| Equations balanced on the previous day |
KCl + Cu = KCu + Cl
CH3COOH + NaHCO3 = CH3COHNa + H2O + CO2 =>
11 CH3COOH + 8 NaHCO3 = 8 CH3COHNa + 10 H2O + 14 CO2
LiBr + I2 = LiI + Br =>
2 LiBr + I2 = 2 LiI + 2 Br
MgN2 = Mg + N =>
MgN2 = Mg + 2 N
H2S(g) + O2 = SO2 + H2O =>
2 H2S(g) + 3 O2 = 2 SO2 + 2 H2O
(NH4)HSO3 + NaOH = H2O + NH3 + Na2SO3 =>
(NH4)HSO3 + 2 NaOH = 2 H2O + NH3 + Na2SO3
H{2} + N{2} = N + H{3} =>
2 H{2} + N{2} = N + 2 H{3}
PBr5 + NH3 = HBr + N2 + PH3 =>
3 PBr5 + 8 NH3 = 15 HBr + 4 N2 + 3 PH3
C2O4Na + K(MnO4) + H2SO4 = CO2 + K2(SO4) + Na2(SO4) + Mn(SO4) + H2O =>
10 C2O4Na + 2 K(MnO4) + 8 H2SO4 = 20 CO2 + K2(SO4) + 5 Na2(SO4) + 2 Mn(SO4) + 8 H2O
AgNO3 + MgCl2 = AgCl + Mg(NO3)2 =>
2 AgNO3 + MgCl2 = 2 AgCl + Mg(NO3)2
CuSO4 + Na2CO3 = NaSO4 + Cu + CO3 =>
2 CuSO4 + Na2CO3 = 2 NaSO4 + 2 Cu + CO3
C6H5COOH + NaAOH = C6H5COONaA + H2O =>
C6H5COOH + NaAOH = C6H5COONaA + H2O
C5H11OH + CrO3 = Cr2O3 + C5H10OH + H2O =>
6 C5H11OH + 2 CrO3 = Cr2O3 + 6 C5H10OH + 3 H2O
FeCl + NH4P = FeP + NH4Cl =>
FeCl + NH4P = FeP + NH4Cl
Cu2[Fe(CN)6] + NH4OH = Cu(NH3)4{2+} + Fe(CN)6{4-} + H2O =>
Cu2[Fe(CN)6] + 8 NH4OH = 2 Cu(NH3)4{2+} + Fe(CN)6{4-} + 8 H2O
V3(PO4)5 + Pb(C2O4)2 = Pb3(PO4)4 + V2(C2O4)5 =>
4 V3(PO4)5 + 15 Pb(C2O4)2 = 5 Pb3(PO4)4 + 6 V2(C2O4)5
CuCl + Na2S2O3 = Na[Cu(S2O3)] + NaCl =>
CuCl + Na2S2O3 = Na[Cu(S2O3)] + NaCl
Pb(C2H3O2)2 + H2O + CO2 = PbCO2 + HC2H3O2 =>
4 Pb(C2H3O2)2 + 2 H2O + 2 CO2 = 4 PbCO2 + 7 HC2H3O2
K2CrO7 + Na2S2O3 + H2SO4 = Cr2(SO4)3 + K2SO4 + Na2SO4 + H2O =>
8 K2CrO7 + 9 Na2S2O3 + 11 H2SO4 = 4 Cr2(SO4)3 + 8 K2SO4 + 9 Na2SO4 + 11 H2O
Na2 + CO3 + AlCl2 = NaCl + Al2(CO3)3 =>
2 Na2 + 3 CO3 + 2 AlCl2 = 4 NaCl + Al2(CO3)3
C2H6O + Na = NaC2 + H6O =>
C2H6O + Na = NaC2 + H6O
NH3 + CH4 + O2 = NH2CH2COOH + H2O =>
2 NH3 + 4 CH4 + 5 O2 = 2 NH2CH2COOH + 6 H2O
ammoniumnitrate + NaOH = sodiumnitrate + NH3 + water =>
NH4NO3 + NaOH = NaNO3 + NH3 + H2O
Al(OH)2 + H2SO4 = Al(SO4) + H2O =>
Al(OH)2 + H2SO4 = Al(SO4) + 2 H2O
CaO + CO2 + H2 = H2O + Ca2C2O4 =>
2 CaO + 2 CO2 + 2 H2 = 2 H2O + Ca2C2O4
CH2O + CuSO4 + NaOH = CHOO + Cu2O + Na2SO4 + H2O =>
2 CH2O + 6 CuSO4 + 12 NaOH = 2 CHOO + 3 Cu2O + 6 Na2SO4 + 7 H2O
H2SO4 + NH4OH = NH4HSO3 + OH =>
H2SO4 + NH4OH = NH4HSO3 + 2 OH
Al2O3 + Ca(OH)2 = Al2(CaO2)3 + H2O =>
Al2O3 + 3 Ca(OH)2 = Al2(CaO2)3 + 3 H2O
SrCl2 + K2CO3 = SrCO3 + Cl2K2 =>
SrCl2 + K2CO3 = SrCO3 + Cl2K2
C5H8NO4Na + NaOH = CO2 + H2O + Na + N =>
C5H8NO4Na + 20 NaOH = 5 CO2 + 14 H2O + 21 Na + N
Na2O + CaO + B2O3 + GeO2 = Na2OCaOB2O3GeO2 =>
Na2O + CaO + B2O3 + GeO2 = Na2OCaOB2O3GeO2
FeS + Br2 + OH{-} = Fe(OH)3 + SO42{-} + H2O + Br{-} =>
FeS + 43 Br2 + 87 OH{-} = Fe(OH)3 + SO42{-} + 42 H2O + 86 Br{-}
Pb(s) + HCl(l) = PbCl2 + H =>
Pb(s) + 2 HCl(l) = PbCl2 + 2 H
Zn(SO4)2 + NaOH = Zn(OH)2 + NaSO4 =>
Zn(SO4)2 + 2 NaOH = Zn(OH)2 + 2 NaSO4
CH2O = COH2 =>
CH2O = COH2
CuCl2 + HCl = [CuCl4]{2-} + H{+} =>
CuCl2 + 2 HCl = [CuCl4]{2-} + 2 H{+}
Al2O3 + HF = Al2F + HO3 =>
Al2O3 + HF = Al2F + HO3
FeO + HNO3 = H2O + NO + Fe(NO3)3 =>
3 FeO + 10 HNO3 = 5 H2O + NO + 3 Fe(NO3)3
NaOH + P4O6 = Na2PHO3 + H2O =>
8 NaOH + P4O6 = 4 Na2PHO3 + 2 H2O
KOH + Cu = CuO2 + H2 + K =>
2 KOH + Cu = CuO2 + H2 + 2 K
NO3 + C6H12O6 = CO2 + H2O + NO =>
6 NO3 + C6H12O6 = 6 CO2 + 6 H2O + 6 NO
Cu2O2(s) + C(s) = Cu(s) + CO(g) =>
Cu2O2(s) + 2 C(s) = 2 Cu(s) + 2 CO(g)
carbon + aluminumoxide = carbonmonoxide + aluminum =>
3 C + Al2O3 = 3 CO + 2 Al
Fe2{+} + Cl2{-} + H2O = FeO4 + H2 + HCl =>
Fe2{+} + Cl2{-} + 8 H2O = 2 FeO4 + 7 H2 + 2 HCl
RbF(aq) + FeBr3(aq) = RbBr(s) + FeF3(aq) =>
3 RbF(aq) + FeBr3(aq) = 3 RbBr(s) + FeF3(aq)
Ca + C2 = CaC2(s) =>
Ca + C2 = CaC2(s)
Ar2O3 + NaOH + H2O = Na3[Ar(OH)6] =>
Ar2O3 + 6 NaOH + 3 H2O = 2 Na3[Ar(OH)6]
NaNO{3} + H{2}SO{4} = Na{2}SO{4} + HNO{3} =>
NaNO{3} + H{2}SO{4} = Na{2}SO{4} + HNO{3}
K2S + Zn(PO4) = K2PO4 + ZnS =>
K2S + Zn(PO4) = K2PO4 + ZnS
NH3*H2O + O2 + [Cu(NH3)2]OH = [Cu(NH3)4](OH)2 + H2O =>
8 NH3*H2O + O2 + 4[Cu(NH3)2]OH = 4[Cu(NH3)4](OH)2 + 6 H2O
Balance the equation of any chemical reaction
| Equations balanced on the previous day |
Equations balanced on 12/19/24
Equations balanced on 01/18/24
Please let us know how we can improve this web app.
