Equations balanced on the previous day |
HCl + NaOH = NaCl + H2O
Zn + CuCI2 = ZnCI2 + Cu =>
Zn + CuCI2 = ZnCI2 + Cu
NaCl + K3(PO)4 = KCl + Na3(PO)4 =>
3 NaCl + K3(PO)4 = 3 KCl + Na3(PO)4
Na + H2O = NaOH + H =>
Na + H2O = NaOH + H
Fe(NO3)3 + Ca(NO3)2 + La(NO3)3 + Co(NO3)2 + C2H5NO2 = Ca9*8La0*2CoFeO5 + N2 + CO2 + H2O =>
18 Fe(NO3)3 + 81 Ca(NO3)2 + 72 La(NO3)3 + 18 Co(NO3)2 + 292 C2H5NO2 = 9 Ca9*8La0*2CoFeO5 + 380 N2 + 584 CO2 + 730 H2O
C2H8O7P2 + NaOH = C2H4Na4O7P2 + H2O =>
C2H8O7P2 + 4 NaOH = C2H4Na4O7P2 + 4 H2O
H2SO4 + NaOH = Na2SO4 + H2O =>
H2SO4 + 2 NaOH = Na2SO4 + 2 H2O
Na2[Zn(OH)4] + H2S = Zn(OH)2 + Na2S + H2O =>
Na2[Zn(OH)4] + H2S = Zn(OH)2 + Na2S + 2 H2O
Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2
AgNO3 + NaCl = AgCl + NaNO3 =>
AgNO3 + NaCl = AgCl + NaNO3
Mn + H2SO4 = MnSO4 + H2 =>
Mn + H2SO4 = MnSO4 + H2
AlS = Al + S8 =>
8 AlS = 8 Al + S8
HCl + NaOH = NaCl + H2O =>
HCl + NaOH = NaCl + H2O
Fe(OH)3 + H2SO3 = Fe2(SO3)3 + H2O =>
2 Fe(OH)3 + 3 H2SO3 = Fe2(SO3)3 + 6 H2O
Cu2(OH)2CO3 = CuO + CO2 + H2O =>
Cu2(OH)2CO3 = 2 CuO + CO2 + H2O
FeSO4 + KMnO4 + H2SO4 = Fe2(SO4)3 + MnSO4 + K2SO4 + H2O =>
10 FeSO4 + 2 KMnO4 + 8 H2SO4 = 5 Fe2(SO4)3 + 2 MnSO4 + K2SO4 + 8 H2O
Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2
AlCl3 + Na2CO3 + H2O = Al(OH)3 + CO2 + NaCl =>
2 AlCl3 + 3 Na2CO3 + 3 H2O = 2 Al(OH)3 + 3 CO2 + 6 NaCl
KMnO4 + H2O = H2O2 + KMn =>
KMnO4 + 4 H2O = 4 H2O2 + KMn
MnCl2 + H2SO4 = Mn2(SO4)2 + HCl =>
2 MnCl2 + 2 H2SO4 = Mn2(SO4)2 + 4 HCl
K3[Cr(OH)6] + Br2 + KOH = K2CrO4 + H2O + KBr =>
2 K3[Cr(OH)6] + 3 Br2 + 4 KOH = 2 K2CrO4 + 8 H2O + 6 KBr
H2SO4 + Al = H + Al3(SO4)3 =>
3 H2SO4 + 3 Al = 6 H + Al3(SO4)3
CuSe + HNO3 = NO + Cu(NO3)2 + Se + H2O =>
3 CuSe + 8 HNO3 = 2 NO + 3 Cu(NO3)2 + 3 Se + 4 H2O
C20H12N2Na2O7S2 + NaOH = Na + CO2 + H2O + N + S =>
C20H12N2Na2O7S2 + 78 NaOH = 80 Na + 20 CO2 + 45 H2O + 2 N + 2 S
CH3CH2OH + K2Cr2O7 = CH3CH2O7 + K2Cr2OH =>
CH3CH2OH + K2Cr2O7 = CH3CH2O7 + K2Cr2OH
CuC2O4*2H2O = CuO + CO + CO2 + H2O =>
CuC2O4*2H2O = CuO + CO + CO2 + 2 H2O
CH2CHCH2OH + KMnO4 + H2O = KOH + MnO2 + CH2(OH)CH(OH)CH2(OH) =>
3 CH2CHCH2OH + 2 KMnO4 + 4 H2O = 2 KOH + 2 MnO2 + 3 CH2(OH)CH(OH)CH2(OH)
KCrO4 + NaSO4 = KSO4 + NaCrO4 =>
KCrO4 + NaSO4 = KSO4 + NaCrO4
FeS + O2 = Fe2O3 + SO2 =>
4 FeS + 7 O2 = 2 Fe2O3 + 4 SO2
NaOH + AlCl3 = NaCl3 + OHAl =>
NaOH + AlCl3 = NaCl3 + OHAl
H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O
FePO4 = Fe + PO4 =>
FePO4 = Fe + PO4
NaCl + KC4H5O6 = KCl + NaC4H5O6 =>
NaCl + KC4H5O6 = KCl + NaC4H5O6
MgSO4(aq) + Zn(NO3)2(aq) = Mg(NO3)2(aq) + ZnSO4(aq) =>
MgSO4(aq) + Zn(NO3)2(aq) = Mg(NO3)2(aq) + ZnSO4(aq)
MnCl2 + H2SO4 = Mn2(SO4)2 + HCl =>
2 MnCl2 + 2 H2SO4 = Mn2(SO4)2 + 4 HCl
(c)Na2B4O7(s) + H2SO4(aq) + H2O(l) = H3BO3(s) + Na2SO4(aq) =>
(c)Na2B4O7(s) + H2SO4(aq) + 5 H2O(l) = 4 H3BO3(s) + Na2SO4(aq)
Ca + H3PO4 = Ca3(PO4)2 + H2 =>
3 Ca + 2 H3PO4 = Ca3(PO4)2 + 3 H2
Cu(NO3)2 + CaO = CuO + Ca(NO3)2 =>
Cu(NO3)2 + CaO = CuO + Ca(NO3)2
Bi(OH)3 + HCl = BiCl + H(OH)3 =>
Bi(OH)3 + HCl = BiCl + H(OH)3
CHCHCN + LiAlH4 = CH3CH2CH2NH2 + LiAl =>
4 CHCHCN + 7 LiAlH4 = 4 CH3CH2CH2NH2 + 7 LiAl
CoSCN + KOH + C5H11 + NH3 = Co(NH3)2 + KSCN + C5H11OH =>
CoSCN + KOH + C5H11 + 2 NH3 = Co(NH3)2 + KSCN + C5H11OH
Zn + KNO2 + KOH = K2ZnO2 + NH3 + Zn(NO2)2 =>
6 Zn + 4 KNO2 + 6 KOH = 5 K2ZnO2 + 2 NH3 + Zn(NO2)2
V4(Sb2O7)5 + KCl = K4(Sb2O7) + VCl5 =>
V4(Sb2O7)5 + 20 KCl = 5 K4(Sb2O7) + 4 VCl5
Mg4Al2(OH)12(NO3)2*6H2O + Na2WO4*2H2O = Mg4Al2(OH)12WO4*6H2O + NaNO3 + H2O =>
Mg4Al2(OH)12(NO3)2*6H2O + Na2WO4*2H2O = Mg4Al2(OH)12WO4*6H2O + 2 NaNO3 + 2 H2O
Al + NiCl2 = AlCl3 + Ni =>
2 Al + 3 NiCl2 = 2 AlCl3 + 3 Ni
MgI2 + Cu(NO3)2 = Mg(NO3)2 + CuI2 =>
MgI2 + Cu(NO3)2 = Mg(NO3)2 + CuI2
CrCl2(s) + Ba(OH)2(s) = Cr(OH)2 + BaCl2 =>
CrCl2(s) + Ba(OH)2(s) = Cr(OH)2 + BaCl2
CO + O2 = CO2 =>
2 CO + O2 = 2 CO2
CH3COOH + LiOH = H2O + LiC2H3O2 =>
CH3COOH + LiOH = H2O + LiC2H3O2
K2S(aq) + FeSO4(aq) = FeS(s) + K2SO4(aq) =>
K2S(aq) + FeSO4(aq) = FeS(s) + K2SO4(aq)
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 11/04/24
Equations balanced on 12/04/23
Please let us know how we can improve this web app.