| Equations balanced on the previous day | Equations balanced on the next day |
C6H6 + HCl = C6H5Cl + H2
K2Cr2O7(aq) + HI(aq) = KI(aq) + CrI3(aq) + I2(s) + H2O(l) =>
K2Cr2O7(aq) + 14 HI(aq) = 2 KI(aq) + 2 CrI3(aq) + 3 I2(s) + 7 H2O(l)
Na2O + H2O = NaOH =>
Na2O + H2O = 2 NaOH
NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O
Al2(SO4)3 + KBr = Al2Br + K(SO4)3 =>
Al2(SO4)3 + KBr = Al2Br + K(SO4)3
H2SO4 + Ba(OH)2 = BaSO4 + H2O =>
H2SO4 + Ba(OH)2 = BaSO4 + 2 H2O
Cr(OH)3 + KOH + O2 = K2CrO4 + H2O =>
4 Cr(OH)3 + 8 KOH + 3 O2 = 4 K2CrO4 + 10 H2O
Na2SO3 + H2SO4 = Na2SO4 + H2SO3 =>
Na2SO3 + H2SO4 = Na2SO4 + H2SO3
HNO3 + H2SO4 = H2O + HSO4{-} + NO2{+} =>
HNO3 + H2SO4 = H2O + HSO4{-} + NO2{+}
(Cu(NO3)2*3H2O)10 + (Cr(NO3)2*9H2O)10 + (C6H8O7)10 + (Ni(NO3)2*H2O)10 = Cu8Ni2Cr20O40 + N2O + H20O10 + C10O20 =>
36(Cu(NO3)2*3H2O)10 + 90(Cr(NO3)2*9H2O)10 + 55(C6H8O7)10 + 9(Ni(NO3)2*H2O)10 = 45 Cu8Ni2Cr20O40 + 1350 N2O + 1147 H20O10 + 330 C10O20
H2SO3 = H2O + SO2 =>
H2SO3 = H2O + SO2
CaH4P2O8 + NaHCO3 = CaHCO3 + NaH4P2O8 =>
CaH4P2O8 + NaHCO3 = CaHCO3 + NaH4P2O8
BF3 + PH3 + O2 = BP3O2 + HF + H2O =>
2 BF3 + 6 PH3 + 5 O2 = 2 BP3O2 + 6 HF + 6 H2O
P2O5 + BaO = BaO2 + PO2 =>
P2O5 + BaO = BaO2 + 2 PO2
CuCl2(aw) + NH3 + H2O = [Cu(NH3)4(H2O)2] + NH4Cl + OH =>
CuCl2(aw) + 6 NH3 + 4 H2O = [Cu(NH3)4(H2O)2] + 2 NH4Cl + 2 OH
P + HNO3 = H3PO4 + NO2 + H2O =>
P + 5 HNO3 = H3PO4 + 5 NO2 + H2O
SO3 + Cr2O3 = Cr2S + O =>
SO3 + Cr2O3 = Cr2S + 6 O
NaCl + C6H8C7 = C6H8C7NaCl =>
NaCl + C6H8C7 = C6H8C7NaCl
RbNO3 + Zn(OH)2 = Rb + ZnO2 + NH3 + H2O =>
2 RbNO3 + 9 Zn(OH)2 = 2 Rb + 9 ZnO2 + 2 NH3 + 6 H2O
NaBr + F = FBr + Na =>
NaBr + F = FBr + Na
KH4F2 = KF + H2 + F2 =>
2 KH4F2 = 2 KF + 4 H2 + F2
Mg(OH)2 + FeCl3 = Fe(OH)3 + MgCl2 =>
3 Mg(OH)2 + 2 FeCl3 = 2 Fe(OH)3 + 3 MgCl2
H3AsO4 + CuOH = CuAsO3 + H2O =>
H3AsO4 + CuOH = CuAsO3 + 2 H2O
RbNO3 + Zn(OH)2 = Rb + ZnO2 + NH3 + H2O =>
2 RbNO3 + 9 Zn(OH)2 = 2 Rb + 9 ZnO2 + 2 NH3 + 6 H2O
H{+} + Ce{3+} + Pb3O4 = Ce{4+} + PbO + H2O =>
2 H{+} + 2 Ce{3+} + Pb3O4 = 2 Ce{4+} + 3 PbO + H2O
CH4 + O2 = CO2 + HO4 =>
CH4 + 9 O2 = CO2 + 4 HO4
K2S + HNO3 = K2SO4 + NO2 + H2O =>
K2S + 8 HNO3 = K2SO4 + 8 NO2 + 4 H2O
NaOH + Na2Co3 + BaCl2 = BaCo + NaCl2 + OH =>
NaOH + Na2Co3 + 3 BaCl2 = 3 BaCo + 3 NaCl2 + OH
KH4F2 = KF + H2 + F2 =>
2 KH4F2 = 2 KF + 4 H2 + F2
Cl2 + Ca(OH)2 = CaCl2 + Ca(ClO)3 + H2O =>
7 Cl2 + 6 Ca(OH)2 = 4 CaCl2 + 2 Ca(ClO)3 + 6 H2O
CaH4P2O8 + NaHCO3 = Ca3P2O8 + Na2HPO4 + H2O + CO2 =>
3 CaH4P2O8 + 8 NaHCO3 = Ca3P2O8 + 4 Na2HPO4 + 8 H2O + 8 CO2
KH4F2 = KF + H2 + F2 =>
2 KH4F2 = 2 KF + 4 H2 + F2
RbNO3 + Zn(OH)2 = Rb + ZnO2 + NH3 + H2O =>
2 RbNO3 + 9 Zn(OH)2 = 2 Rb + 9 ZnO2 + 2 NH3 + 6 H2O
CaH4P2O8 + NaHCO3 = Ca3(PO4)2 + Na2HPO4 + CO2 + H2O =>
3 CaH4P2O8 + 8 NaHCO3 = Ca3(PO4)2 + 4 Na2HPO4 + 8 CO2 + 8 H2O
CaH4P2O8 + NaHCO3 = CaNa2H2P2O8 + H2O + CO2 =>
CaH4P2O8 + 2 NaHCO3 = CaNa2H2P2O8 + 2 H2O + 2 CO2
RbNO3 + Zn(OH)2 = Rb + ZnO2 + NH3 + H2O =>
2 RbNO3 + 9 Zn(OH)2 = 2 Rb + 9 ZnO2 + 2 NH3 + 6 H2O
CaCl2 + Na2HPO4 + NH3 = Ca3(PO4)2 + NaCl + (NH4)3PO4 =>
3 CaCl2 + 3 Na2HPO4 + 3 NH3 = Ca3(PO4)2 + 6 NaCl + (NH4)3PO4
CuS + HNO3 = NO + Cu(NO3)2 + H2O + SO2 =>
CuS + 4 HNO3 = 2 NO + Cu(NO3)2 + 2 H2O + SO2
CaH4P2O8 + NaHCO3 = CaHCO3 + NaH4P2O8 =>
CaH4P2O8 + NaHCO3 = CaHCO3 + NaH4P2O8
B(OH)3 + KOH = KBO2 + H2O =>
B(OH)3 + KOH = KBO2 + 2 H2O
Cr(OH)3 + O2 + KOH = K2CrO4 + H2O =>
4 Cr(OH)3 + 3 O2 + 8 KOH = 4 K2CrO4 + 10 H2O
H2S + KCIO = SO2 + KCI + H2O =>
H2S + 3 KCIO = SO2 + 3 KCI + H2O
CH3CHOHCH2 + OH = CO + H2O =>
CH3CHOHCH2 + 11 OH = 3 CO + 9 H2O
C2H4 + P2O3 = P + CO2 + H2O =>
C2H4 + 2 P2O3 = 4 P + 2 CO2 + 2 H2O
KH4F2 = KF + H2 + F2 =>
2 KH4F2 = 2 KF + 4 H2 + F2
CaH4P2O8 + NaHCO3 = CaHCO3 + NaH4P2O8 =>
CaH4P2O8 + NaHCO3 = CaHCO3 + NaH4P2O8
CH3CH2COH + K2CrO7 + H2SO4 = CH3CH2COOH + K2SO4 + H2O + Cr2(SO4)3 =>
9 CH3CH2COH + 2 K2CrO7 + 5 H2SO4 = 9 CH3CH2COOH + 2 K2SO4 + 5 H2O + Cr2(SO4)3
DI + H2O = HDI + OH =>
DI + H2O = HDI + OH
(Cu(NO3)2*3H2O)10 + (Cr(NO3)2*9H2O)10 + (C6H8O7)10 + (Ni(NO3)2*H2O)10 = Cu8Ni2Cr20O40 + N2O + H20O10 + C10O20 =>
36(Cu(NO3)2*3H2O)10 + 90(Cr(NO3)2*9H2O)10 + 55(C6H8O7)10 + 9(Ni(NO3)2*H2O)10 = 45 Cu8Ni2Cr20O40 + 1350 N2O + 1147 H20O10 + 330 C10O20
NaOH + Pb(NO3)2 = NaNO3 + Pb(OH)2 =>
2 NaOH + Pb(NO3)2 = 2 NaNO3 + Pb(OH)2
| 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 |
| Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/20/24
Equations balanced on 03/21/23
Please let us know how we can improve this web app.
