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Chemical Equations Balanced on 04/15/25

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Balance the equation of any chemical reaction
Ag + Ca(Br)2 = Ca + Ag(Br)2 =>
Ag + Ca(Br)2 = Ca + Ag(Br)2

C2H2 + [Cu(NH3)2]OH = C2HCu + NH3 + H2O =>
C2H2 + [Cu(NH3)2]OH = C2HCu + 2 NH3 + H2O

AgCl + (NH4)2S + H2O = Ag + NH4Cl + H2S + O2 =>
4 AgCl + 2(NH4)2S + 2 H2O = 4 Ag + 4 NH4Cl + 2 H2S + O2

(NH4)3PO4(aq) + CaBr2(aq) = Ca3(PO4)2(s) + NH4Br =>
2(NH4)3PO4(aq) + 3 CaBr2(aq) = Ca3(PO4)2(s) + 6 NH4Br

C4H10 + Cl = HCl + C4H9 =>
C4H10 + Cl = HCl + C4H9

Br + FeCl2 = Cl2 + FeBr2 =>
2 Br + FeCl2 = Cl2 + FeBr2

AntimonicPhosphite + AmmoniumSulfate = AmmoniumPhosphite + AntimonicSulfate =>
AntimonicPhosphite + AmmoniumSulfate = AmmoniumPhosphite + AntimonicSulfate

NH4HCO3 + Ba(OH)2 = BaCO3 + (NH4)2CO3 + H2O =>
2 NH4HCO3 + Ba(OH)2 = BaCO3 + (NH4)2CO3 + 2 H2O

C9H20O + H2SO4 + Na2Cr2O7 = C9H18O + Na2SO4 + Cr2(SO4)3 + H2O =>
3 C9H20O + 4 H2SO4 + Na2Cr2O7 = 3 C9H18O + Na2SO4 + Cr2(SO4)3 + 7 H2O

Mg + CuCl = Mg2Cl3 + Cu =>
2 Mg + 3 CuCl = Mg2Cl3 + 3 Cu

CH4 + NH3 + O2 = H2O + C3H7O2N =>
3 CH4 + NH3 + 3 O2 = 4 H2O + C3H7O2N

HgO{+2} = Hg{+2} + O2 =>
2 HgO{+2} = 2 Hg{+2} + O2

Al + H2SO4 = H2O + AlSO2 + O =>
Al + H2SO4 = H2O + AlSO2 + O

K3[Cr(OH)6] + CO2 = Cr(OH)3 + K2CO3 + H2O =>
2 K3[Cr(OH)6] + 3 CO2 = 2 Cr(OH)3 + 3 K2CO3 + 3 H2O

CH3CH2OH + K2CrO7 + H2SO4 = CH3CH2CHO + K2SO4 + Cr2(SO4)3 + H2O =>
27 CH3CH2OH + 4 K2CrO7 + 10 H2SO4 = 18 CH3CH2CHO + 4 K2SO4 + 2 Cr2(SO4)3 + 37 H2O

Rb(OH) + H(CH3CO2) = RbCH3CO2 + H2O =>
Rb(OH) + H(CH3CO2) = RbCH3CO2 + H2O

NaI + HNO3 = NaNO3 + NaNO2 + I2 + H2O =>
2 NaI + 2 HNO3 = NaNO3 + NaNO2 + I2 + H2O

Sn(ClO3)4 + Cd = Cd(ClO3)2 + Sn =>
Sn(ClO3)4 + 2 Cd = 2 Cd(ClO3)2 + Sn

C6H6 + Cl = C6H4Cl2 + HCl =>
C6H6 + 4 Cl = C6H4Cl2 + 2 HCl

Fe(s) + HCl(aq) = FeCl2(g) + H2(g) =>
Fe(s) + 2 HCl(aq) = FeCl2(g) + H2(g)

HI + CsOH = H2O + ICs =>
HI + CsOH = H2O + ICs

CO3 + HCl = CO2 + H2O + Cl =>
CO3 + 2 HCl = CO2 + H2O + 2 Cl

Cu(NO3)2 + KI = CuI + I2 + KNO3 =>
2 Cu(NO3)2 + 4 KI = 2 CuI + I2 + 4 KNO3

CH4 + I = CH3 + HI =>
CH4 + I = CH3 + HI

P4O10 + FeO = FeP4O11 =>
P4O10 + FeO = FeP4O11

Al + KNO2 + KOH + H2O = K(Al(OH)4) + NH4OH =>
2 Al + KNO2 + KOH + 6 H2O = 2 K(Al(OH)4) + NH4OH

(C2H5)3N + H2O = (C2H6)3N + OH =>
(C2H5)3N + 3 H2O = (C2H6)3N + 3 OH

CH4(g) + Cl2(g) = CHCl3(l) + HCl(g) =>
CH4(g) + 3 Cl2(g) = CHCl3(l) + 3 HCl(g)

CoOC = COCo =>
CoOC = COCo

Mg + CuCl2 = MgCl12 + Cu =>
Mg + 6 CuCl2 = MgCl12 + 6 Cu

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

Al + H2SO4 = H2S + AlSO4 + H2O =>
4 Al + 5 H2SO4 = H2S + 4 AlSO4 + 4 H2O

Dy + H2O = Dy(OH) + H2 =>
2 Dy + 2 H2O = 2 Dy(OH) + H2

K3(Fe(CN)6) + HgCl2 = K3(Hg(CN)6) + FeCl2 =>
K3(Fe(CN)6) + HgCl2 = K3(Hg(CN)6) + FeCl2

(AuXe4)3(Fe(CN)6)2 + H2O = Au{3+} + Xe + Fe{3+} + CO2 + NO3{-} + H{+} + e =>
(AuXe4)3(Fe(CN)6)2 + 60 H2O = 3 Au{3+} + 12 Xe + 2 Fe{3+} + 12 CO2 + 12 NO3{-} + 120 H{+} + 123e

Ni(OH)2 + HSO4 = Ni(SO4)2 + H2O =>
Ni(OH)2 + 2 HSO4 = Ni(SO4)2 + 2 H2O

Ba + HPO4 = BaPO4 + H2 =>
2 Ba + 2 HPO4 = 2 BaPO4 + H2

(NH4)3PO4 + Ba(CH3CO2)2 = NH4CH3CO2 + Ba3(PO4)2 =>
2(NH4)3PO4 + 3 Ba(CH3CO2)2 = 6 NH4CH3CO2 + Ba3(PO4)2

NiO + Ni = Ni2O =>
NiO + Ni = Ni2O

Al2(CO3)3 + HCH3COO = H2CO3 + Al(CH3COO)3 =>
Al2(CO3)3 + 6 HCH3COO = 3 H2CO3 + 2 Al(CH3COO)3

NO2 + CO = NO + CO2 =>
NO2 + CO = NO + CO2

K3PO4 + Ba(NO3)2 = K3(NO3)2 + BaPO4 =>
K3PO4 + Ba(NO3)2 = K3(NO3)2 + BaPO4

Ca(OH)2 + H3PO4 = CaHPO4 + H2O =>
Ca(OH)2 + H3PO4 = CaHPO4 + 2 H2O

I + Cl2 + H2O = IO3{-} + Cl{-} + H{+} =>
2 I + 5 Cl2 + 6 H2O = 2 IO3{-} + 10 Cl{-} + 12 H{+}

KCN + O2 + H2O + Au = KAu(CN)2 + KOH =>
8 KCN + O2 + 2 H2O + 4 Au = 4 KAu(CN)2 + 4 KOH

HNO3 + CuS + HCl = CuCl + S + H2O + NO =>
HNO3 + 3 CuS + 3 HCl = 3 CuCl + 3 S + 2 H2O + NO

KClO3 + FeSO4 + H2SO4 = Fe2(SO4)3 + Cl2 + K2SO4 + H2O =>
2 KClO3 + 10 FeSO4 + 6 H2SO4 = 5 Fe2(SO4)3 + Cl2 + K2SO4 + 6 H2O

Zn + K3Fe(CN)6 = K3Zn(CN)6 + Fe =>
Zn + K3Fe(CN)6 = K3Zn(CN)6 + Fe

CoBr2 + Fe2(SO3)3 = Co3(SO3)3 + FeBr3 =>
3 CoBr2 + Fe2(SO3)3 = Co3(SO3)3 + 2 FeBr3

IrCl3 + SnCl2 = Ir + SnCl4 =>
2 IrCl3 + 3 SnCl2 = 2 Ir + 3 SnCl4

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Balance the equation of any chemical reaction
 Equations balanced on the previous day Equations balanced on the next day
Equations balanced on 04/08/25
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Equations balanced on 04/15/24
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