Equations balanced on the previous day |
4 CH3Cl + 3 Cl2 = 4 CH2Cl2 + 2 H2Cl
Na2CO3 + HCl = NaCl + H2O1 + CO2 =>
Na2CO3 + 2 HCl = 2 NaCl + H2O1 + CO2
C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O
FeCl3 + K3[Fe(CN)6] + SnCl2 = SnCl4 + K[Fe2(CN)6] + KCl =>
2 FeCl3 + 2 K3[Fe(CN)6] + SnCl2 = SnCl4 + 2 K[Fe2(CN)6] + 4 KCl
C3H8 + NH3 + O2 = C2H3N + H2O =>
2 C3H8 + 3 NH3 + 4 O2 = 3 C2H3N + 8 H2O
NaCl + H2SO4 = Na2SO4 + HCl =>
2 NaCl + H2SO4 = Na2SO4 + 2 HCl
C5H11COOH + H2O = HCOOH + C5H11OH =>
C5H11COOH + H2O = HCOOH + C5H11OH
H2S + O2 = SO2 + H2O =>
2 H2S + 3 O2 = 2 SO2 + 2 H2O
Ga(s) + Cl2(g) = GaCl3 =>
2 Ga(s) + 3 Cl2(g) = 2 GaCl3
CH3CH3 + O2 = CO2 + H2O =>
2 CH3CH3 + 7 O2 = 4 CO2 + 6 H2O
Cu + Na(NO3) + H2SO4 = CuSO4 + Na2SO4 + NO + H2O =>
3 Cu + 2 Na(NO3) + 4 H2SO4 = 3 CuSO4 + Na2SO4 + 2 NO + 4 H2O
Na2SO4 + I2 + K2SO4 + H2O = Na2SO3 + KIO3 + H2SO4 =>
5 Na2SO4 + I2 + K2SO4 + H2O = 5 Na2SO3 + 2 KIO3 + H2SO4
H2SO3 + Cu(OH) = Cu(SO3)2 + H2O + H =>
2 H2SO3 + Cu(OH) = Cu(SO3)2 + H2O + 3 H
MgSO3 + SO2 + H2O = Mg(HSO3)2 =>
MgSO3 + SO2 + H2O = Mg(HSO3)2
NO + H2SO4 + KMnO4 = NO3 + K2SO4 + MnSO4 + H2O =>
5 NO + 6 H2SO4 + 4 KMnO4 = 5 NO3 + 2 K2SO4 + 4 MnSO4 + 6 H2O
H2SeO3 + PbCl2 + HCl = PbSe + PbCl4 + H2O =>
H2SeO3 + 4 PbCl2 + 4 HCl = PbSe + 3 PbCl4 + 3 H2O
BrO{-} + NH3 = Br{-} + N2 + H2O =>
3 BrO{-} + 2 NH3 = 3 Br{-} + N2 + 3 H2O
V + HF = VF + H =>
V + HF = VF + H
beryllium + water = berylliumhydroxide + hydrogen =>
Be + 2 H2O = Be(OH)2 + H2
C6H5I + Cu = C6H5C6H5 + I2Cu =>
2 C6H5I + Cu = C6H5C6H5 + I2Cu
NH4OH + AlCl3 = Al(OH)3 + ClNH4 =>
3 NH4OH + AlCl3 = Al(OH)3 + 3 ClNH4
PbO(s) + NH3(aq) = Pb(s) + N2(g) + H2O(l) =>
3 PbO(s) + 2 NH3(aq) = 3 Pb(s) + N2(g) + 3 H2O(l)
SO2 + SnCl2 + HCl = SnCl4 + H2SO4 + S =>
2 SO2 + SnCl2 + 2 HCl = SnCl4 + H2SO4 + S
K(s) + H2O(g) = KOH(aq) + H2(g) =>
2 K(s) + 2 H2O(g) = 2 KOH(aq) + H2(g)
K3PO4 + CaCO3 = K2CO3 + Ca3(PO4)2 =>
2 K3PO4 + 3 CaCO3 = 3 K2CO3 + Ca3(PO4)2
FeCl + Na2S2O4 = Fe + Na2S2O4Cl =>
FeCl + Na2S2O4 = Fe + Na2S2O4Cl
AlCl3 + K(OH)3 = Al(OH)3 + KCl3 =>
AlCl3 + K(OH)3 = Al(OH)3 + KCl3
Cu(NO3)2 + (NH4) = Cu + NH4(NO3)2 =>
Cu(NO3)2 + (NH4) = Cu + NH4(NO3)2
Ag + Hg(NO3)2 = Hg2 + Ag(NO3) =>
4 Ag + 2 Hg(NO3)2 = Hg2 + 4 Ag(NO3)
C2H5OH + Na = C2H5ONa + H2 =>
2 C2H5OH + 2 Na = 2 C2H5ONa + H2
AgS + AlCl = AgCl + AlS =>
AgS + AlCl = AgCl + AlS
NO2 + C = NO + CO2 =>
2 NO2 + C = 2 NO + CO2
Mg + HO = MgO + H2O =>
Mg + 2 HO = MgO + H2O
Cu(NO3)2 + FeI3 = CuI2 + Fe(NO3)3 =>
3 Cu(NO3)2 + 2 FeI3 = 3 CuI2 + 2 Fe(NO3)3
NH4NO3 + H2O = NH6 + NO4 =>
NH4NO3 + H2O = NH6 + NO4
Ba + HNO3 = Ba(NO3)2 + H2O + N20 =>
50 Ba + 120 HNO3 = 50 Ba(NO3)2 + 60 H2O + N20
H3PO4 + NH3 = (NH4)3PO4 =>
H3PO4 + 3 NH3 = (NH4)3PO4
BaO + SO3 = SO2 + BaO2 =>
BaO + SO3 = SO2 + BaO2
K3PO4 + LiOH = KOH + Li3PO4 =>
K3PO4 + 3 LiOH = 3 KOH + Li3PO4
CaCO3 + H2O = HCO3 + Ca(OH) =>
CaCO3 + H2O = HCO3 + Ca(OH)
La100(N100O300)300 + Ni100(N100O300)2*6H200O100 + Fe100(N100O300)300*9H200O100 = La100Ni75Fe25O300 + N100O100 + O200 + H200O100 =>
4.0000000000004La100(N100O300)300 + 3.0000000000003Ni100(N100O300)2*6H200O100 + Fe100(N100O300)300*9H200O100 = 4.0000000000003La100Ni75Fe25O300 + 1506.0000000001N100O100 + 1500.0000000001O200 + 27.000000000002H200O100
AgNO3(s) + NaCl(aq) = AgCl(s) + Na{+} + NO3{-} =>
AgNO3(s) + NaCl(aq) = AgCl(s) + Na{+} + NO3{-}
NiSO4(H2O)6 + C2H8N2 = [Ni(C2H8N2)3]SO4 + H2O =>
NiSO4(H2O)6 + 3 C2H8N2 = [Ni(C2H8N2)3]SO4 + 6 H2O
Mg3(PO4)2 + H2SO4 = MgSO4 + H3(PO4) =>
Mg3(PO4)2 + 3 H2SO4 = 3 MgSO4 + 2 H3(PO4)
C27H46O + O2 = CO2 + H2O =>
C27H46O + 38 O2 = 27 CO2 + 23 H2O
PbCO3 + KNO3 = Pb3O4 + KNO2 + CO2 =>
3 PbCO3 + KNO3 = Pb3O4 + KNO2 + 3 CO2
Br2(g) + H2O(l) + SO2(g) = HBr(aq) + H1SO4(aq) =>
3 Br2(g) + 4 H2O(l) + 2 SO2(g) = 6 HBr(aq) + 2 H1SO4(aq)
(NH4)NO3 + NaOH = Na(NO3) + NH3 + H2O =>
(NH4)NO3 + NaOH = Na(NO3) + NH3 + H2O
LiF + H2SO4 = Li2SO4 + HF =>
2 LiF + H2SO4 = Li2SO4 + 2 HF
Ba(OH)2 + KHCO3 = BaCO3 + K2CO3 + H2O =>
Ba(OH)2 + 2 KHCO3 = BaCO3 + K2CO3 + 2 H2O
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 10/24/24
Equations balanced on 11/23/23
Please let us know how we can improve this web app.