Equations balanced on the previous day | Equations balanced on the next day |
2 KCl + S = 2 K + SCl2
Li2(CO3) + NaCl = LiCl + Na2(CO3) =>
Li2(CO3) + 2 NaCl = 2 LiCl + Na2(CO3)
H2S + H2O2 = H2SO4 + H2O =>
H2S + 4 H2O2 = H2SO4 + 4 H2O
K2O + NO + KMnO4 = KNO3 + MnO =>
K2O + 5 NO + 3 KMnO4 = 5 KNO3 + 3 MnO
NH3 + O2 = NO2 + H2O =>
4 NH3 + 7 O2 = 4 NO2 + 6 H2O
NaNO3 = NaNO2 + O3 =>
3 NaNO3 = 3 NaNO2 + O3
NO2 + H2O = NO4 + H10 =>
5 NO2 + 10 H2O = 5 NO4 + 2 H10
OC8H18 + O2 = CO2 + H2O =>
OC8H18 + 12 O2 = 8 CO2 + 9 H2O
KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2
K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O
Hg + HNO3 + HSO4 = Hg2SO4 + NO + H2O =>
6 Hg + HNO3 + 3 HSO4 = 3 Hg2SO4 + NO + 2 H2O
Cu + HNO3 = Cu(NO3)2 + NO2 + H2O =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O
K4Fe(CN)6 + H2SO4 + H2O = K2SO4 + FeSO4 + (NH4)2SO4 + CO =>
K4Fe(CN)6 + 6 H2SO4 + 6 H2O = 2 K2SO4 + FeSO4 + 3(NH4)2SO4 + 6 CO
Cu + HNO3 = Cu(NO3)2 + NO2 + H2O =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O
H2SO4 + K4Fe(CN)6 + KMnO4 = CO2 + Fe2(SO4)3 + H2O + HNO3 + KHSO4 + MnSO4 =>
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122 MnSO4
C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
C6H5COOH + O2 = CO2 + H2O =>
2 C6H5COOH + 15 O2 = 14 CO2 + 6 H2O
PhCH3 + KMnO4 + H2SO4 = PhCOOH + K2SO4 + MnSO4 + H2O =>
5 PhCH3 + 6 KMnO4 + 9 H2SO4 = 5 PhCOOH + 3 K2SO4 + 6 MnSO4 + 14 H2O
CaSiO3 + CaAl2Si2O8 = Ca3Al2Si3O12 + SiO2 =>
2 CaSiO3 + CaAl2Si2O8 = Ca3Al2Si3O12 + SiO2
CH3COOCH3 + H2O = CH3COOH + CH3OH =>
CH3COOCH3 + H2O = CH3COOH + CH3OH
(NH4)(NO3) + Na(OH) = Na(NO3) + NH3 + H2O =>
(NH4)(NO3) + Na(OH) = Na(NO3) + NH3 + H2O
H2O + BrO3{-} + NH3OH{+} = Br{-} + NO3{-} + H3O{+} =>
H2O + BrO3{-} + NH3OH{+} = Br{-} + NO3{-} + 2 H3O{+}
FeCl3 + NaI = Fe + I2 + NaCl =>
2 FeCl3 + 6 NaI = 2 Fe + 3 I2 + 6 NaCl
FeBr3 + Br2 + KOH = K2FeO4 + KBr + H2O =>
2 FeBr3 + 3 Br2 + 16 KOH = 2 K2FeO4 + 12 KBr + 8 H2O
MnO2 + NaCl + H2SO4 = Cl2 + Na2SO4 + H2O + MnCl2 =>
MnO2 + 4 NaCl + 2 H2SO4 = Cl2 + 2 Na2SO4 + 2 H2O + MnCl2
H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O
FeCl3 + Na3(PO4) = Fe(PO4) + Na3Cl3 =>
FeCl3 + Na3(PO4) = Fe(PO4) + Na3Cl3
ZnS + HNO3 = H2S + Zn(NO3)2 =>
ZnS + 2 HNO3 = H2S + Zn(NO3)2
H2(g) + O(g) = H2O =>
H2(g) + O(g) = H2O
ZnS + HNO3 = H2S + Zn(NO3)2 =>
ZnS + 2 HNO3 = H2S + Zn(NO3)2
Si2H6 + H2O = Si(OH)4 + H2 =>
Si2H6 + 8 H2O = 2 Si(OH)4 + 7 H2
ZnS + HNO3 = H2S + Zn(NO3)2 =>
ZnS + 2 HNO3 = H2S + Zn(NO3)2
CaO + water = Ca(OH)2 =>
CaO + H2O = Ca(OH)2
FeSO4 + KMnO4 + H2SO4 = MnO2 + K2SO4 + Fe2(SO4)3 + H2O =>
6 FeSO4 + 2 KMnO4 + 4 H2SO4 = 2 MnO2 + K2SO4 + 3 Fe2(SO4)3 + 4 H2O
K2CO3(aq) + BaBr2(aq) = BaCO3(s) + KBr(aq) =>
K2CO3(aq) + BaBr2(aq) = BaCO3(s) + 2 KBr(aq)
HC3H5O2 + NaOH = C3H5NaO2 + H2O =>
HC3H5O2 + NaOH = C3H5NaO2 + H2O
NiBr3 = Br2 + Ni =>
2 NiBr3 = 3 Br2 + 2 Ni
KCN(aq) + HBr(aq) = KBr(aq) + HCN(g) =>
KCN(aq) + HBr(aq) = KBr(aq) + HCN(g)
Al2O3 + H2SO4 = Al{3+} + SO4{2-} + H2O =>
Al2O3 + 3 H2SO4 = 2 Al{3+} + 3 SO4{2-} + 3 H2O
Sn(OH)2 + CO2 = Sn(HCO3)2 =>
Sn(OH)2 + 2 CO2 = Sn(HCO3)2
I3N = I2 + N2 =>
2 I3N = 3 I2 + N2
ZnO + NaHCO3 = Na2CO3 + ZnCO3 + H2O =>
ZnO + 2 NaHCO3 = Na2CO3 + ZnCO3 + H2O
Cr2O7 + H2SO3 = Cr + SO4 + H2O =>
2 Cr2O7 + 7 H2SO3 = 4 Cr + 7 SO4 + 7 H2O
H{+} + Cr2O7{2-} + H3PO3 = Cr{3+} + H3PO4 + H2O =>
8 H{+} + Cr2O7{2-} + 3 H3PO3 = 2 Cr{3+} + 3 H3PO4 + 4 H2O
AlCl3 + Na2(SO4) = Al2(SO4)3 + NaCl =>
2 AlCl3 + 3 Na2(SO4) = Al2(SO4)3 + 6 NaCl
P2O5 + H2SO4 = P2(SO4)5 + H2O =>
P2O5 + 5 H2SO4 = P2(SO4)5 + 5 H2O
FeCl3 + Zn = ZnCl2 + Fe =>
2 FeCl3 + 3 Zn = 3 ZnCl2 + 2 Fe
K(s) + HCl = KCl + H2 =>
2 K(s) + 2 HCl = 2 KCl + H2
Na3PO4 + HBr = Na3Br + PO4H =>
Na3PO4 + HBr = Na3Br + PO4H
H2Fe + H2O = Fe3O4 + H2 =>
3 H2Fe + 4 H2O = Fe3O4 + 7 H2
Balance the equation of any chemical reaction
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/19/25
Equations balanced on 03/21/24
Please let us know how we can improve this web app.