Equations balanced on the previous day |
HCl + (NH4)2CO3 = NH4Cl + (NH4)HCO3
CH4 + Cl2 = CCl4 + HCl =>
CH4 + 4 Cl2 = CCl4 + 4 HCl
NH3 + H2O + Ca(NO3)2 + (NH4)2HPO4 = Ca10(PO4)6(OH)2 + NH4NO3 =>
8 NH3 + 2 H2O + 10 Ca(NO3)2 + 6(NH4)2HPO4 = Ca10(PO4)6(OH)2 + 20 NH4NO3
Ba(NO2)2 + H2O = Ba(OH)2 + HNO2 =>
Ba(NO2)2 + 2 H2O = Ba(OH)2 + 2 HNO2
OC10H20 + O2 = H2O + CO2 =>
2 OC10H20 + 29 O2 = 20 H2O + 20 CO2
H2NCH2COOH + O2 = H2O + CO2 + N2 =>
4 H2NCH2COOH + 9 O2 = 10 H2O + 8 CO2 + 2 N2
HMnO4 + HNO2 = Mn(NO3)2 + HNO3 + H2 =>
2 HMnO4 + 8 HNO2 = 2 Mn(NO3)2 + 4 HNO3 + 3 H2
Sb2O3 + Cl2 = SbCl5 + O2 =>
2 Sb2O3 + 10 Cl2 = 4 SbCl5 + 3 O2
MgF2 + I2 = Mg + I2F2 =>
MgF2 + I2 = Mg + I2F2
Ca + Zn(NO3)2 = Zn + Ca(NO3)2(aq) =>
Ca + Zn(NO3)2 = Zn + Ca(NO3)2(aq)
H2O2 = H2O + O2 =>
2 H2O2 = 2 H2O + O2
Mn3Br2 = Mn + Br2 =>
Mn3Br2 = 3 Mn + Br2
HPO4 + Cu(OH)2 = H(OH)2 + CuPO4 =>
HPO4 + Cu(OH)2 = H(OH)2 + CuPO4
C2H6O + H2O = H3O + C2H5O =>
C2H6O + H2O = H3O + C2H5O
H2SO4 + KMnO4 + H2S = K2SO4 + MnSO4 + H2O =>
7 H2SO4 + 8 KMnO4 + 5 H2S = 4 K2SO4 + 8 MnSO4 + 12 H2O
C6H6CHCH3CH3 + KMnO4 + H2SO4 = C6H6CH2COOH + K2SO4 + MnSO4 + H2O =>
80 C6H6CHCH3CH3 + 118 KMnO4 + 177 H2SO4 = 90 C6H6CH2COOH + 59 K2SO4 + 118 MnSO4 + 292 H2O
ZnCl2 + H2O2 = Zn + HCl + O2 =>
ZnCl2 + H2O2 = Zn + 2 HCl + O2
Mg + HNO3(aq) = Mg(NO3)2 + NH3 + H2O =>
4 Mg + 9 HNO3(aq) = 4 Mg(NO3)2 + NH3 + 3 H2O
K2CO3 + K(OH)2 = K2OH + K(CO3)2 =>
2 K2CO3 + K(OH)2 = 2 K2OH + K(CO3)2
CrCl3 + AgNO3 = AgCl + Cr(NO3)3 =>
CrCl3 + 3 AgNO3 = 3 AgCl + Cr(NO3)3
C2H6O(aq) + CH3COOH(aq) = CH3COOCH2CH3(aq) + H2O(l) =>
C2H6O(aq) + CH3COOH(aq) = CH3COOCH2CH3(aq) + H2O(l)
C6H8O7 + NH4OH = C6H5O7(NH4)3 + H2O =>
C6H8O7 + 3 NH4OH = C6H5O7(NH4)3 + 3 H2O
C4H10 + Cl2 + O2 = CO2CCl4 + H2O =>
2 C4H10 + 8 Cl2 + 9 O2 = 4 CO2CCl4 + 10 H2O
[Cr(OH2)6]Cl3 = [Cr(OH2)5Cl]Cl2*H2O =>
[Cr(OH2)6]Cl3 = [Cr(OH2)5Cl]Cl2*H2O
Na3N + H2 = NaH + NH3 =>
Na3N + 3 H2 = 3 NaH + NH3
Cl2 + NaOH = NaOCl + NaCl + H2O =>
Cl2 + 2 NaOH = NaOCl + NaCl + H2O
C8H18O3(l) + O2(g) = H2O(g) + CO2(g) =>
C8H18O3(l) + 11 O2(g) = 9 H2O(g) + 8 CO2(g)
H3PO4 + (NH4)OH = (NH4)2HPO4 + H2O =>
H3PO4 + 2(NH4)OH = (NH4)2HPO4 + 2 H2O
NaOH + MgF2 = Mg(OH)2 + NaF =>
2 NaOH + MgF2 = Mg(OH)2 + 2 NaF
BaCl2*2H2O + AgNO3 = H2O + Ba(NO3)2 + AgCl =>
BaCl2*2H2O + 2 AgNO3 = 2 H2O + Ba(NO3)2 + 2 AgCl
Fe(OH)3(s) + NH4Cl(aq) + NaOCl = NaClO4 + Fe2O3 + NH4 + HCl =>
2 Fe(OH)3(s) + 6 NH4Cl(aq) + NaOCl = NaClO4 + Fe2O3 + 6 NH4 + 6 HCl
U(OH)6 + Cr(OH)2 + H2SO4 = UCr(SO4)4 + H2O =>
U(OH)6 + Cr(OH)2 + 4 H2SO4 = UCr(SO4)4 + 8 H2O
Fe{2+} + MnO4{-} + H{+} = Fe{+3} + Mn{2+} + H2O =>
5 Fe{2+} + MnO4{-} + 8 H{+} = 5 Fe{+3} + Mn{2+} + 4 H2O
CH3CH2OH + KMnO4 + HCl = CH3COOH + MnCl3 + KCl + H2O =>
CH3CH2OH + KMnO4 + 4 HCl = CH3COOH + MnCl3 + KCl + 3 H2O
K2C2O4 + H2C2O4*2H2O + K2Cr2O7 = K3[Cr(C2O4)3]*3H2O + H2O + CO2 =>
2 K2C2O4 + 7 H2C2O4*2H2O + K2Cr2O7 = 2 K3[Cr(C2O4)3]*3H2O + 15 H2O + 6 CO2
Y(NO3)2 + GaPO4 = Y3(PO4)2 + Ga(NO3)3 =>
3 Y(NO3)2 + 2 GaPO4 = Y3(PO4)2 + 2 Ga(NO3)3
PbO2 + HF = PbF4 + H2O =>
PbO2 + 4 HF = PbF4 + 2 H2O
FeNO + BaCl = FeCl + BaNO =>
FeNO + BaCl = FeCl + BaNO
C8H18 + O2 = C24 + H2O =>
6 C8H18 + 27 O2 = 2 C24 + 54 H2O
KCl + H2O = HCl + KOH =>
KCl + H2O = HCl + KOH
C4H6O6 + NaHCO3 = NaC4H5O6 + H2O + CO2 =>
C4H6O6 + NaHCO3 = NaC4H5O6 + H2O + CO2
Fe(OH)2 + Cu = CuO + Fe3O4 + H2 =>
3 Fe(OH)2 + 2 Cu = 2 CuO + Fe3O4 + 3 H2
MgO + NH4Cl = MgCl + NH4O =>
MgO + NH4Cl = MgCl + NH4O
C6H12O6 + NH3 = C6H10NO3 + H2O + CO2 =>
25 C6H12O6 + 24 NH3 = 24 C6H10NO3 + 66 H2O + 6 CO2
Al + Cd(CH2COO)2 = Al(CH2COO)2 + Cd =>
Al + Cd(CH2COO)2 = Al(CH2COO)2 + Cd
C2H2O4 + Na = Na2C2O4 + H2 =>
C2H2O4 + 2 Na = Na2C2O4 + H2
NaPb + CH3CH2Cl = (CH3CH2)2Pb + Pb + NaCl =>
2 NaPb + 2 CH3CH2Cl = (CH3CH2)2Pb + Pb + 2 NaCl
Magnesiumoxide + carbon = magnesium + carbondioxide =>
2 MgO + C = 2 Mg + CO2
Li3PO4(aq) + CuNO3(aq) = Cu3(PO4)2(s) + Li2NO3(aq) =>
2 Li3PO4(aq) + 3 CuNO3(aq) = Cu3(PO4)2(s) + 3 Li2NO3(aq)
HCl(aq) = H + Cl =>
HCl(aq) = H + Cl
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 02/02/25
Equations balanced on 03/04/24
Please let us know how we can improve this web app.