2O2(aq) = I2(s) + 2 H2O(l)
PH3 + Cl = PCl3 + HCl =>
PH3 + 6 Cl = PCl3 + 3 HCl
Al2O3 + Mg3(PO4)2 = AlPO4 + MgO =>
Al2O3 + Mg3(PO4)2 = 2 AlPO4 + 3 MgO
NiCl2*6H2O + C2H6O = Ni(C2H6)6Cl2 + H2O + CO2 =>
NiCl2*6H2O + 7 C2H6O = Ni(C2H6)6Cl2 + 9 H2O + 2 CO2
Br2 + NaOH = NaBr + NaBrO + H2O =>
Br2 + 2 NaOH = NaBr + NaBrO + H2O
C21H22NO5 + O2 = CO2 + H2O + N =>
C21H22NO5 + 24 O2 = 21 CO2 + 11 H2O + N
AlOHCl2 + Al(OH)3 = Al(OH)2Cl =>
AlOHCl2 + Al(OH)3 = 2 Al(OH)2Cl
Yb(NO3)3(H2O)5 = Yb{3+} + NO3{-} + H2O =>
Yb(NO3)3(H2O)5 = Yb{3+} + 3 NO3{-} + 5 H2O
K(ClO3) + H2SO4 = KHSO4 + O2 + ClO2 + H2O =>
4 K(ClO3) + 4 H2SO4 = 4 KHSO4 + O2 + 4 ClO2 + 2 H2O
Cr + ClO3{-} + H{+} = Cr3{+} + HClO2 + H2O =>
6 Cr + ClO3{-} + 3 H{+} = 2 Cr3{+} + HClO2 + H2O
C(s) + S8(s) + KNO3(s) = CO2(g) + N2(g) + K2S(s) =>
24 C(s) + S8(s) + 16 KNO3(s) = 24 CO2(g) + 8 N2(g) + 8 K2S(s)
CO2 + WS2 = WO2 + CO + SO2 =>
6 CO2 + WS2 = WO2 + 6 CO + 2 SO2
HNO3 + H3P = H3PO4 + H2O + N2 =>
8 HNO3 + 5 H3P = 5 H3PO4 + 4 H2O + 4 N2
Ag2S + H2O + Al = H2S + Ag + Al2O3 =>
3 Ag2S + 3 H2O + 2 Al = 3 H2S + 6 Ag + Al2O3
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 10/24/24
Equations balanced on 11/23/23
Please let us know how we can improve this web app.