Equations balanced on the previous day |
BaCl2 + NH3 = BaNH3 + 2 Cl
Ca3(PO4)2 + ZnSO4 = Zn3(PO4)2 + CaSO4 =>
Ca3(PO4)2 + 3 ZnSO4 = Zn3(PO4)2 + 3 CaSO4
CH4(g) + NH3(g) = HCN(g) + H2 =>
CH4(g) + NH3(g) = HCN(g) + 3 H2
[Ru2(CO)3(CO)4(PPh3)2] + KOH = K2[Ru2(CO)6(PPh3)2] + K2CO3 + H2O =>
[Ru2(CO)3(CO)4(PPh3)2] + 4 KOH = K2[Ru2(CO)6(PPh3)2] + K2CO3 + 2 H2O
MgSO4 + H2SO4 = Mg(HSO4)2 =>
MgSO4 + H2SO4 = Mg(HSO4)2
BaO + ZnO = BaZnO2 =>
BaO + ZnO = BaZnO2
CH4(g) + NH3(g) = HCN(g) + H2 =>
CH4(g) + NH3(g) = HCN(g) + 3 H2
RbOH + Al2O3 + H2O = Rb3[Al(OH)6] =>
6 RbOH + Al2O3 + 3 H2O = 2 Rb3[Al(OH)6]
CH3COOH + Cr2O72{-} + H{+} = CO2 + H2O + Cr3{+} =>
427 CH3COOH + 24 Cr2O72{-} + 40 H{+} = 854 CO2 + 874 H2O + 16 Cr3{+}
KMnO4 + H2SO4 + NaNO2 = MnSO4 + NaNO3 + H2O + K2SO4 =>
2 KMnO4 + 3 H2SO4 + 5 NaNO2 = 2 MnSO4 + 5 NaNO3 + 3 H2O + K2SO4
Fe + CHO2 = FeO + HCO =>
Fe + CHO2 = FeO + HCO
Ca + H2O = Ca(OH)2 + H2 =>
Ca + 2 H2O = Ca(OH)2 + H2
C9H12 + KMnO4 + H2SO4 = C8H6O4 + K2SO4 + MnSO4 + H2O =>
40 C9H12 + 114 KMnO4 + 171 H2SO4 = 45 C8H6O4 + 57 K2SO4 + 114 MnSO4 + 276 H2O
CoCl2 + Na2SO4 = Co(SO4) + NaCl =>
CoCl2 + Na2SO4 = Co(SO4) + 2 NaCl
Zn + HCl + H2O = [Zn(H2O)4]Cl2 + H2 =>
Zn + 2 HCl + 4 H2O = [Zn(H2O)4]Cl2 + H2
HCl + S = H + SCl =>
HCl + S = H + SCl
Cl2(g) + S8(s) = SCl2 =>
8 Cl2(g) + S8(s) = 8 SCl2
NH3 + BaCl2 = Ba3N2 + HCl =>
2 NH3 + 3 BaCl2 = Ba3N2 + 6 HCl
NaHSO4 + NaCl + H2 + O2 = Na2SO4*10H2O + HCl =>
NaHSO4 + NaCl + 10 H2 + 5 O2 = Na2SO4*10H2O + HCl
KMnO4 + H2C2O4 + H2SO4 = MnSO4 + K2SO4 + CO2 + H2O =>
2 KMnO4 + 5 H2C2O4 + 3 H2SO4 = 2 MnSO4 + K2SO4 + 10 CO2 + 8 H2O
Cu + O2 = Cu2O =>
4 Cu + O2 = 2 Cu2O
CO(g) = C(s) + CO2(g) =>
2 CO(g) = C(s) + CO2(g)
PCl3 + KOH = K2HPO3 + KCl + H2O =>
PCl3 + 5 KOH = K2HPO3 + 3 KCl + 2 H2O
BaCl2 + NH3 = Ba(NH3)2 + Cl =>
BaCl2 + 2 NH3 = Ba(NH3)2 + 2 Cl
NH3 + O2 = NO2 + H2O =>
4 NH3 + 7 O2 = 4 NO2 + 6 H2O
BaCl2 + NH3 = Ba(NH3)2 + Cl =>
BaCl2 + 2 NH3 = Ba(NH3)2 + 2 Cl
CuS + H2SO4 = CuSO4 + SO2 + H2O =>
CuS + 4 H2SO4 = CuSO4 + 4 SO2 + 4 H2O
Fe + HClO3 = Fe(ClO3)3 + HCl + H2O =>
2 Fe + 7 HClO3 = 2 Fe(ClO3)3 + HCl + 3 H2O
CH4(g) + NH3(g) = HCN(g) + H2 =>
CH4(g) + NH3(g) = HCN(g) + 3 H2
C3H7NH2 + H2O = C3H7NH3 + OH =>
C3H7NH2 + H2O = C3H7NH3 + OH
Fe3C + PbO2 + HNO3 = Fe(NO3)3 + Pb(NO3)2 + CO2 + H2O =>
2 Fe3C + 13 PbO2 + 44 HNO3 = 6 Fe(NO3)3 + 13 Pb(NO3)2 + 2 CO2 + 22 H2O
K2CO3 + BaCl2 = KCl + BaCO3 =>
K2CO3 + BaCl2 = 2 KCl + BaCO3
As2O5 + KOH = AsKO3 + H2O =>
As2O5 + 2 KOH = 2 AsKO3 + H2O
CaSiO3 + CO2 + H2O = Ca{2+} + HCO3{-} + SiO2 =>
CaSiO3 + 2 CO2 + H2O = Ca{2+} + 2 HCO3{-} + SiO2
NH3 + BaCl2 = NCl3 + BaH2 =>
2 NH3 + 3 BaCl2 = 2 NCl3 + 3 BaH2
NH3 + O2 = NO2 + H2O =>
4 NH3 + 7 O2 = 4 NO2 + 6 H2O
C9H12 + KMnO4 + H2SO4 = C7H6O2 + K2SO4 + MnSO4 + H2O =>
35 C9H12 + 66 KMnO4 + 99 H2SO4 = 45 C7H6O2 + 33 K2SO4 + 66 MnSO4 + 174 H2O
C3H6(g) + O2(g) = CO2(g) + H2O(g) =>
2 C3H6(g) + 9 O2(g) = 6 CO2(g) + 6 H2O(g)
H2CO3 + NH4OH = (NH4)2CO3 + H2O =>
H2CO3 + 2 NH4OH = (NH4)2CO3 + 2 H2O
CH4(g) + NH3(g) = HCN(g) + H2 =>
CH4(g) + NH3(g) = HCN(g) + 3 H2
SIC + Cl2 = SICl4 + C =>
SIC + 2 Cl2 = SICl4 + C
C9H12 + KMnO4 + H2SO4 = C8H6O4 + K2SO4 + MnSO4 + H2O =>
40 C9H12 + 114 KMnO4 + 171 H2SO4 = 45 C8H6O4 + 57 K2SO4 + 114 MnSO4 + 276 H2O
NaOH + CH3Br = CH3OH + NaBr =>
NaOH + CH3Br = CH3OH + NaBr
Zn(ClO4)2 + KOH = KClO4 + Zn(OH)2 =>
Zn(ClO4)2 + 2 KOH = 2 KClO4 + Zn(OH)2
N2Cl4 + CH4 = CCl4 + N6 + H12 =>
3 N2Cl4 + 3 CH4 = 3 CCl4 + N6 + H12
CH40 + O2 = H2O + CO2 =>
CH40 + 11 O2 = 20 H2O + CO2
(NH4)2S + K2Cr2O7 + KOH + H2O = S + K3[Cr(OH)6] + NH3*H2O =>
3(NH4)2S + K2Cr2O7 + 4 KOH + 7 H2O = 3 S + 2 K3[Cr(OH)6] + 6 NH3*H2O
Cl + HBr + H2O = ClBr + H3O =>
Cl + HBr + H2O = ClBr + H3O
CH3COOH + CH3CH2CH2OH = CH3COOCH2CH2OH + H2O =>
9 CH3COOH + 2 CH3CH2CH2OH = 6 CH3COOCH2CH2OH + 2 H2O
TIO2 + Ca = TI + CaO =>
TIO2 + 2 Ca = TI + 2 CaO
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 11/17/24
Equations balanced on 12/17/23
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