Equations balanced on the previous day | Equations balanced on the next day |
C6H8O6 + NaOH = C6H9O7 + Na
CO3{2-} + HCl = HCO3{-} + Cl{-} =>
CO3{2-} + HCl = HCO3{-} + Cl{-}
ZnI2(aq) + Na2CO3(aq) = NaI + ZnCO3 =>
ZnI2(aq) + Na2CO3(aq) = 2 NaI + ZnCO3
Mn(CH3COO)2 + (NH4)2S2O8 + H2O = MnO2 + H2SO4 + NH4CH3COO =>
Mn(CH3COO)2 + (NH4)2S2O8 + 2 H2O = MnO2 + 2 H2SO4 + 2 NH4CH3COO
Co(OH)2 + CH2O2 = Co(CHO2)2 + H2O =>
Co(OH)2 + 2 CH2O2 = Co(CHO2)2 + 2 H2O
C6H12O + H{+} + Cr2O7{2-} = C6H10O + H2O + Cr{3+} =>
3 C6H12O + 8 H{+} + Cr2O7{2-} = 3 C6H10O + 7 H2O + 2 Cr{3+}
Na2CO3 + C6H8O7 = Na2C6H6O7 + CO2 + H2O =>
Na2CO3 + C6H8O7 = Na2C6H6O7 + CO2 + H2O
Fe(SCN)3 + SnCl2 = FeCl3 + Sn(SCN)2 =>
2 Fe(SCN)3 + 3 SnCl2 = 2 FeCl3 + 3 Sn(SCN)2
Re + Cl2 = ReCl3 =>
2 Re + 3 Cl2 = 2 ReCl3
PCl3 + KClO3 + H2O = H3PO4 + KCl + HCl =>
3 PCl3 + KClO3 + 9 H2O = 3 H3PO4 + KCl + 9 HCl
NaC2H3O2 + PbSO4 = Pb(C2H3O2)2 + Na2SO4 =>
2 NaC2H3O2 + PbSO4 = Pb(C2H3O2)2 + Na2SO4
PdCl2 + NH4OH = Pd(NH3)2Cl2 + H2O =>
PdCl2 + 2 NH4OH = Pd(NH3)2Cl2 + 2 H2O
Cr(NO3)3 + KClO3 = Cr(ClO3)3 + KNO3 =>
Cr(NO3)3 + 3 KClO3 = Cr(ClO3)3 + 3 KNO3
NaCO3{-}2 + HCl = NaCl + HCO3{-}2 =>
NaCO3{-}2 + HCl = NaCl + HCO3{-}2
Cr2(SO4)3 + HNO3 = Cr(NO3)3 + H2SO4 =>
Cr2(SO4)3 + 6 HNO3 = 2 Cr(NO3)3 + 3 H2SO4
C3H5(OH)3 + NaOH = C3H5(ONa)3 + H2O =>
C3H5(OH)3 + 3 NaOH = C3H5(ONa)3 + 3 H2O
Cr(OH)3 + Na2CO3 = NaCrO2 + H2O + CO2 =>
2 Cr(OH)3 + Na2CO3 = 2 NaCrO2 + 3 H2O + CO2
MgN + Cl2 = MgCl2 + N2 =>
2 MgN + 2 Cl2 = 2 MgCl2 + N2
(NH4)6Mo7O24*6H2O + NiNO4*6H2O + (NH4)2S2O8 = (NH4)6NiMo9O32 + (NH4)2SO4 + NH4NO3 + H2O =>
90(NH4)6Mo7O24*6H2O + 70 NiNO4*6H2O + 27(NH4)2S2O8 = 70(NH4)6NiMo9O32 + 54(NH4)2SO4 + 68 NH4NO3 + 956 H2O
PCl3 + KClO3 + H2O = H3PO4 + KCl + HCl =>
3 PCl3 + KClO3 + 9 H2O = 3 H3PO4 + KCl + 9 HCl
Au + H2 = AuH2 =>
Au + H2 = AuH2
Cu + HCl(aq) = CuCl2(aq) + H2(g) =>
Cu + 2 HCl(aq) = CuCl2(aq) + H2(g)
AgNO3(aq) + NaI = AgI(s) + NO3Na(aq) =>
AgNO3(aq) + NaI = AgI(s) + NO3Na(aq)
FeCl3 + O2 = Fe2O3 + Cl =>
4 FeCl3 + 3 O2 = 2 Fe2O3 + 12 Cl
Cl{-} + Ag{+}NO3{-} = AgCl =>
Cl{-} + Ag{+}NO3{-} = AgCl
PCl3 + KClO3 + H2O = H3PO4 + KCl + HCl =>
3 PCl3 + KClO3 + 9 H2O = 3 H3PO4 + KCl + 9 HCl
AlCl3 + Zn(NO3)2 = Al(NO3)3 + ZnCl2 =>
2 AlCl3 + 3 Zn(NO3)2 = 2 Al(NO3)3 + 3 ZnCl2
Mg + Pb3O4 = MgO + Pb =>
4 Mg + Pb3O4 = 4 MgO + 3 Pb
PCl3 + KClO3 + H2O = H3PO4 + KCl + HCl =>
3 PCl3 + KClO3 + 9 H2O = 3 H3PO4 + KCl + 9 HCl
KAg = K + Ag =>
KAg = K + Ag
PCl3 + KClO3 + H2O = H3PO4 + KCl + HCl =>
3 PCl3 + KClO3 + 9 H2O = 3 H3PO4 + KCl + 9 HCl
HF + Ca(NO3)2 = HNO3 + CaF2 =>
2 HF + Ca(NO3)2 = 2 HNO3 + CaF2
Na2Cr2O7 + H2SO4 + FeSO4 = Cr2(SO4)3 + Fe2(SO4)3 + Na2(SO4)3 + H2O =>
Na2Cr2O7 + 7 H2SO4 + 2 FeSO4 = Cr2(SO4)3 + Fe2(SO4)3 + Na2(SO4)3 + 7 H2O
FeCl2 + CaCO3 = FeCO3 + CaCl2 =>
FeCl2 + CaCO3 = FeCO3 + CaCl2
Si5H10 + O2 = SiO2 + H2O =>
2 Si5H10 + 15 O2 = 10 SiO2 + 10 H2O
Me2O3 + H2 = Me + H2O =>
Me2O3 + 3 H2 = 2 Me + 3 H2O
Cu0 + SO4 = CuSO4 =>
Cu0 + SO4 = CuSO4
Zn + Fe(N03)3 = Zn(N03) + Fe =>
3 Zn + Fe(N03)3 = 3 Zn(N03) + Fe
O5 + H6 = OH7 =>
6 O5 + 35 H6 = 30 OH7
NH3 + O(g) = H2O + NO2 =>
2 NH3 + 7 O(g) = 3 H2O + 2 NO2
N2 + CaCl2 = Ca3N2 + Cl =>
N2 + 3 CaCl2 = Ca3N2 + 6 Cl
YCl3 + K = Y + KCl =>
YCl3 + 3 K = Y + 3 KCl
Pb{+2} + K2CrO4{-2} = PbCrO4 + K =>
Pb{+2} + K2CrO4{-2} = PbCrO4 + 2 K
PtSiO4 + Al = Al(SiO4)3 + Pt =>
3 PtSiO4 + Al = Al(SiO4)3 + 3 Pt
S(s) + H2SO4(aq) = SO2(s) + H2O(l) =>
S(s) + 2 H2SO4(aq) = 3 SO2(s) + 2 H2O(l)
CuI2 + Cs = Cu + CsI =>
CuI2 + 2 Cs = Cu + 2 CsI
Fe(OH)3 + NH4Cl = FeCl3 + NH4OH =>
Fe(OH)3 + 3 NH4Cl = FeCl3 + 3 NH4OH
Na2O2 + C12H23ClO = NaCl + C24H46O4 =>
Na2O2 + 2 C12H23ClO = 2 NaCl + C24H46O4
K2SO4 + MgSO4 = K2Mg(SO4)2 =>
K2SO4 + MgSO4 = K2Mg(SO4)2
C(s) + O2(g) = CO2(l) =>
C(s) + O2(g) = CO2(l)
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 |
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/19/25
Equations balanced on 03/21/24
Please let us know how we can improve this web app.