Equations balanced on the previous day | Equations balanced on the next day |
2 Cr(s) + 6 HCl(aq) = 2 CrCl3 + 3 H2
Fe(OH) + H2SO4 = Fe2SO4 + H2O =>
2 Fe(OH) + H2SO4 = Fe2SO4 + 2 H2O
NH3 + NaOH = NOH3 + NaH =>
NH3 + NaOH = NOH3 + NaH
Fe + CuCl2 = Cl + CuFe =>
Fe + CuCl2 = 2 Cl + CuFe
HAs + NH4F = HF + NH4As =>
HAs + NH4F = HF + NH4As
NH4NO3*210H2O = NH4NO3 + H2O =>
NH4NO3*210H2O = NH4NO3 + 210 H2O
Pb(CH3COO)2 + NaCl = PbCl2 + NaCH3COO =>
Pb(CH3COO)2 + 2 NaCl = PbCl2 + 2 NaCH3COO
Fe(NO3)3 + K2CrO4 = Fe2(CrO4)3 + KNO3 =>
2 Fe(NO3)3 + 3 K2CrO4 = Fe2(CrO4)3 + 6 KNO3
Mg + KMnO4 + H2SO4 = MnSO4 + MgSO4 + K2SO4 + H2O =>
5 Mg + 2 KMnO4 + 8 H2SO4 = 2 MnSO4 + 5 MgSO4 + K2SO4 + 8 H2O
K2CO3(aq) + HBr(aq) = KBr + H2CO3 =>
K2CO3(aq) + 2 HBr(aq) = 2 KBr + H2CO3
FeO + H2O = Fe(OH)2 =>
FeO + H2O = Fe(OH)2
C3H7Cl + Cl2 = C3H6Cl + HCl =>
2 C3H7Cl + Cl2 = 2 C3H6Cl + 2 HCl
K2S + FeCl3 = Fe3S2 + K + Cl =>
2 K2S + 3 FeCl3 = Fe3S2 + 4 K + 9 Cl
Ni + C4H8O2N2 = [Ni(C4H8O2N2)]2 =>
2 Ni + 2 C4H8O2N2 = [Ni(C4H8O2N2)]2
SbCl5(s) + KI(aq) = SbCl3(s) + KCl(aq) + I2(s) =>
SbCl5(s) + 2 KI(aq) = SbCl3(s) + 2 KCl(aq) + I2(s)
KMnO4 + Na2SO3 + HCl = KCl + MnCl2 + Na2SO4 + H2O =>
2 KMnO4 + 5 Na2SO3 + 6 HCl = 2 KCl + 2 MnCl2 + 5 Na2SO4 + 3 H2O
PbN6 = Pb + N =>
PbN6 = Pb + 6 N
PbN6 = Pb + N2 =>
PbN6 = Pb + 3 N2
CHOH + H2O2 = H2O + CO2 =>
CHOH + 2 H2O2 = 3 H2O + CO2
Cu + HCl = CuCl2 + H2 =>
Cu + 2 HCl = CuCl2 + H2
CO2(g) + H2O(l) = O2(g) + C6H12O2(aq) =>
6 CO2(g) + 6 H2O(l) = 8 O2(g) + C6H12O2(aq)
Ca + O2 = CaO =>
2 Ca + O2 = 2 CaO
CH3COOH(aq) + NaHCO3(s) = NaCH3COO(aq) + H2O(l) + CO2(g) =>
CH3COOH(aq) + NaHCO3(s) = NaCH3COO(aq) + H2O(l) + CO2(g)
N2O3 + Ca(OH)2 = Ca(OH)NO2 + H2O =>
N2O3 + 2 Ca(OH)2 = 2 Ca(OH)NO2 + H2O
Co(NO3)2 + LiOH = Co(OH)2 + LiNO3 =>
Co(NO3)2 + 2 LiOH = Co(OH)2 + 2 LiNO3
PbN6 = Pb + N =>
PbN6 = Pb + 6 N
Cu(NO3)2*25H2O + Cr2O3 = CuCrO2 + O2 + H2O + N2 =>
4 Cu(NO3)2*25H2O + 2 Cr2O3 = 4 CuCrO2 + 11 O2 + 100 H2O + 4 N2
HNO3 + Fe(OH)2 = Fe(OH)3 + NO2 =>
HNO3 + Fe(OH)2 = Fe(OH)3 + NO2
(CH3)2CC(CH3)2 + KMnO4 + H2SO4 = CH3COOH + MnSO4 + K2SO4 + H2O =>
5(CH3)2CC(CH3)2 + 12 KMnO4 + 18 H2SO4 = 15 CH3COOH + 12 MnSO4 + 6 K2SO4 + 18 H2O
AgC2H3O2 + MgSO4 = Ag2SO4 + Mg(C2H3O2)2 =>
2 AgC2H3O2 + MgSO4 = Ag2SO4 + Mg(C2H3O2)2
CO + H2 = CH3OH =>
CO + 2 H2 = CH3OH
Mg + H(NO3) = Mg(NO3)2 + H2O + NO2 =>
Mg + 4 H(NO3) = Mg(NO3)2 + 2 H2O + 2 NO2
CaCl2 + Na3PO4 = Ca3(PO4)2 + NaCl =>
3 CaCl2 + 2 Na3PO4 = Ca3(PO4)2 + 6 NaCl
C3H7CHO + Cu(OH)2 = Cu2O + C3H7COOH + H2O =>
C3H7CHO + 2 Cu(OH)2 = Cu2O + C3H7COOH + 2 H2O
H2SO4(aq) + NaOH(aq) = H2OH(aq) + NaSO4 =>
H2SO4(aq) + NaOH(aq) = H2OH(aq) + NaSO4
BaCOOO + C + HHO = CO + BaOHOH =>
BaCOOO + C + HHO = 2 CO + BaOHOH
CaCl2 + Na3PO4 = Ca3(PO4)2 + NaCl =>
3 CaCl2 + 2 Na3PO4 = Ca3(PO4)2 + 6 NaCl
FeCl2 + FeCl3*6H2O + NaOH = Fe3O4 + NaCl + H2O =>
FeCl2 + 2 FeCl3*6H2O + 8 NaOH = Fe3O4 + 8 NaCl + 16 H2O
PbN6 = Pb + N =>
PbN6 = Pb + 6 N
Pb(NO3)2 + NaN3 = Pb(N3)2 + NaNO3 =>
Pb(NO3)2 + 2 NaN3 = Pb(N3)2 + 2 NaNO3
NaI(aq) + K2CO3(aq) = Na2CO3(aq) + KI(aq) =>
2 NaI(aq) + K2CO3(aq) = Na2CO3(aq) + 2 KI(aq)
KMnO4 + NaCl + H2SO4 = Cl2 + K2O4 + H2O + NaSO4 + MnSO4 =>
2 KMnO4 + 2 NaCl + 4 H2SO4 = Cl2 + K2O4 + 4 H2O + 2 NaSO4 + 2 MnSO4
CuSO4 + CH3CHO + NaOH = Cu2O + Na2SO4 + CH3COONa + H2O =>
2 CuSO4 + CH3CHO + 5 NaOH = Cu2O + 2 Na2SO4 + CH3COONa + 3 H2O
MgCl2 + Cu = Mg + CuCl2 =>
MgCl2 + Cu = Mg + CuCl2
C16H34 + H2O = CO2 + CH4 =>
4 C16H34 + 30 H2O = 15 CO2 + 49 CH4
Al(s) + Pb(N03)2(aq) = Al(N03)3(aq) + Pb(s) =>
2 Al(s) + 3 Pb(N03)2(aq) = 2 Al(N03)3(aq) + 3 Pb(s)
Ca3N2 + water = Ca(OH)2 + NH3 =>
Ca3N2 + 6 H2O = 3 Ca(OH)2 + 2 NH3
C6H2(NO2)3CH3 + O2 = C6H2(NO2)3CH3O2 =>
C6H2(NO2)3CH3 + O2 = C6H2(NO2)3CH3O2
SO2 + HCl = SOCl2 + H2O =>
SO2 + 2 HCl = SOCl2 + H2O
CaN = Ca2 + N2 =>
2 CaN = Ca2 + N2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 |
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 07/23/24
Equations balanced on 08/22/23
Please let us know how we can improve this web app.