| Equations balanced on the previous day |
2 Cu(NO3)2*H2O + 2 Al(NO3)3*3H2O + 14 NaOH = 2 CuAlO2 + 5 NaN2O3 + 9 NaO2 + 15 H2O
C5H12 + O2 = CO2 + H2O =>
C5H12 + 8 O2 = 5 CO2 + 6 H2O
*2Fe(s) + O2 = *2FeO(s) =>
*2Fe(s) + O2 = *2FeO(s)
HClO4 + Cd = CdClO4H =>
HClO4 + Cd = CdClO4H
Na2B4O7 + H2O = H3BO3 + NaOH =>
Na2B4O7 + 7 H2O = 4 H3BO3 + 2 NaOH
K2O(s) + HBr(aq) = KBr(aq) + H2O(l) =>
K2O(s) + 2 HBr(aq) = 2 KBr(aq) + H2O(l)
O2 + HCl + N2Cl2 = N2Cl4 + H2O =>
O2 + 4 HCl + 2 N2Cl2 = 2 N2Cl4 + 2 H2O
CuCl2 + NaOH = Cu(OH)2 + NaCl =>
CuCl2 + 2 NaOH = Cu(OH)2 + 2 NaCl
Na2SO4 + CuSO4 + H2O = Na2Cu(SO4)2*6H2O =>
Na2SO4 + CuSO4 + 6 H2O = Na2Cu(SO4)2*6H2O
CuO + CH4 = CO + H2O + Cu =>
3 CuO + CH4 = CO + 2 H2O + 3 Cu
Cu(NO3)2 + Na2CO3 = Cu2(CO3)2 + NaNO3 =>
2 Cu(NO3)2 + 2 Na2CO3 = Cu2(CO3)2 + 4 NaNO3
CaCl2 + K4[Fe(CN)6] = Ca(Fe(CN)6) + K2Cl =>
CaCl2 + K4[Fe(CN)6] = Ca(Fe(CN)6) + 2 K2Cl
Cu + HNO3(diluido) = CuNO3 + NO + H2O =>
3 Cu + 4 HNO3(diluido) = 3 CuNO3 + NO + 2 H2O
Ba(OH)2 + VBr4 = BaBr2 + V(OH)4 =>
2 Ba(OH)2 + VBr4 = 2 BaBr2 + V(OH)4
NO2 = NO + O2 =>
2 NO2 = 2 NO + O2
Ni(NO3)2 + NH3 + H2O = NH4(NO3)2 + Ni(OH3)2 =>
17 Ni(NO3)2 + 26 NH3 + 52 H2O = 20 NH4(NO3)2 + 17 Ni(OH3)2
K2CrO4 + Na2S + H2SO4 = K2SO4 + Cr2(SO4)3 + H2O + Na2SO4 =>
8 K2CrO4 + 3 Na2S + 20 H2SO4 = 8 K2SO4 + 4 Cr2(SO4)3 + 20 H2O + 3 Na2SO4
C2H5NH2 + O2 = C + NO + H2O =>
4 C2H5NH2 + 9 O2 = 8 C + 4 NO + 14 H2O
CaHPO4 + NaOH = Na2HPO4 + Ca(OH)2 =>
CaHPO4 + 2 NaOH = Na2HPO4 + Ca(OH)2
Co(H2O)6{+2} + H2O2 + HCO3{-} + NO3{-} = Co(CO3)3{-3} + H2O + HNO3 =>
2 Co(H2O)6{+2} + H2O2 + 6 HCO3{-} + 4 NO3{-} = 2 Co(CO3)3{-3} + 14 H2O + 4 HNO3
Co = Co2 =>
2 Co = Co2
Na2S2O3*5H2O + HCl*51H2O = H2O + NaCl + S + SO2 =>
Na2S2O3*5H2O + 2 HCl*51H2O = 108 H2O + 2 NaCl + S + SO2
NaHS + Cl2 = HCl + NaSCl =>
NaHS + Cl2 = HCl + NaSCl
KMnO4 + H2SO4 + FeSO4 = Fe2(SO4)3 + K2SO4 + MnSO2 + H2O =>
2 KMnO4 + 12 H2SO4 + 18 FeSO4 = 9 Fe2(SO4)3 + K2SO4 + 2 MnSO2 + 12 H2O
Br + BaI2 = Ba + BrI =>
2 Br + BaI2 = Ba + 2 BrI
[Cr(H2O)3(OH)3] + OH = [Cr(H2O)2(OH)4] + H2O =>
[Cr(H2O)3(OH)3] + OH = [Cr(H2O)2(OH)4] + H2O
Ba(s)Cl2(g) = BaCl2(s) =>
Ba(s)Cl2(g) = BaCl2(s)
C + O2 + N2 + H2 = CO(NH2)2 =>
2 C + O2 + 2 N2 + 4 H2 = 2 CO(NH2)2
HNO3 + HI = HINO3 + H =>
HNO3 + HI = HINO3 + H
CH2 + Cl2 = C + HCl =>
CH2 + Cl2 = C + 2 HCl
NCl3 = N2Cl + Cl2 =>
4 NCl3 = 2 N2Cl + 5 Cl2
PbCO3 + SO3 = PbSO4 + CO2 =>
PbCO3 + SO3 = PbSO4 + CO2
NaNO3 + PbO = Na2O + Pb(NO3)2 =>
2 NaNO3 + PbO = Na2O + Pb(NO3)2
H(NO3) + Fe(OH)3 = Fe(NO3)3 + H(OH) =>
3 H(NO3) + Fe(OH)3 = Fe(NO3)3 + 3 H(OH)
CH3CH2COOC2H5 + O2 = CO2 + H2O =>
2 CH3CH2COOC2H5 + 13 O2 = 10 CO2 + 10 H2O
NaClO2 + CH3COOH = CH3COONa + ClO2 + H2 =>
2 NaClO2 + 2 CH3COOH = 2 CH3COONa + 2 ClO2 + H2
Na2O2H2 + C4H4O4 = HOH + C4H2Na2O4 =>
Na2O2H2 + C4H4O4 = 2 HOH + C4H2Na2O4
Na2CO3 + AgNO3 = AgNa2 + CO3NO3 =>
Na2CO3 + AgNO3 = AgNa2 + CO3NO3
K + CO + H2 = KHCO3 + CH4 =>
2 K + 6 CO + 9 H2 = 2 KHCO3 + 4 CH4
NoN3 = No + N2 =>
2 NoN3 = 2 No + 3 N2
Al2S3 + O2 = Al2O3 + S =>
2 Al2S3 + 3 O2 = 2 Al2O3 + 6 S
CH4 + Br2 = C3H2Br4 + HBr =>
3 CH4 + 7 Br2 = C3H2Br4 + 10 HBr
AgNO3 + Mg = Ag + Mg(NO3)2 =>
2 AgNO3 + Mg = 2 Ag + Mg(NO3)2
NaAl7Si11O30(OH)6 + CO2 + H2O = Al2Si2O5(OH)4 + Na{+} + HCO3{-} + H4SiO4 =>
2 NaAl7Si11O30(OH)6 + 2 CO2 + 25 H2O = 7 Al2Si2O5(OH)4 + 2 Na{+} + 2 HCO3{-} + 8 H4SiO4
C3H7OH + O2 = C2O4 + H2O =>
2 C3H7OH + 9 O2 = 3 C2O4 + 8 H2O
C(s) + O2(g) = O2(g)CO2(g) =>
C(s) + 2 O2(g) = O2(g)CO2(g)
KI + Mg(SO4) = K2SO4 + MgI2 =>
2 KI + Mg(SO4) = K2SO4 + MgI2
HCO3 + NaOH = NaHCO3 + H2O2 =>
2 HCO3 + 2 NaOH = 2 NaHCO3 + H2O2
La(NO3)3*6H2O + Cr(NO3)3*9H2O + Co(NO3)2*6H2O + Fe(NO3)3*9H2O + SrCO3 + SrF2 + O2 = La8Sr2Cr5Fe2Co3O30F2 + N2O5 + CO2 + H2O =>
32 La(NO3)3*6H2O + 20 Cr(NO3)3*9H2O + 12 Co(NO3)2*6H2O + 8 Fe(NO3)3*9H2O + 4 SrCO3 + 4 SrF2 + 7 O2 = 4 La8Sr2Cr5Fe2Co3O30F2 + 102 N2O5 + 4 CO2 + 516 H2O
Zn(NO3)2*6H2O + C6H10O5 + Ga(NO3)3*9H2O = ZnGaO + N2 + CO2 + H2O =>
6 Zn(NO3)2*6H2O + 7 C6H10O5 + 6 Ga(NO3)3*9H2O = 6 ZnGaO + 15 N2 + 42 CO2 + 125 H2O
Balance the equation of any chemical reaction
| Equations balanced on the previous day |
Equations balanced on 02/01/25
Equations balanced on 03/03/24
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