Equations balanced on the previous day | Equations balanced on the next day |
2 AgNO3 + H2S = Ag2S + 2 HNO3
P2H4 = PH3 + P4H2 =>
5 P2H4 = 6 PH3 + P4H2
Cu(s) + L(aq) = CuL(aq) =>
Cu(s) + L(aq) = CuL(aq)
NH4Cl(s) + NaOH(s) = NH3 + H2O + NaCl(s) =>
NH4Cl(s) + NaOH(s) = NH3 + H2O + NaCl(s)
Pb{2+} + SiO3{2-} = PbSiO3 =>
Pb{2+} + SiO3{2-} = PbSiO3
P(Br)3 + H2O = HBr + H3PO3 =>
P(Br)3 + 3 H2O = 3 HBr + H3PO3
Mn{+2} + Co{+3} + H2O = MnO2 + Co{2+} + H{+} =>
Mn{+2} + 2 Co{+3} + 2 H2O = MnO2 + 2 Co{2+} + 4 H{+}
CuOH + HNO3 = CuNO3 + H2O =>
CuOH + HNO3 = CuNO3 + H2O
C2H3Cl3 + HO = CO2 + H2O + Cl2 =>
2 C2H3Cl3 + 22 HO = 4 CO2 + 14 H2O + 3 Cl2
Cr + H2SO4 = Cr2(SO4)3 + SO2 + H2O =>
2 Cr + 6 H2SO4 = Cr2(SO4)3 + 3 SO2 + 6 H2O
H2SO4 + Al(OH)3 = H2O + Al2(SO4)3 =>
3 H2SO4 + 2 Al(OH)3 = 6 H2O + Al2(SO4)3
N2 + O2 + H2O = NO2{-} + H{+} =>
2 N2 + 3 O2 + 2 H2O = 4 NO2{-} + 4 H{+}
K3Fe(CN)6 + Cr2O4 + KOH = K4Fe(CN)6 + K2CrO4 + H2O =>
4 K3Fe(CN)6 + Cr2O4 + 8 KOH = 4 K4Fe(CN)6 + 2 K2CrO4 + 4 H2O
NH3 + H2SO4 = SO4 + H(NH3) =>
2 NH3 + H2SO4 = SO4 + 2 H(NH3)
MnO4{-} + I{-} + H2O = MnO2 + I2 + OH{-} =>
2 MnO4{-} + 6 I{-} + 4 H2O = 2 MnO2 + 3 I2 + 8 OH{-}
CuOH + HNO3 = CuNO3 + H2O =>
CuOH + HNO3 = CuNO3 + H2O
KDO3 = KD + O2 =>
2 KDO3 = 2 KD + 3 O2
C3H8 + O2 = CO2 + H1 =>
C3H8 + 3 O2 = 3 CO2 + 8 H1
Co2S3 + HNO3 = Co + H2S + NO3 =>
Co2S3 + 6 HNO3 = 2 Co + 3 H2S + 6 NO3
CaC2 + H2O = CO2 + Ca(OH)2 + H2 =>
CaC2 + 6 H2O = 2 CO2 + Ca(OH)2 + 5 H2
Na2S2O3 + ClO2 = NaCl + NaS2O5 =>
Na2S2O3 + ClO2 = NaCl + NaS2O5
K2S2O4 + KMnO4 = K2SO4 + MnO2 =>
K2S2O4 + 2 KMnO4 = 2 K2SO4 + 2 MnO2
CH3CH2CHO + O2 = CO2 + H2O =>
CH3CH2CHO + 4 O2 = 3 CO2 + 3 H2O
CrS3 + Mn(NO3)2 + NaCO3 = NaCrO4 + NO + Na2MnO4 + Na2SO4 + CO2 =>
2 CrS3 + 9 Mn(NO3)2 + 32 NaCO3 = 2 NaCrO4 + 18 NO + 9 Na2MnO4 + 6 Na2SO4 + 32 CO2
C2H5OH + Cr2O7{2-} + H{+} = CH3COH + Cr3{+} + H2O =>
17 C2H5OH + 3 Cr2O7{2-} + 8 H{+} = 17 CH3COH + 2 Cr3{+} + 21 H2O
N3PO4 + CoCl3 = CoPO4 + NCl =>
N3PO4 + CoCl3 = CoPO4 + 3 NCl
NH4NO2 + LiOH = LiNO3 + NH3 + H2O =>
4 NH4NO2 + 3 LiOH = 3 LiNO3 + 5 NH3 + 2 H2O
HO* + SO2 = H2SO4 =>
2 HO* + SO2 = H2SO4
C2H3Cl3 + HO = CO2 + H2O + Cl2 =>
2 C2H3Cl3 + 22 HO = 4 CO2 + 14 H2O + 3 Cl2
Al2O3 + Na2SO3 = Al2(SO3)3 + Na2O =>
Al2O3 + 3 Na2SO3 = Al2(SO3)3 + 3 Na2O
H2O + KNO2 = KOH + HNO2 =>
H2O + KNO2 = KOH + HNO2
Pb(NO3)2(aq) + FeCl3(aq) = PbCl2(s) + Fe(NO3)3(aq) =>
3 Pb(NO3)2(aq) + 2 FeCl3(aq) = 3 PbCl2(s) + 2 Fe(NO3)3(aq)
K3(PO4) + Ag(NO3) = Ag3(PO4) + K(NO3) =>
K3(PO4) + 3 Ag(NO3) = Ag3(PO4) + 3 K(NO3)
C2H3Cl3 + HO = CO2 + H2O + Cl2 =>
2 C2H3Cl3 + 22 HO = 4 CO2 + 14 H2O + 3 Cl2
(NH4)2O = NH4 + O2 =>
2(NH4)2O = 4 NH4 + O2
Ca(NO3)2 + H2O = Ca(OH)2 + HNO3 =>
Ca(NO3)2 + 2 H2O = Ca(OH)2 + 2 HNO3
Pb(NO3)2 + H2O = NO3 + PbO + H =>
Pb(NO3)2 + H2O = 2 NO3 + PbO + 2 H
C2H3Cl3 + HO = CO2 + H2O + Cl2 =>
2 C2H3Cl3 + 22 HO = 4 CO2 + 14 H2O + 3 Cl2
CrO7{-2} + MnO4{-} + CH3OH = Cr2O3 + MnO4{-2} + CHHO + H2O =>
2 CrO7{-2} + 4 MnO4{-} + 11 CH3OH = Cr2O3 + 4 MnO4{-2} + 11 CHHO + 11 H2O
Al2O3 + NaOH = Na3AlO3 + H2O =>
Al2O3 + 6 NaOH = 2 Na3AlO3 + 3 H2O
C2H3Cl3 + HO = CO2 + H2O + Cl2 =>
2 C2H3Cl3 + 22 HO = 4 CO2 + 14 H2O + 3 Cl2
CaF2 + AlH3 = AlF3 + CaH2 =>
3 CaF2 + 2 AlH3 = 2 AlF3 + 3 CaH2
Cu + SnCl2 = CuCl + Sn =>
2 Cu + SnCl2 = 2 CuCl + Sn
AgF + HCl = AgCl + HF =>
AgF + HCl = AgCl + HF
Ba(NO3)NaSO4 = Na(NO3)BaSO4 =>
Ba(NO3)NaSO4 = Na(NO3)BaSO4
AlSO4 + Ba(Cl)2 = Al(Cl)3 + (Ba)3(SO4)2 =>
2 AlSO4 + 3 Ba(Cl)2 = 2 Al(Cl)3 + (Ba)3(SO4)2
Be + H2SO4 = BeSO4 + H2S + H2O =>
4 Be + 5 H2SO4 = 4 BeSO4 + H2S + 4 H2O
MnO2 + BeCl2 = MnCl4 + BeO =>
MnO2 + 2 BeCl2 = MnCl4 + 2 BeO
Cu + SnCl2 = CuCl2 + Sn =>
Cu + SnCl2 = CuCl2 + Sn
HCl + (OH)3 = HOH + Cl3 =>
3 HCl + (OH)3 = 3 HOH + Cl3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 |
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/20/23
Equations balanced on 12/20/22
Please let us know how we can improve this web app.