| Equations balanced on the previous day |
Cl2 + Ca + O2 = Ca(ClO)2
FeCl3 + CuCO3 = Fe(CO3)3 + CuCl =>
FeCl3 + 3 CuCO3 = Fe(CO3)3 + 3 CuCl
KClO3 + KMnO4 + H2SO4 = HClO4 + MnSO4 + K2SO4 + H2O =>
10 KClO3 + 4 KMnO4 + 11 H2SO4 = 10 HClO4 + 4 MnSO4 + 7 K2SO4 + 6 H2O
MnO4{-} + Cl{-} + H2SO4 = Mn{2+} + Cl2 + H2O + SO4{2-} =>
2 MnO4{-} + 10 Cl{-} + 8 H2SO4 = 2 Mn{2+} + 5 Cl2 + 8 H2O + 8 SO4{2-}
Ba(NO3)2 + K2SO4 = Ba(SO4) + KNO3 =>
Ba(NO3)2 + K2SO4 = Ba(SO4) + 2 KNO3
HBr + Mg = H2 + MgBr2 =>
2 HBr + Mg = H2 + MgBr2
Pb3O4 + Fe = FeO + PbO =>
Pb3O4 + Fe = FeO + 3 PbO
HIO3 + HCl = I2 + Cl2 + H2O =>
2 HIO3 + 10 HCl = I2 + 5 Cl2 + 6 H2O
ZrOCl2*8H2O + NH4H2PO4 = Zr3(PO4)4 + NH3 + HCl + H2O =>
3 ZrOCl2*8H2O + 4 NH4H2PO4 = Zr3(PO4)4 + 4 NH3 + 6 HCl + 27 H2O
C10*O8*H14 + O2 = CO2 + H2O =>
2 C10*O8*H14 + 19 O2 = 20 CO2 + 14 H2O
Fe2(SO4)3 + HOH = (FeOH)SO4 + H2SO4 =>
Fe2(SO4)3 + 2 HOH = 2(FeOH)SO4 + H2SO4
Na2CrO4 + NaOH + H2O2 = Na3[Cr(OH)3] + O2 =>
Na2CrO4 + NaOH + H2O2 = Na3[Cr(OH)3] + 2 O2
C2H5NO2 + KOH = CO2 + (NH4)OH + K + H2O =>
C2H5NO2 + 6 KOH = 2 CO2 + (NH4)OH + 6 K + 3 H2O
NaCn + HCl = HCn + NaCl =>
NaCn + HCl = HCn + NaCl
BI2O3 + Cl2 + KOH = BI2O5 + KCl + H2O =>
BI2O3 + 2 Cl2 + 4 KOH = BI2O5 + 4 KCl + 2 H2O
Li + N3 = Li3N =>
9 Li + N3 = 3 Li3N
PO2 + H2 = PH3 + H2O =>
2 PO2 + 7 H2 = 2 PH3 + 4 H2O
Li + KOH = LiOH + K =>
Li + KOH = LiOH + K
Bi2O3 + H2 = Bi2H2 + O3 =>
Bi2O3 + H2 = Bi2H2 + O3
K2CO3 + BaCl2 = Ba(CO3) + K2Cl2 =>
K2CO3 + BaCl2 = Ba(CO3) + K2Cl2
HH2O = H2 + O2 =>
2 HH2O = 3 H2 + O2
H2O + AlI3 = HI + Al2O3 =>
3 H2O + 2 AlI3 = 6 HI + Al2O3
K + HCl = KCl + H2 =>
2 K + 2 HCl = 2 KCl + H2
K4Fe[CN]6 + H2SO4 + H2O = K2SO4 + FeSO4 + (NH4)2SO4 + CO =>
K4Fe[CN]6 + 6 H2SO4 + 6 H2O = 2 K2SO4 + FeSO4 + 3(NH4)2SO4 + 6 CO
CuBO2 + NaBO2 + C = Cu + Na2B4O7 + CO =>
2 CuBO2 + 2 NaBO2 + C = 2 Cu + Na2B4O7 + CO
Na(OH)2 + NaClO + H2O = Na(OH)3 + NaCl =>
2 Na(OH)2 + NaClO + H2O = 2 Na(OH)3 + NaCl
(C2H5)2O + NH3 = (C2H5)2ONH3 =>
(C2H5)2O + NH3 = (C2H5)2ONH3
C + MnO = CO2 + Mn =>
C + 2 MnO = CO2 + 2 Mn
Ca(IO3)2 = Ca + I + O3 =>
Ca(IO3)2 = Ca + 2 I + 2 O3
H2O + AgI = H2Ag2 + OI2 =>
H2O + 2 AgI = H2Ag2 + OI2
S4 + O2 + Cl2 = SOCl2 =>
S4 + 2 O2 + 4 Cl2 = 4 SOCl2
Fe123 + Cl7 = FeCl3 =>
7 Fe123 + 369 Cl7 = 861 FeCl3
C6H12O6 + NH3 + H2SO4 = C1742H2757N473O554S9 + CO2 + H2O =>
1813 C6H12O6 + 2838 NH3 + 54 H2SO4 = 6 C1742H2757N473O554S9 + 426 CO2 + 6918 H2O
C6H5MgBr + CO2 + C6H5Br + HCl = C12H10 + C6H5COOH + MgBr2Cl =>
2 C6H5MgBr + 2 CO2 + 2 C6H5Br + 2 HCl = C12H10 + 2 C6H5COOH + 2 MgBr2Cl
K2Cr2O7 + NH4OH = Cr(OH)3 + N2 + KOH + H2O =>
K2Cr2O7 + 2 NH4OH = 2 Cr(OH)3 + N2 + 2 KOH + H2O
Al(s) + NaOH + H2O = Na{+} + [Al(OH)4]{-} + H2(g) =>
2 Al(s) + 2 NaOH + 6 H2O = 2 Na{+} + 2[Al(OH)4]{-} + 3 H2(g)
Zn(HSO4)2 + BaOHCl = ZnCl2 + BaSO4 + H2O =>
Zn(HSO4)2 + 2 BaOHCl = ZnCl2 + 2 BaSO4 + 2 H2O
SPb + HNO3 = Pb(NO3)2 + S + NO + H2O =>
3 SPb + 8 HNO3 = 3 Pb(NO3)2 + 3 S + 2 NO + 4 H2O
Cr(OH)2 = H2O + CrO =>
Cr(OH)2 = H2O + CrO
Fe(NO3)3 + MgS = Fe2S3 + Mg(NO3)2 = =>
2 Fe(NO3)3 + 3 MgS = Fe2S3 + 3 Mg(NO3)2
C5H7O2N + H2O = CO2 + NH3 + H =>
C5H7O2N + 8 H2O = 5 CO2 + NH3 + 20 H
Fr + Cl2 + O2 = FrClO4 =>
2 Fr + Cl2 + 4 O2 = 2 FrClO4
Fe(NO3)3 + NH4HS = Fe(NH3) + H2S + NO3 =>
Fe(NO3)3 + NH4HS = Fe(NH3) + H2S + 3 NO3
Na2HPO3 + NaOH = H3PO3 + Na + O2 =>
Na2HPO3 + 2 NaOH = H3PO3 + 4 Na + O2
Fe(NO3)2(aq) + Na2S(aq) = FeS + NaNO3 =>
Fe(NO3)2(aq) + Na2S(aq) = FeS + 2 NaNO3
MgS(s) + HNO3(aq) = Mg(NO3)2(aq) + H2S(aq) =>
MgS(s) + 2 HNO3(aq) = Mg(NO3)2(aq) + H2S(aq)
NH4ClO4 + Al = Al2O3 + AlCl3 + H2O + N =>
3 NH4ClO4 + 5 Al = 2 Al2O3 + AlCl3 + 6 H2O + 3 N
K2[Zn(OH)4] = Zn(OH)2 + K2(OH)2 =>
K2[Zn(OH)4] = Zn(OH)2 + K2(OH)2
P2S3 + Cl2 + H2O = H3PO4 + HCl + S =>
P2S3 + 5 Cl2 + 8 H2O = 2 H3PO4 + 10 HCl + 3 S
Ba(OH)2 + BaCl2 = ClOH + Ba =>
Ba(OH)2 + BaCl2 = 2 ClOH + 2 Ba
Balance the equation of any chemical reaction
| Equations balanced on the previous day |
Equations balanced on 12/12/24
Equations balanced on 01/11/24
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