Equations balanced on the previous day |
3 FeSO4 + 8 HNO3 = 2 NO + Fe(SO4)3 + 2 Fe(NO3)3 + 4 H2O
[Fe(CN)6]{-4} + Cu2(SO4)3 = Cu4[Fe(CN)6]3 + SO4{-2} =>
3[Fe(CN)6]{-4} + 2 Cu2(SO4)3 = Cu4[Fe(CN)6]3 + 6 SO4{-2}
K2Cr2O7 + NaI + H2SO4 = Cr2(SO4)3 + I2 + H2O + Na2SO4 + K2SO4 =>
K2Cr2O7 + 6 NaI + 7 H2SO4 = Cr2(SO4)3 + 3 I2 + 7 H2O + 3 Na2SO4 + K2SO4
Cu(s) + AgNO3(ac) = Cu(NO3)2(ac) + Ag(s) =>
Cu(s) + 2 AgNO3(ac) = Cu(NO3)2(ac) + 2 Ag(s)
LiAlH4 + AlCl3 = AlH3 + LiCl =>
3 LiAlH4 + AlCl3 = 4 AlH3 + 3 LiCl
HClO4 + CH3COOH = ClO4{-} + CH3COOH2{+} =>
HClO4 + CH3COOH = ClO4{-} + CH3COOH2{+}
C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
LiOH + H2(CO3) = Li(CO3) + H2(OH) =>
LiOH + H2(CO3) = Li(CO3) + H2(OH)
Al + S = Al2S3 =>
2 Al + 3 S = Al2S3
NO + O2 = NO2 =>
2 NO + O2 = 2 NO2
NaBr + KMnO4 + H2O = Br2 + MnO2 + NaOH + KOH =>
6 NaBr + 2 KMnO4 + 4 H2O = 3 Br2 + 2 MnO2 + 6 NaOH + 2 KOH
Na2SnO2 + Bi(OH)3 = Na2SnO3 + Bi + H2O =>
3 Na2SnO2 + 2 Bi(OH)3 = 3 Na2SnO3 + 2 Bi + 3 H2O
Na3PO4 + Ba(NO3)2 = Ba3(PO4)2 + NaNO3 =>
2 Na3PO4 + 3 Ba(NO3)2 = Ba3(PO4)2 + 6 NaNO3
Na3PO4 + Ca(NO3)2 = NaNO3 + Ca3(PO4)2 =>
2 Na3PO4 + 3 Ca(NO3)2 = 6 NaNO3 + Ca3(PO4)2
Ag2S2O3(g) + H2O(l) = Ag2S(s) + H2SO4 =>
Ag2S2O3(g) + H2O(l) = Ag2S(s) + H2SO4
K2SO4 + H3PO4 = H2SO4 + K3PO4 =>
3 K2SO4 + 2 H3PO4 = 3 H2SO4 + 2 K3PO4
NaBr + AgNO3 = NaNO3 + AgBr =>
NaBr + AgNO3 = NaNO3 + AgBr
Pb2 + NO3 + NaSO4 = PbSO4 + NaNO3 =>
Pb2 + 2 NO3 + 2 NaSO4 = 2 PbSO4 + 2 NaNO3
NaBr + Ca(OH)2 = CaBr2 + NaOH =>
2 NaBr + Ca(OH)2 = CaBr2 + 2 NaOH
H3PO3 + KOH = H3PO3KOH =>
H3PO3 + KOH = H3PO3KOH
C4H6O4Ba + Na2CrO4 = BaCrO4 + Na2C4H6O4 =>
C4H6O4Ba + Na2CrO4 = BaCrO4 + Na2C4H6O4
FeSO4 + KClO3 + HCl = FeCl3 + K2SO4 + Cl2 + H2O =>
2 FeSO4 + 4 KClO3 + 24 HCl = 2 FeCl3 + 2 K2SO4 + 11 Cl2 + 12 H2O
UO2(NO3)2 + H2O2 + H2O = UO4*2H2O + HNO3 =>
UO2(NO3)2 + H2O2 + 2 H2O = UO4*2H2O + 2 HNO3
NaCO3 + CH3COOH = CH3COONa + CO2 + HOH =>
8 NaCO3 + 9 CH3COOH = 8 CH3COONa + 10 CO2 + 6 HOH
Cl + Au = AuCl =>
Cl + Au = AuCl
K2C2O4*H2O + FeCl3*6H2O = K3[Fe(C2O4)3*3H2O] + KCl + H2O =>
3 K2C2O4*H2O + FeCl3*6H2O = K3[Fe(C2O4)3*3H2O] + 3 KCl + 6 H2O
FeCl2 + H2SO3 + HCl = FeCl3 + S + H2O =>
4 FeCl2 + H2SO3 + 4 HCl = 4 FeCl3 + S + 3 H2O
Mg(s) + Cr(NO3)3(aq) = Mg(NO3)2(aq) + Cr(s) =>
3 Mg(s) + 2 Cr(NO3)3(aq) = 3 Mg(NO3)2(aq) + 2 Cr(s)
NaCl + I2 + H2O = HCl + NaIO4 + NaI =>
8 NaCl + 4 I2 + 4 H2O = 8 HCl + NaIO4 + 7 NaI
HN3 + NO2 = NO + H2O =>
2 HN3 + 7 NO2 = 13 NO + H2O
H2SO4 + NaOH = Na2SO4 + H2O =>
H2SO4 + 2 NaOH = Na2SO4 + 2 H2O
K2Cr2O7 + Ca(NO2)2 + H2SO4 = Cr2(SO4)3 + K2SO4 + Ca(NO3)2 + H2O =>
2 K2Cr2O7 + 3 Ca(NO2)2 + 8 H2SO4 = 2 Cr2(SO4)3 + 2 K2SO4 + 3 Ca(NO3)2 + 8 H2O
HNO3 + Mg(OH)2 = Mg(NO3)2 + H2O =>
2 HNO3 + Mg(OH)2 = Mg(NO3)2 + 2 H2O
NaCl + MnO2 + H2SO4 = NaHSO4 + MnSO4 + H2O + Cl2 =>
2 NaCl + MnO2 + 3 H2SO4 = 2 NaHSO4 + MnSO4 + 2 H2O + Cl2
AgBr = Ag + Br2 =>
2 AgBr = 2 Ag + Br2
CCl2F2 + H2 = CH2F2 + HCl =>
CCl2F2 + 2 H2 = CH2F2 + 2 HCl
NaMnO4 + NaOH = Na2MnO4 + O2 + H =>
2 NaMnO4 + 2 NaOH = 2 Na2MnO4 + O2 + 2 H
Fe + CuCl2 = FeCl + Cu22 =>
44 Fe + 22 CuCl2 = 44 FeCl + Cu22
HC8H7O7(aq) + NaHCO3(aq) = NaC8H7O7(aq) + H2O(l) + CO2(g) =>
HC8H7O7(aq) + NaHCO3(aq) = NaC8H7O7(aq) + H2O(l) + CO2(g)
NaHCO3 + CH3COOH = CH3COONa + CO2 + HOH =>
NaHCO3 + CH3COOH = CH3COONa + CO2 + HOH
CaCl2 + Na2CO3 = CaCO3 + NaCl =>
CaCl2 + Na2CO3 = CaCO3 + 2 NaCl
MnO4{-} + C2O4{-} + H2O = CO2 + MnO2 + OH{-} =>
MnO4{-} + 3 C2O4{-} + 2 H2O = 6 CO2 + MnO2 + 4 OH{-}
CH2CHCHO + O2 = CH2CHCOOH =>
2 CH2CHCHO + O2 = 2 CH2CHCOOH
HBr(aq) + MgSO3(s) = H2SO3(aq) + MgBr2 =>
2 HBr(aq) + MgSO3(s) = H2SO3(aq) + MgBr2
K2Cr2O7 + H2O2 = Cr2O3 + O2 + KOH =>
K2Cr2O7 + H2O2 = Cr2O3 + 2 O2 + 2 KOH
H2S + O2 = H2O + S =>
2 H2S + O2 = 2 H2O + 2 S
sulfuricacid + NaOH = H2O + Na2SO4 =>
H2SO4 + 2 NaOH = 2 H2O + Na2SO4
Al + (HO) = Al(HO) =>
Al + (HO) = Al(HO)
NaHCO3 + CH3COOH = CH3COONa + H2O + CO2 =>
NaHCO3 + CH3COOH = CH3COONa + H2O + CO2
BaCl2 + NaOH = Ba(OH)2 + NaCl =>
BaCl2 + 2 NaOH = Ba(OH)2 + 2 NaCl
Balance the equation of any chemical reaction
Equations balanced on the previous day |
Equations balanced on 10/29/24
Equations balanced on 11/28/23
Please let us know how we can improve this web app.