Equations balanced on the previous day | Equations balanced on the next day |
2 NaF + Ba(NO3)2 = BaF2 + 2 Na(NO3)
K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O
KMnO4 + NaI + H2SO4 = I2 + MnSO4 + K2SO4 + H2O + Na2SO4 =>
2 KMnO4 + 10 NaI + 8 H2SO4 = 5 I2 + 2 MnSO4 + K2SO4 + 8 H2O + 5 Na2SO4
C3H6 + KMnO4 + H2SO4 = CH3COOH + K2SO4 + MnSO4 + H2O =>
10 C3H6 + 12 KMnO4 + 18 H2SO4 = 15 CH3COOH + 6 K2SO4 + 12 MnSO4 + 18 H2O
NaOH(s) = Na2O(s) + H2O(l) =>
2 NaOH(s) = Na2O(s) + H2O(l)
Na3Po4 + MgCl2 = NaCl + Mg3(Po4)2 =>
2 Na3Po4 + 3 MgCl2 = 6 NaCl + Mg3(Po4)2
HBr + K2CO3 = HCO3 + K2Br =>
HBr + K2CO3 = HCO3 + K2Br
N2H4 + F2 = NF3 + H2 =>
N2H4 + 3 F2 = 2 NF3 + 2 H2
Cr + H2SO4 = Cr2(SO4)3 + SO2 + H2O =>
2 Cr + 6 H2SO4 = Cr2(SO4)3 + 3 SO2 + 6 H2O
SiO2 + NaOH = SiO3 + Na2O + H2 =>
SiO2 + 2 NaOH = SiO3 + Na2O + H2
CI2 + H2 = HCI2 =>
2 CI2 + H2 = 2 HCI2
AgNO3 + Na2SO3 = Ag2SO3 + NaNO3 =>
2 AgNO3 + Na2SO3 = Ag2SO3 + 2 NaNO3
C7H5N3O6(s) = CO(g) + H2O(l) + N2(g) + C(s) =>
2 C7H5N3O6(s) = 7 CO(g) + 5 H2O(l) + 3 N2(g) + 7 C(s)
N2H4O3 = N2O + H2O =>
N2H4O3 = N2O + 2 H2O
NiCl + NaOH = Ni(OH) + NaCl =>
NiCl + NaOH = Ni(OH) + NaCl
Ca(OH)2(aq) + Al2(SO4)3 = Al(OH)3 + CaSO4(s) =>
3 Ca(OH)2(aq) + Al2(SO4)3 = 2 Al(OH)3 + 3 CaSO4(s)
NOXOH = HNOXO =>
NOXOH = HNOXO
H3PO4(aq) + OH(aq) = H2PO4(aq) + H2O(l) =>
H3PO4(aq) + OH(aq) = H2PO4(aq) + H2O(l)
Li + S = Li2S =>
2 Li + S = Li2S
NH3 + SO3 = (NH4)2SO3 + N2H2 =>
6 NH3 + 2 SO3 = 2(NH4)2SO3 + N2H2
C2H3O2 + H2O = C2H2O2 + H3O =>
C2H3O2 + H2O = C2H2O2 + H3O
CoCl2 + HCl = CoCl3 + H2 =>
2 CoCl2 + 2 HCl = 2 CoCl3 + H2
FeS + HNO3 = Fe(NO3)3 + H2SO4 + NO2 + H2O =>
FeS + 12 HNO3 = Fe(NO3)3 + H2SO4 + 9 NO2 + 5 H2O
(FeSO4) + Cu = CuSO4 + Fe =>
(FeSO4) + Cu = CuSO4 + Fe
HNO2(aq) + Ba(OH)2(aq) = Ba(NO2)2(aq) + H2O =>
2 HNO2(aq) + Ba(OH)2(aq) = Ba(NO2)2(aq) + 2 H2O
Cu + HBr = CuBr2 + H2 =>
Cu + 2 HBr = CuBr2 + H2
Au + HNO3 + HCl = AuCl3 + NO + H2O =>
Au + HNO3 + 3 HCl = AuCl3 + NO + 2 H2O
BaCl2 + CoCl2 = BaCo + Cl2 =>
BaCl2 + CoCl2 = BaCo + 2 Cl2
KCl + NaClO4 = KClO4 + NaCl =>
KCl + NaClO4 = KClO4 + NaCl
C6H5COOH + NaHCO3 = C6H5COONa + H2O + CO3 =>
21 C6H5COOH + 22 NaHCO3 = 22 C6H5COONa + 19 H2O + 15 CO3
Cr + ZnSO4 = Cr(SO4)3 + Zn =>
Cr + 3 ZnSO4 = Cr(SO4)3 + 3 Zn
C2H4 + KMnO4 = MnO2 + KOH + C2O4K2 + H2O =>
3 C2H4 + 10 KMnO4 = 10 MnO2 + 4 KOH + 3 C2O4K2 + 4 H2O
KH2O = HKOH =>
KH2O = HKOH
KCH3 + COO = KCH3COO =>
KCH3 + COO = KCH3COO
SN + HNO3 = SNO2 + NO2 + H2O =>
SN + 4 HNO3 = SNO2 + 4 NO2 + 2 H2O
HNO3(aq) + Na2SO3(aq) = NaNO3(aq) + H2SO3 =>
2 HNO3(aq) + Na2SO3(aq) = 2 NaNO3(aq) + H2SO3
C2H26 + O2 = CO2 + H2O =>
2 C2H26 + 17 O2 = 4 CO2 + 26 H2O
Fe[Fe(SCN)6] + NaF + NH4NO3 = NaNO3 + Fe(FeF6) + NH4SCN =>
Fe[Fe(SCN)6] + 6 NaF + 6 NH4NO3 = 6 NaNO3 + Fe(FeF6) + 6 NH4SCN
[Fe(H2O)6]{2+} + NO3{-} + H{+} = [Fe(H2O)6]{3+} + NO + H2O =>
3[Fe(H2O)6]{2+} + NO3{-} + 4 H{+} = 3[Fe(H2O)6]{3+} + NO + 2 H2O
K2CO3 + Fe(NO3)2 = KNO3 + Fe2(CO3)2 =>
2 K2CO3 + 2 Fe(NO3)2 = 4 KNO3 + Fe2(CO3)2
C8H18 + O = CO2 + H2O =>
C8H18 + 25 O = 8 CO2 + 9 H2O
Al(C2H3O2)3 + (NH4)3PO4 = AlPO4 + NH4C2H3O2 =>
Al(C2H3O2)3 + (NH4)3PO4 = AlPO4 + 3 NH4C2H3O2
CH2COH2O = CH3COOH =>
CH2COH2O = CH3COOH
Na + Cl2 = NaCl =>
2 Na + Cl2 = 2 NaCl
Cu + MgSO4 + H2O = H2 + CuSO4 + Mg(OH)2 =>
Cu + MgSO4 + 2 H2O = H2 + CuSO4 + Mg(OH)2
Zn + As = Zn3As2 =>
3 Zn + 2 As = Zn3As2
H2O = H2 + O2 =>
2 H2O = 2 H2 + O2
Ca + NiS = CaSNi =>
Ca + NiS = CaSNi
CrO5 + H2SO4 + KI = I2 + Cr(SO4)3 + K2SO4 + H2O =>
CrO5 + 5 H2SO4 + 4 KI = 2 I2 + Cr(SO4)3 + 2 K2SO4 + 5 H2O
Mg + C = Mg4C2 =>
4 Mg + 2 C = Mg4C2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 |
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/04/24
Equations balanced on 03/05/23
Please let us know how we can improve this web app.