Equations balanced on the previous day |
C6H8O7 = C6H6O7 + 2 H
HF(aq) + Na2S(aq) = H2S + NaF =>
2 HF(aq) + Na2S(aq) = H2S + 2 NaF
(NH4)2MoO4 + NaPO4 + HNO3 = (NH4)3P(Mo3O10)4 + H2O + NaNO3 + NH3 =>
48(NH4)2MoO4 + 4 NaPO4 + 3 HNO3 = 4(NH4)3P(Mo3O10)4 + 45 H2O + 4 NaNO3 + 83 NH3
Hg2(NO3)2 + Na2S = Na(NO3) + Hg2S =>
Hg2(NO3)2 + Na2S = 2 Na(NO3) + Hg2S
B2Cl4(g) + O2(g) = B2O3(s) + BCl3(g) =>
6 B2Cl4(g) + 3 O2(g) = 2 B2O3(s) + 8 BCl3(g)
KMnO4 + (CH3)2SO = MnO + K2CO3 + H2O + CO2 + SO2 =>
16 KMnO4 + 5(CH3)2SO = 16 MnO + 8 K2CO3 + 15 H2O + 2 CO2 + 5 SO2
MnI2 + AgNO3 = AgI + Mn(NO3)2 =>
MnI2 + 2 AgNO3 = 2 AgI + Mn(NO3)2
Mg3P2 + HNO3 = NO2 + H2O + Mg3(PO4)2 =>
Mg3P2 + 16 HNO3 = 16 NO2 + 8 H2O + Mg3(PO4)2
F + KCI = CI + KF =>
F + KCI = CI + KF
MnO4 + CH3OH = MnO2 + HCOO + H2O =>
5 MnO4 + 4 CH3OH = 5 MnO2 + 4 HCOO + 6 H2O
Ba(oh)2 + NaCl = BaCl + Na(oh)2 =>
Ba(oh)2 + 2 NaCl = 2 BaCl + Na(oh)2
KBrO3 + KCl + H2SO4 = Cl2 + KBr + K2SO4 + H2O =>
KBrO3 + 6 KCl + 3 H2SO4 = 3 Cl2 + KBr + 3 K2SO4 + 3 H2O
Nitrogendioxide + Water + Oxygen = Nitricacid =>
4 NO2 + 2 H2O + O2 = 4 HNO3
(v)Zn + HNO3 = Zn(NO3)2 + H2O + NO =>
3(v)Zn + 8 HNO3 = 3 Zn(NO3)2 + 4 H2O + 2 NO
CH3CH2OH + CH3OHMnO4{-} + H{+} = CH3COOH + Mn{2+} + H2O =>
3 CH3CH2OH + 4 CH3OHMnO4{-} + 12 H{+} = 5 CH3COOH + 4 Mn{2+} + 13 H2O
KMnO4 + H2SO4 + NH3 = HNO3 + K2SO4 + MnSO4 + H2O =>
8 KMnO4 + 12 H2SO4 + 5 NH3 = 5 HNO3 + 4 K2SO4 + 8 MnSO4 + 17 H2O
C17H33OOH + O2 = CO2 + H2O =>
2 C17H33OOH + 49 O2 = 34 CO2 + 34 H2O
AgNO3 + Na2CO3 = Ag2CO3 + Na(NO3) =>
2 AgNO3 + Na2CO3 = Ag2CO3 + 2 Na(NO3)
F2(g) + H2O(g) = OF2(g) + HF(g) =>
2 F2(g) + H2O(g) = OF2(g) + 2 HF(g)
(CH3CO)2O + C6H5NH2 = CH3COOH + C6H5NHCOCH3 =>
(CH3CO)2O + C6H5NH2 = CH3COOH + C6H5NHCOCH3
MgBr2 + Ca(OH)2 = Mg(OH)2 + CaBr2 =>
MgBr2 + Ca(OH)2 = Mg(OH)2 + CaBr2
S + I{-} = I{2} + S{2-} =>
3 S + 2 I{-} = 2 I{2} + 3 S{2-}
CO2 + BCl3 = B2O3 + CCl4 =>
3 CO2 + 4 BCl3 = 2 B2O3 + 3 CCl4
C6H5OH + H2S + H2O = CH4 + H2SO3 =>
3 C6H5OH + 10 H2S + 27 H2O = 18 CH4 + 10 H2SO3
K2SO4(aq) + BaBr2(aq) = BaSO4(aq) + KBr(aq) =>
K2SO4(aq) + BaBr2(aq) = BaSO4(aq) + 2 KBr(aq)
NaNO3 + AgCH3COO = AgNO3 + NaCH3COO =>
NaNO3 + AgCH3COO = AgNO3 + NaCH3COO
Al + CoO = Al2O3 + CoAl3 =>
11 Al + 3 CoO = Al2O3 + 3 CoAl3
CH3(CH2)6COONa + CuSO4 = (CH3(CH2)6COO)2Cu + Na2SO4 =>
2 CH3(CH2)6COONa + CuSO4 = (CH3(CH2)6COO)2Cu + Na2SO4
C7H16O2 + O2 = CO2 + H2O =>
C7H16O2 + 10 O2 = 7 CO2 + 8 H2O
HBr + Pb(ClO4)2 = HClO4 + PbBr2 =>
2 HBr + Pb(ClO4)2 = 2 HClO4 + PbBr2
Ba + (IO3)2 = Ba(IO3)2 =>
Ba + (IO3)2 = Ba(IO3)2
NaHSO3 + HI = NaH + HSO3I =>
NaHSO3 + HI = NaH + HSO3I
C4H8O2 + O2 = H8O4 + C4 =>
C4H8O2 + O2 = H8O4 + C4
FeO2 + Na2SO4 = FeSO4 + NaO =>
FeO2 + Na2SO4 = FeSO4 + 2 NaO
BaHO(aq) + HCl(aq) = BaCl(s) + H2O(l) =>
BaHO(aq) + HCl(aq) = BaCl(s) + H2O(l)
(CH3COO)2Mg + HCl = (CH3COO)2MgHCl =>
(CH3COO)2Mg + HCl = (CH3COO)2MgHCl
SiI3 + Mg = Si + MgI2 =>
2 SiI3 + 3 Mg = 2 Si + 3 MgI2
In2O3 + C + Cl2 = InCl3 + CO2 =>
2 In2O3 + 3 C + 6 Cl2 = 4 InCl3 + 3 CO2
TiI3 + Hg2(C2H3O2)2 = Ti(C2H3O2)3 + Hg2I2 =>
2 TiI3 + 3 Hg2(C2H3O2)2 = 2 Ti(C2H3O2)3 + 3 Hg2I2
Fe(III) + OH = Fe(III)(OH)3 =>
Fe(III) + 3 OH = Fe(III)(OH)3
F2 + InBr3 = InF3 + Br2 =>
3 F2 + 2 InBr3 = 2 InF3 + 3 Br2
Cl2(g) + H2(g) = HCl(g) =>
Cl2(g) + H2(g) = 2 HCl(g)
Al + (H)2(SO)4 + KOH + H2O = KAl(SO)4*12H2O + H2 =>
2 Al + 2(H)2(SO)4 + 2 KOH + 22 H2O = 2 KAl(SO)4*12H2O + H2
Na3AsO4 + NaI + H2SO4 = Na3AsO3 + H2O + I2 + Na2SO4 =>
Na3AsO4 + 2 NaI + H2SO4 = Na3AsO3 + H2O + I2 + Na2SO4
CaF2 + H2SO4 + SiO2 = CaSO4 + SiF4 + H2O =>
2 CaF2 + 2 H2SO4 + SiO2 = 2 CaSO4 + SiF4 + 2 H2O
AgNO3 + KCl2 = KNO3 + AgCl2 =>
AgNO3 + KCl2 = KNO3 + AgCl2
Al + Ba(OH)2 = Ba + Al(OH)3 =>
2 Al + 3 Ba(OH)2 = 3 Ba + 2 Al(OH)3
HIO + NO2 = IO + HNO2 =>
HIO + NO2 = IO + HNO2
Ba(OH)2 + HOCN = Ba(OCN)2 + H2O =>
Ba(OH)2 + 2 HOCN = Ba(OCN)2 + 2 H2O
(C15H16O2) + COCl2 + NaOH = (OC6H4C(CH3)2(C6H4OCO))50 + NaCl + H2O =>
50(C15H16O2) + 50 COCl2 + 100 NaOH = (OC6H4C(CH3)2(C6H4OCO))50 + 100 NaCl + 100 H2O
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 02/01/25
Equations balanced on 03/03/24
Please let us know how we can improve this web app.