Printed from https://www.webqc.org

Chemical Equations Balanced on 12/06/17

 Equations balanced on the previous day Equations balanced on the next day
Balance the equation of any chemical reaction
Fe(OH)3 = Fe2O3 + H2O =>
2 Fe(OH)3 = Fe2O3 + 3 H2O

Al + NaOH + H2O = Na[Al(OH)4] + H2 =>
2 Al + 2 NaOH + 6 H2O = 2 Na[Al(OH)4] + 3 H2

S2{-} + OH{-} = SO4 + H2O + e =>
S2{-} + 16 OH{-} = 2 SO4 + 8 H2O + 17e

CaCO3 + H2O + CO2 = Ca(HCO3)2 =>
CaCO3 + H2O + CO2 = Ca(HCO3)2

Fe + S = FeS =>
Fe + S = FeS

CH2{-}CH2 + KMnO4 + H2O = CH2OH{-}CH2OH + MnO2 + KOH =>
3 CH2{-}CH2 + KMnO4 + 2 H2O = 3 CH2OH{-}CH2OH + MnO2 + KOH

Cu + HCl = CuCl + H =>
Cu + HCl = CuCl + H

HNO3 + NAOH = NANO3 + H2O =>
HNO3 + NAOH = NANO3 + H2O

Zn + Sn{2+} = Sn + Zn{2+} =>
Zn + Sn{2+} = Sn + Zn{2+}

Fe + H2SO4 = Fe(SO4) + H2 =>
Fe + H2SO4 = Fe(SO4) + H2

Na + Br2 = NaBr =>
2 Na + Br2 = 2 NaBr

Zn + CuSO4 = ZnSO4 + Cu =>
Zn + CuSO4 = ZnSO4 + Cu

CH3CHOHCH3 + HCl + ZnCl2 = CH3CH2CH2ClCl2 + Zn + H2O =>
CH3CHOHCH3 + HCl + ZnCl2 = CH3CH2CH2ClCl2 + Zn + H2O

S2{-} + OH{-} = SO42{-} + H2O + e =>
S2{-} + 168 OH{-} = 2 SO42{-} + 84 H2O + 167e

CH3COOH + H2O = CH3COO + H3O =>
CH3COOH + H2O = CH3COO + H3O

Rb + Cl2 = RbCl =>
2 Rb + Cl2 = 2 RbCl

HCl + NaOH = NaCl + H2O =>
HCl + NaOH = NaCl + H2O

SO3 + H2O = H2SO4 =>
SO3 + H2O = H2SO4

S2{-} + OH{-} = SO2{-} + H2O + e =>
S2{-} + 8 OH{-} = 2 SO2{-} + 4 H2O + 7e

KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2

CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O

Al + CUSO4 = Al(SO4)3 + CU =>
Al + 3 CUSO4 = Al(SO4)3 + 3 CU

KMnO4 + FeSO3 + H2SO4 = MnSO4 + Fe2(SO4)3 + K2SO4 + H2O =>
6 KMnO4 + 10 FeSO3 + 14 H2SO4 = 6 MnSO4 + 5 Fe2(SO4)3 + 3 K2SO4 + 14 H2O

Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 H2O

CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O

NO + O2 = NO2 =>
2 NO + O2 = 2 NO2

Cu + HNO3 = Cu(NO3)2 + H2O + NO =>
3 Cu + 8 HNO3 = 3 Cu(NO3)2 + 4 H2O + 2 NO

Na + O2 = Na2O =>
4 Na + O2 = 2 Na2O

CH2{-}CH2 + KMnO4 + H2O = CH2OH{-}CH2OH + MnO2 + KOH =>
3 CH2{-}CH2 + KMnO4 + 2 H2O = 3 CH2OH{-}CH2OH + MnO2 + KOH

C6H12O6 + O2 = CO2 + H2O =>
C6H12O6 + 6 O2 = 6 CO2 + 6 H2O

Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3

KHCO3 + H2O = KOH + H2CO3 =>
KHCO3 + H2O = KOH + H2CO3

HClO4 + KOH = KClO4 + H2O =>
HClO4 + KOH = KClO4 + H2O

NaOH + H2SO4 = Na2SO4 + H2O =>
2 NaOH + H2SO4 = Na2SO4 + 2 H2O

P4 + NaOH + H2O = NaH2PO2 + PH3 =>
P4 + 3 NaOH + 3 H2O = 3 NaH2PO2 + PH3

Fe(OH)3 = Fe2O3 + H2O =>
2 Fe(OH)3 = Fe2O3 + 3 H2O

Pb + Sn + Ta + Se = Pb80Sn20Ta100Se200 =>
80 Pb + 20 Sn + 100 Ta + 200 Se = Pb80Sn20Ta100Se200

K2Cr2O7 + H2SO3 + HClO4 = HSO3 + Cr(ClO4)3 + KClO4 + H2O =>
K2Cr2O7 + 6 H2SO3 + 8 HClO4 = 6 HSO3 + 2 Cr(ClO4)3 + 2 KClO4 + 7 H2O

NaCl2 + AgNo3 = AgCl2 + NaNo3 =>
NaCl2 + AgNo3 = AgCl2 + NaNo3

SnO2 + H2 = Sn + H2O =>
SnO2 + 2 H2 = Sn + 2 H2O

S2{-} + OH{-} = SO4{-} + H2O + e =>
S2{-} + 16 OH{-} = 2 SO4{-} + 8 H2O + 15e

Pb + Sn + Ta + Se = Pb75Sn25Ta100Se200 =>
75 Pb + 25 Sn + 100 Ta + 200 Se = Pb75Sn25Ta100Se200

C6H6 + O2 = CO2 + H2O =>
2 C6H6 + 15 O2 = 12 CO2 + 6 H2O

Pb + Sn + Ta + Se = Pb70Sn30Ta100Se200 =>
70 Pb + 30 Sn + 100 Ta + 200 Se = Pb70Sn30Ta100Se200

HF(aq) + LiOH(aq) = H2O + LiF =>
HF(aq) + LiOH(aq) = H2O + LiF

S2{-} + OH{-} = SO4{-} + H2O + e =>
S2{-} + 16 OH{-} = 2 SO4{-} + 8 H2O + 15e

P + KOH + H2O = PH3 + KH2PO2 =>
4 P + 3 KOH + 3 H2O = PH3 + 3 KH2PO2

K2Cr2O7 + NaI + H2SO4 = Cr2(SO4)3 + I2 + Na2SO4 + K2SO4 + H2O =>
K2Cr2O7 + 6 NaI + 7 H2SO4 = Cr2(SO4)3 + 3 I2 + 3 Na2SO4 + K2SO4 + 7 H2O

S2{-} + OH{-} = SO2{-} + H2O + e =>
S2{-} + 8 OH{-} = 2 SO2{-} + 4 H2O + 7e

C + H2SO4 = SO2 + CO2 + H2O =>
C + 2 H2SO4 = 2 SO2 + CO2 + 2 H2O

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
Balance the equation of any chemical reaction
 Equations balanced on the previous day Equations balanced on the next day
Equations balanced on 11/29/17
Equations balanced on 11/06/17
Equations balanced on 12/06/16
Please let us know how we can improve this web app.
Menu Balance Molar mass Gas laws Units Chemistry tools Periodic table Chemical forum Symmetry Constants Contribute Contact us
How to cite?