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Chemical Equations Balanced on 04/17/24

 Equations balanced on the previous day Equations balanced on the next day
Balance the equation of any chemical reaction
Ba(HCO3)2 = BaCO3 + CO2 + H2O =>
Ba(HCO3)2 = BaCO3 + CO2 + H2O

Al + NiCl2 = Al2(Cl2)3 + Ni =>
2 Al + 3 NiCl2 = Al2(Cl2)3 + 3 Ni

N2C4H3Br + OC4H3B(OH)2 = N2C8OH6 + BrB(OH)2 =>
N2C4H3Br + OC4H3B(OH)2 = N2C8OH6 + BrB(OH)2

K4Fe(CN)6 + MnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HN03 + CO2 + H2O =>
6 K4Fe(CN)6 + 29 MnO4 + 62 H2SO4 = 24 KHSO4 + 3 Fe2(SO4)3 + 29 MnSO4 + 12 HN03 + 36 CO2 + 44 H2O

C4H8 + H2 = C4H10 =>
C4H8 + H2 = C4H10

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

C11H22OH(s) + O2(g) = CO2(g) + H2O(g) =>
4 C11H22OH(s) + 65 O2(g) = 44 CO2(g) + 46 H2O(g)

Pb(NO3)2 + KCl = PbCl2(s) + KNO3(aq) =>
Pb(NO3)2 + 2 KCl = PbCl2(s) + 2 KNO3(aq)

Cd(NO3)2 + (NH4)OH = CdOH + NH4 + NO3 =>
Cd(NO3)2 + (NH4)OH = CdOH + NH4 + 2 NO3

[Co(H2O)6]{2+} + H2O2 + NH3 = [Co(NH3)6]{3+} + OH{-} + H2O =>
2[Co(H2O)6]{2+} + H2O2 + 12 NH3 = 2[Co(NH3)6]{3+} + 2 OH{-} + 12 H2O

NaBr(aq) + Mg(NO3)(aq) = Na(NO3)(aq) + MgBr(aq) =>
NaBr(aq) + Mg(NO3)(aq) = Na(NO3)(aq) + MgBr(aq)

Al + KOH + H2O = K[Al(OH)4(H2O)] + H2 =>
2 Al + 2 KOH + 8 H2O = 2 K[Al(OH)4(H2O)] + 3 H2

MgCl2 + H2SO4 = MgSO4 + H2Cl2 =>
MgCl2 + H2SO4 = MgSO4 + H2Cl2

HCl + O2 = Cl2 + H2O =>
4 HCl + O2 = 2 Cl2 + 2 H2O

NiO2 = Ni + O2 =>
NiO2 = Ni + O2

Ca(NH2)2 + H2O = NH3 + Ca(OH)2 =>
Ca(NH2)2 + 2 H2O = 2 NH3 + Ca(OH)2

C12H22O11 + H = C6H6 + H2O =>
C12H22O11 + 12 H = 2 C6H6 + 11 H2O

PbI2 + KClO3 + HCl = PbCl4 + I2 + KCl + H2O =>
3 PbI2 + 2 KClO3 + 12 HCl = 3 PbCl4 + 3 I2 + 2 KCl + 6 H2O

CH3OC + CH3 = CH3OC(CH3)3 =>
CH3OC + 3 CH3 = CH3OC(CH3)3

CuSO4 + NH4OH = NH4SO4 + CuOH =>
CuSO4 + NH4OH = NH4SO4 + CuOH

Fe(s) + O2(g) = Fe2O3 =>
4 Fe(s) + 3 O2(g) = 2 Fe2O3

BaCl2 + Fe(SO4)3 = Ba(SO4)3 + FeCl2 =>
BaCl2 + Fe(SO4)3 = Ba(SO4)3 + FeCl2

NO2{-} + H3O{+} + I{-} = I2 + NO + H2O =>
2 NO2{-} + 4 H3O{+} + 2 I{-} = I2 + 2 NO + 6 H2O

BaCl2 + Fe(SO4)3 = Ba(SO4)3 + FeCl2 =>
BaCl2 + Fe(SO4)3 = Ba(SO4)3 + FeCl2

H2SO4 + HI = SO02 + I2 + H2O =>
H2SO4 + 2 HI = SO02 + I2 + 2 H2O

Ca(No3)2 + Al(OH)3 = Ca(OH)2 + Al(No3)3 =>
3 Ca(No3)2 + 2 Al(OH)3 = 3 Ca(OH)2 + 2 Al(No3)3

Al + SnCl4 = Sn + AlCl3 =>
4 Al + 3 SnCl4 = 3 Sn + 4 AlCl3

C4H7(OH)3 + O2 = CO2 + H2O =>
C4H7(OH)3 + 5 O2 = 4 CO2 + 5 H2O

CUSO4 + Fe = CU + Fe2(SO4)3 =>
3 CUSO4 + 2 Fe = 3 CU + Fe2(SO4)3

In + H2SO4 = InSO4 + H2S + H2O =>
4 In + 5 H2SO4 = 4 InSO4 + H2S + 4 H2O

Al(s) + Fe(NO3)2(aq) = Al(NO3)2 + Fe(s) =>
Al(s) + Fe(NO3)2(aq) = Al(NO3)2 + Fe(s)

MgCl2 + Al(OH)3 = AlCl3 + Mg(OH)2 =>
3 MgCl2 + 2 Al(OH)3 = 2 AlCl3 + 3 Mg(OH)2

Pb(NO3)2 + (KI) = PbI2 + KNO3 =>
Pb(NO3)2 + 2(KI) = PbI2 + 2 KNO3

C3H6O3 + H2 = C5H12 + H2O =>
5 C3H6O3 + 18 H2 = 3 C5H12 + 15 H2O

NaNO2 + HO = NaNO3 + H2O =>
NaNO2 + 2 HO = NaNO3 + H2O

KMnO4 + (NH4)2Fe(SO4)2 + H2SO4 = K2SO4 + MnSO4 + Fe(SO4)3 + (NH4)2SO4 + H2O =>
4 KMnO4 + 5(NH4)2Fe(SO4)2 + 16 H2SO4 = 2 K2SO4 + 4 MnSO4 + 5 Fe(SO4)3 + 5(NH4)2SO4 + 16 H2O

K2C2O4*H2O + H2C2O4*2H2O + K2Cr2O7 = K3[Cr(C2O4)3]*3H2O + CO2 + H2O =>
2 K2C2O4*H2O + 7 H2C2O4*2H2O + K2Cr2O7 = 2 K3[Cr(C2O4)3]*3H2O + 6 CO2 + 17 H2O

Fe + H2O = Fe(OH)3 + H2 =>
2 Fe + 6 H2O = 2 Fe(OH)3 + 3 H2

iron(iii)oxide + carbonmonoxide = iron + carbondioxide =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2

Pd(OH)4 + H3PO4 = Pd3(PO4)4 + H2O =>
3 Pd(OH)4 + 4 H3PO4 = Pd3(PO4)4 + 12 H2O

H3PO4 + Mq(OH)2 = Mq3(PO4)2 + H2O =>
2 H3PO4 + 3 Mq(OH)2 = Mq3(PO4)2 + 6 H2O

Al2O3 + AlBr3 = Al + O3Br3 =>
Al2O3 + AlBr3 = 3 Al + O3Br3

H2MnO4 + Al(OH)3 = Al(OH)(MnO4) + H2O =>
H2MnO4 + Al(OH)3 = Al(OH)(MnO4) + 2 H2O

K2Cr2O7 + HCl = Cl2 + H2O + CrCl3 + KCl =>
K2Cr2O7 + 14 HCl = 3 Cl2 + 7 H2O + 2 CrCl3 + 2 KCl

Ba(C2O4) + K(IO3) = Ba(IO3)2 + K2(C2O4) =>
Ba(C2O4) + 2 K(IO3) = Ba(IO3)2 + K2(C2O4)

Fe + AgNO3 = Fe(NO3)2 + Ag =>
Fe + 2 AgNO3 = Fe(NO3)2 + 2 Ag

H2NC(O)NH2 + NaHCO3 = H2NC(O)NHCO2H + NaOH =>
H2NC(O)NH2 + NaHCO3 = H2NC(O)NHCO2H + NaOH

Fe3(PO4)2 + NaOH = [Fe(OH)]3PO4 + Na3PO4 =>
Fe3(PO4)2 + 3 NaOH = [Fe(OH)]3PO4 + Na3PO4

NaOH + MgCl2 = Mg(OH)2 + NaCl =>
2 NaOH + MgCl2 = Mg(OH)2 + 2 NaCl

N2 + P4 = NP3 =>
2 N2 + 3 P4 = 4 NP3

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Balance the equation of any chemical reaction
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