Equations balanced on the previous day | Equations balanced on the next day |
2 UH3 + 9 NaClO = 5 NaCl + 2 UO2Cl2 + H2O + 4 NaOH
C2H4Br2 + Zn = C4H8 + ZnBr2 =>
2 C2H4Br2 + 2 Zn = C4H8 + 2 ZnBr2
(NH2)2CO + KBrO3 + NaOH = CO2 + KBr + NaNO3 + H2O =>
3(NH2)2CO + 8 KBrO3 + 6 NaOH = 3 CO2 + 8 KBr + 6 NaNO3 + 9 H2O
Cu + HNO3 + H2O = [Cu(OH)6](NO3)2 + NO =>
3 Cu + 14 HNO3 + 2 H2O = 3[Cu(OH)6](NO3)2 + 8 NO
Al2(SO4)3(aq) + Pb(NO3)2(aq) = Al(NO3)3 + PbSO4 =>
Al2(SO4)3(aq) + 3 Pb(NO3)2(aq) = 2 Al(NO3)3 + 3 PbSO4
NaCl + NH4HCO3 = NH4Cl + NaHCO3 =>
NaCl + NH4HCO3 = NH4Cl + NaHCO3
Na2CO3 + NH4NO3 = Na2NO3 + NH4(CO3) =>
Na2CO3 + NH4NO3 = Na2NO3 + NH4(CO3)
SO3{-2} + MnO4{-} + H{+} = SO4{-2} + Mn2{+} + H2O =>
13 SO3{-2} + 4 MnO4{-} + 6 H{+} = 13 SO4{-2} + 2 Mn2{+} + 3 H2O
NaS + H2O = NaO + H2S =>
NaS + H2O = NaO + H2S
AlCl3 + NaOH = Na3Cl3 + Al(OH)3 =>
AlCl3 + 3 NaOH = Na3Cl3 + Al(OH)3
Li2CO3 + C4H6CaO4 = C2H3LiO2 + CCaO3 =>
Li2CO3 + C4H6CaO4 = 2 C2H3LiO2 + CCaO3
Na2B4O7 + HF + NaF = H2O + NaBF4 =>
Na2B4O7 + 14 HF + 2 NaF = 7 H2O + 4 NaBF4
CuCI2 + Na3PO4 = CuPO4 + Na3CI2 =>
CuCI2 + Na3PO4 = CuPO4 + Na3CI2
Na(NO3)(aq) + Ca(s) = Na(s) + Ca(NO3)2(aq) =>
2 Na(NO3)(aq) + Ca(s) = 2 Na(s) + Ca(NO3)2(aq)
MnCO3 + HCl = MnCl2 + HOH + CO2 =>
MnCO3 + 2 HCl = MnCl2 + HOH + CO2
Cu + Al(OH)3 = Cu(OH)2 + Al =>
3 Cu + 2 Al(OH)3 = 3 Cu(OH)2 + 2 Al
Na2H2C2O6 = Na2CO3 + H2O + CO2 =>
Na2H2C2O6 = Na2CO3 + H2O + CO2
Si4H10 + O2 = SiO2 + H2O =>
2 Si4H10 + 13 O2 = 8 SiO2 + 10 H2O
C5H5 + Fe = Fe(C5H5)2 =>
2 C5H5 + Fe = Fe(C5H5)2
OH{-} + ClO{-} + CrO2{-} = Cl{-} + CrO4{2-} + H2O =>
2 OH{-} + 3 ClO{-} + 2 CrO2{-} = 3 Cl{-} + 2 CrO4{2-} + H2O
N(g) + O2(g) + H2O = HNO3(aq) =>
4 N(g) + 5 O2(g) + 2 H2O = 4 HNO3(aq)
PbSO4 + Na2CO3 = Pb + Na2SO4 + CO3 =>
PbSO4 + Na2CO3 = Pb + Na2SO4 + CO3
K4Fe(CN)6 + Zn(NO3)2 = KNO3 + Zn4(Fe(CN)6)2 =>
2 K4Fe(CN)6 + 4 Zn(NO3)2 = 8 KNO3 + Zn4(Fe(CN)6)2
Pb(CH3COO)2 + HNO3 = H(CH3COO) + Pb(NO3)2 =>
Pb(CH3COO)2 + 2 HNO3 = 2 H(CH3COO) + Pb(NO3)2
H3AsO3 + Ni(OH)2 = Ni3(AsO3)2 + H2O =>
2 H3AsO3 + 3 Ni(OH)2 = Ni3(AsO3)2 + 6 H2O
CH3COOH + Na2CO3 = CH3COONa + H2O + CO2 =>
2 CH3COOH + Na2CO3 = 2 CH3COONa + H2O + CO2
H7CrO10 + Na2SO3 + H2SO4 = Cr2(SO4)3 + Na2SO4 + H2O =>
2 H7CrO10 + 10 Na2SO3 + 3 H2SO4 = Cr2(SO4)3 + 10 Na2SO4 + 10 H2O
Ba(NO3)2 + H2SO4 = BaSO4 + HNO3 =>
Ba(NO3)2 + H2SO4 = BaSO4 + 2 HNO3
Fe2(SO4)3 + KCN = K3Fe(CN)6 + K2SO4 =>
Fe2(SO4)3 + 12 KCN = 2 K3Fe(CN)6 + 3 K2SO4
TiO2 + BaO = BaTiO3 =>
TiO2 + BaO = BaTiO3
C5H5 + Fe = Fe(C5H5)2 =>
2 C5H5 + Fe = Fe(C5H5)2
NaNo3 + BaCl2 = NaCl + Ba(No3)2 =>
2 NaNo3 + BaCl2 = 2 NaCl + Ba(No3)2
Li + Fe2(CO3)3 = Fe + Li2CO3 =>
6 Li + Fe2(CO3)3 = 2 Fe + 3 Li2CO3
Ni2(OH)3 + HSO2 = Ni2(SO2)3 + H2O =>
Ni2(OH)3 + 3 HSO2 = Ni2(SO2)3 + 3 H2O
TiO2 + BaO = BaTiO3 =>
TiO2 + BaO = BaTiO3
Na2CO3 + AgNO2 = NaNO2 + Ag2CO3 =>
Na2CO3 + 2 AgNO2 = 2 NaNO2 + Ag2CO3
phosphoricacid + calciumhydroxide = Ca3(PO4)2 + water =>
2 H3PO4 + 3 Ca(OH)2 = Ca3(PO4)2 + 6 H2O
Hg2O + Mg3(PO4)2 = (Hg2)3(PO4)2 + MgO =>
3 Hg2O + Mg3(PO4)2 = (Hg2)3(PO4)2 + 3 MgO
Pb(NO3)2 + NH4 + OH = Pb(OH)2 + HNO3 =>
3 Pb(NO3)2 + NH4 + 9 OH = 3 Pb(OH)2 + 7 HNO3
Nb2O5 + HF + NH4OH = NH4F + Nb2O5*50H2O =>
Nb2O5 + 50 HF + 50 NH4OH = 50 NH4F + Nb2O5*50H2O
C4H8 + H2SO4 = C4H8SO3 + H2O =>
C4H8 + H2SO4 = C4H8SO3 + H2O
H2SO4 + Ca[OH]2 = CaSO4 + H2O =>
H2SO4 + Ca[OH]2 = CaSO4 + 2 H2O
CuSO4*5H2O + KBr + Na2SO3 = CuBr + Na2SO4 + H2SO4 + K2SO4 + H2O =>
2 CuSO4*5H2O + 2 KBr + Na2SO3 = 2 CuBr + Na2SO4 + H2SO4 + K2SO4 + 9 H2O
Al2O3 + CuCO3 = CuAlO2 + CO + O2 =>
2 Al2O3 + 4 CuCO3 = 4 CuAlO2 + 4 CO + 3 O2
CaSiO3 + Na2CO3 = CaCO3 + Na2SiO3 =>
CaSiO3 + Na2CO3 = CaCO3 + Na2SiO3
Hg(NO3)2 + H2O = Hg(OH)2 + HNO3 =>
Hg(NO3)2 + 2 H2O = Hg(OH)2 + 2 HNO3
KNO3 = KNO2 + O2 = KNO3 = KNO2 =>
2 KNO3 = 2 KNO2 + O2
TiO2 + BaO = BaTiO3 =>
TiO2 + BaO = BaTiO3
C2H2COOH + O2 = CO2 + H2O =>
4 C2H2COOH + 11 O2 = 12 CO2 + 6 H2O
Cl2(g) + CaBr2(aq) = Ca + Cl2Br2 =>
Cl2(g) + CaBr2(aq) = Ca + Cl2Br2
Balance the equation of any chemical reaction
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/13/24
Equations balanced on 01/12/24
Please let us know how we can improve this web app.