| Equations balanced on the previous day |
5 NaHCO3 + C2OOH = 7 CO2 + 5 Na + 3 H2O
Pb2 + H3PO4 = Pb3PO4 + H2 =>
3 Pb2 + 2 H3PO4 = 2 Pb3PO4 + 3 H2
ClNa + H2SO4 = Na2SO4 + HCl =>
2 ClNa + H2SO4 = Na2SO4 + 2 HCl
I2 + S2O3{2-} = S4O6{2-} + I{-} =>
I2 + 2 S2O3{2-} = S4O6{2-} + 2 I{-}
C6H6MgBr + C10H13O = C16H19OMgBr =>
C6H6MgBr + C10H13O = C16H19OMgBr
CrOH2 = CrO + H2 =>
CrOH2 = CrO + H2
ClO3 + K2O = KClO3 + O2 =>
4 ClO3 + 2 K2O = 4 KClO3 + O2
CH2COOH + CH3CH2OH = CH3COOCH2CH3 + H2O =>
4 CH2COOH + 6 CH3CH2OH = 5 CH3COOCH2CH3 + 4 H2O
Ba + HC2H3O2 = Ba(C2H3O2)2 + H =>
Ba + 2 HC2H3O2 = Ba(C2H3O2)2 + 2 H
Al(s) + H2SO4(aq) = H2(g) + Al2(SO4)3 =>
2 Al(s) + 3 H2SO4(aq) = 3 H2(g) + Al2(SO4)3
H2SO4 + Cu3OH = Cu3SO4 + H2OH =>
H2SO4 + Cu3OH = Cu3SO4 + H2OH
H2O + NaCl = NaClO3 + H2 =>
3 H2O + NaCl = NaClO3 + 3 H2
SrCl2 + Na2Co3 = SrCo3 + NaCl =>
SrCl2 + Na2Co3 = SrCo3 + 2 NaCl
Na3(PO4) = Na3PO4 =>
Na3(PO4) = Na3PO4
CH3CHOHCH3 + K2CrO7 + H2SO4 = CH3CHO + Cr2(SO4)3 + K2SO4 + H2O =>
6 CH3CHOHCH3 + 2 K2CrO7 + 5 H2SO4 = 9 CH3CHO + Cr2(SO4)3 + 2 K2SO4 + 11 H2O
Na2CrO4 + HCl + FeSO4 = CrCl3 + NaCl + Fe2(SO4)3 + FeCl3 + H2O =>
Na2CrO4 + 8 HCl + 3 FeSO4 = CrCl3 + 2 NaCl + Fe2(SO4)3 + FeCl3 + 4 H2O
S + HNO3 = NO3S + H2 =>
2 S + 2 HNO3 = 2 NO3S + H2
FeCr2O4 + Na2CO3 + KNO3 = Fe2O3 + Na2CrO4 + KNO2 + CO2 =>
2 FeCr2O4 + 4 Na2CO3 + 7 KNO3 = Fe2O3 + 4 Na2CrO4 + 7 KNO2 + 4 CO2
C21H16O5 + H2O2 = CO2 + H2O =>
C21H16O5 + 45 H2O2 = 21 CO2 + 53 H2O
AlBr3 + Pb = PbBr4 + Al3 =>
12 AlBr3 + 9 Pb = 9 PbBr4 + 4 Al3
MnO2 + KI + H2O = MnI2 + I2 + KOH =>
MnO2 + 4 KI + 2 H2O = MnI2 + I2 + 4 KOH
(NH4)2CO3 + CrBr2 = (NH4)2Br2 + CrCO3 =>
(NH4)2CO3 + CrBr2 = (NH4)2Br2 + CrCO3
NaOH + H3AsO4 = Na3AsO4 + H2O =>
3 NaOH + H3AsO4 = Na3AsO4 + 3 H2O
Pb(NO3)2(aq) + NH3(aq) = NH3(NO3) + Pb =>
Pb(NO3)2(aq) + 2 NH3(aq) = 2 NH3(NO3) + Pb
NaCl + KMnO4 + H2SO4 = MnSO4 + K2SO4 + Na2SO4 + Cl2 + H2O =>
10 NaCl + 2 KMnO4 + 8 H2SO4 = 2 MnSO4 + K2SO4 + 5 Na2SO4 + 5 Cl2 + 8 H2O
O2 + S = O2S =>
O2 + S = O2S
F + O2 = FO2 =>
F + O2 = FO2
NaHC2O4 + Cl2 + NaOH + Ba(NO3)2 = NaCl + NaNO3 + H2O + BaCO3 =>
NaHC2O4 + Cl2 + 5 NaOH + 2 Ba(NO3)2 = 2 NaCl + 4 NaNO3 + 3 H2O + 2 BaCO3
CH3COOH + NH3 = CH3OH + C10H16O4N3 + CO2 =>
57 CH3COOH + 12 NH3 = 50 CH3OH + 4 C10H16O4N3 + 24 CO2
PPH3 + RuCl3(H2O)2 = Ru(PPH3)3Cl2 + H2O + HCl + PPH3O =>
7 PPH3 + 2 RuCl3(H2O)2 = 2 Ru(PPH3)3Cl2 + 3 H2O + 2 HCl + PPH3O
KHSO4 + Ba(OH)2 = K2SO4 + BaSO4 + H2O =>
2 KHSO4 + Ba(OH)2 = K2SO4 + BaSO4 + 2 H2O
Al2O3 + H2O(l) = Al(OH)3 =>
Al2O3 + 3 H2O(l) = 2 Al(OH)3
C6H5NO3 + (NH4)2S = C6H5NH2 + NH3 + S + H2O =>
C6H5NO3 + 4(NH4)2S = C6H5NH2 + 8 NH3 + 4 S + 3 H2O
K2SO4 + AiBr3 = KBr + Ai2(SO4)3 =>
3 K2SO4 + 2 AiBr3 = 6 KBr + Ai2(SO4)3
Ba(OH)2 + HCl = H2O + BaCl2 =>
Ba(OH)2 + 2 HCl = 2 H2O + BaCl2
N2F5 = N + F =>
N2F5 = 2 N + 5 F
Hf + C = HfC05 =>
Hf + 5 C = HfC05
L + Br2 = LBr =>
2 L + Br2 = 2 LBr
SnCl2 + Na2WO4 + HCl = W5O14 + Na2SnCl6 + NaCl + H2O =>
SnCl2 + 5 Na2WO4 + 12 HCl = W5O14 + Na2SnCl6 + 8 NaCl + 6 H2O
C3H8O(g) + O2(g) = CO2 + H2O(g) =>
2 C3H8O(g) + 9 O2(g) = 6 CO2 + 8 H2O(g)
CH3COOH + NaHCO3 = CH3COONa + H2O + CO2 =>
CH3COOH + NaHCO3 = CH3COONa + H2O + CO2
HCl + Mg2O6 = MgCl2 + H2O + Cl2 =>
12 HCl + Mg2O6 = 2 MgCl2 + 6 H2O + 4 Cl2
CuCl + SrBr2 = SrCl2 + CuBr =>
2 CuCl + SrBr2 = SrCl2 + 2 CuBr
Na2SO3 + Mg = MgSO3 + Na =>
Na2SO3 + Mg = MgSO3 + 2 Na
Zn(S) + HCl(ac) = ZnCl2(S) + H2(g) =>
Zn(S) + 2 HCl(ac) = ZnCl2(S) + H2(g)
H2 + CO3 = HO + CH =>
2 H2 + CO3 = 3 HO + CH
Si2H + O2 = SiO2 + H2O3 =>
4 Si2H + 11 O2 = 8 SiO2 + 2 H2O3
Mg(NO3)2*6H2O + Fe(NO3)3*9H2O + KOH + K2CO3 = Mg6Fe2(OH)16CO3 + KNO3 + H2O =>
6 Mg(NO3)2*6H2O + 2 Fe(NO3)3*9H2O + 16 KOH + K2CO3 = Mg6Fe2(OH)16CO3 + 18 KNO3 + 54 H2O
NH4Cl + Ba(OH)2 = NH3 + BaCl2 + HOH =>
2 NH4Cl + Ba(OH)2 = 2 NH3 + BaCl2 + 2 HOH
B + FeO = B2O3 + Fe =>
2 B + 3 FeO = B2O3 + 3 Fe
Balance the equation of any chemical reaction
| Equations balanced on the previous day |
Equations balanced on 12/19/24
Equations balanced on 01/18/24
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