| Equations balanced on the previous day | Equations balanced on the next day |
Al{+3] = Al{+3}
NH2CH2COOH + KNO3 = (NH2CH2COOH)KNO3 =>
NH2CH2COOH + KNO3 = (NH2CH2COOH)KNO3
CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O
Cr(OH)3 + HBr = Cr(Br)3 + HOH =>
Cr(OH)3 + 3 HBr = Cr(Br)3 + 3 HOH
Na2SO4 + NH4NO3 = Na2(NO3)2 + SO4(NH4)2 =>
Na2SO4 + 2 NH4NO3 = Na2(NO3)2 + SO4(NH4)2
CH3CHO + CH3MgCl = CH3CH2CH2OMgCl =>
CH3CHO + CH3MgCl = CH3CH2CH2OMgCl
HC1 + Na2S2O3 = S + SO2 + NaC1 + H2O =>
2 HC1 + Na2S2O3 = S + SO2 + 2 NaC1 + H2O
Al2O3 + BaO = Al2Ba + O =>
Al2O3 + BaO = Al2Ba + 4 O
Ca(OH)2 + KCn = CaCn2 + KOH =>
Ca(OH)2 + 2 KCn = CaCn2 + 2 KOH
Na + NaNO3 = Na2O + N2 =>
10 Na + 2 NaNO3 = 6 Na2O + N2
MnSO4 + KClO4 + KOH = K2MnO4 + KCl + K2SO4 + H2O =>
2 MnSO4 + KClO4 + 8 KOH = 2 K2MnO4 + KCl + 2 K2SO4 + 4 H2O
BaO + Mg = BaMg + O =>
BaO + Mg = BaMg + O
Ca(OH)2(aq) + H3Po4(aq) = Ca3(Po4)2(ppt) + H2O(l) =>
3 Ca(OH)2(aq) + 2 H3Po4(aq) = Ca3(Po4)2(ppt) + 6 H2O(l)
C4H8N2O3 + O = CO2 + H2O + CH4N2O =>
C4H8N2O3 + 6 O = 3 CO2 + 2 H2O + CH4N2O
Fe{2+} + H3O{-} + MnO4{-} = Fe{2-} + H2O + Mn{3+} =>
3 Fe{2+} + 8 H3O{-} + MnO4{-} = 3 Fe{2-} + 12 H2O + Mn{3+}
V3(PO4)5 + Ca = Ca3(PO4)2 + V =>
2 V3(PO4)5 + 15 Ca = 5 Ca3(PO4)2 + 6 V
Zn + CaNO3 + H2O = NH3 + Ca(OH)2 + Zn(OH)2 =>
7 Zn + 2 CaNO3 + 12 H2O = 2 NH3 + 2 Ca(OH)2 + 7 Zn(OH)2
(NH4)3 + PO4 + Ba(OH)2 = Ba3(PO4)2 + NH4OH =>
2(NH4)3 + 2 PO4 + 3 Ba(OH)2 = Ba3(PO4)2 + 6 NH4OH
Mg(HCO3)2(ag) = MgO(s) + H2O(l) + CO2(g) =>
Mg(HCO3)2(ag) = MgO(s) + H2O(l) + 2 CO2(g)
(NH4)2(C2O4) + Al(ClO4)3 = NH4ClO4 + Al2(C2O4)3 =>
3(NH4)2(C2O4) + 2 Al(ClO4)3 = 6 NH4ClO4 + Al2(C2O4)3
CaO + MnI4 = MnO2 + CaI2 =>
2 CaO + MnI4 = MnO2 + 2 CaI2
NaOCl + SO2 + H2O = H2SO4 + NaCl =>
NaOCl + SO2 + H2O = H2SO4 + NaCl
HClO3 + MnCO3 = MnO2 + CO2 + HCl =>
HClO3 + 3 MnCO3 = 3 MnO2 + 3 CO2 + HCl
Al + Pb(NO)2 = Al(NO) + Pb =>
2 Al + Pb(NO)2 = 2 Al(NO) + Pb
C6H4COOCH3NO2 + NaOH = NaNO3 + C6H5COOCH3 =>
C6H4COOCH3NO2 + NaOH = NaNO3 + C6H5COOCH3
K2Cr2O7 + HI + H2SO4 = Cr2S3O12 + I2 + K2SO4 + H2O =>
K2Cr2O7 + 6 HI + 4 H2SO4 = Cr2S3O12 + 3 I2 + K2SO4 + 7 H2O
Na2SO3 + Cr2O7 = Na2SO4 + Cr =>
7 Na2SO3 + Cr2O7 = 7 Na2SO4 + 2 Cr
Cu(NO3)2 + NaCl = NaNO3 + CuCl2 =>
Cu(NO3)2 + 2 NaCl = 2 NaNO3 + CuCl2
(CH3)2CO + [Ag(NH3)2]OH = CH3COONH4 + Ag + NH3 + H2O =>
2(CH3)2CO + 8[Ag(NH3)2]OH = 3 CH3COONH4 + 8 Ag + 13 NH3 + 4 H2O
Hg(aq) + HCl(aq) = HgCl2(s) + H2(g) =>
Hg(aq) + 2 HCl(aq) = HgCl2(s) + H2(g)
NaNO2 + KI + H2SO4 = I2 + NO + Na2SO4 + K2SO4 + H2O =>
2 NaNO2 + 2 KI + 2 H2SO4 = I2 + 2 NO + Na2SO4 + K2SO4 + 2 H2O
Na2Co3 + Fe2(NO3)2 = Na2NO3 + Fe2(Co3)2 =>
2 Na2Co3 + Fe2(NO3)2 = 2 Na2NO3 + Fe2(Co3)2
CaMgO2 + H2O = Mg(OH)2 + Ca(OH)2 =>
CaMgO2 + 2 H2O = Mg(OH)2 + Ca(OH)2
Al(SO4)3 + Ag = Al + Ag(SO4)3 =>
Al(SO4)3 + Ag = Al + Ag(SO4)3
PCl5 + CH3COOH = CH3COCl + H3PO4 + HCl =>
PCl5 + 4 CH3COOH = 4 CH3COCl + H3PO4 + HCl
Ag(s) + S{2-}(aq) + O2(g) + H{+}(aq) = Ag2S(s) + H2O(l) =>
4 Ag(s) + 2 S{2-}(aq) + O2(g) + 4 H{+}(aq) = 2 Ag2S(s) + 2 H2O(l)
NH4Cl(s) = NH3(g) + HCl(g) =>
NH4Cl(s) = NH3(g) + HCl(g)
Cl2O + NH3 + H2 = NH4Cl + H2O =>
Cl2O + 2 NH3 + 2 H2 = 2 NH4Cl + H2O
XeF4 + H = Xe + HF4 =>
XeF4 + H = Xe + HF4
OF + NaOH = NaF + O2 + H2O =>
4 OF + 4 NaOH = 4 NaF + 3 O2 + 2 H2O
Na3PO4 + CuCl2 = NaCl + (PO4)2Cu3 =>
2 Na3PO4 + 3 CuCl2 = 6 NaCl + (PO4)2Cu3
BaCO3 + C + H2O = CO + BaOH2 =>
BaCO3 + 2 C + H2O = 3 CO + BaOH2
CeF3 + H2O = HF + CeOF =>
CeF3 + H2O = 2 HF + CeOF
Ni + C + O2 = Ni(CO)2 =>
Ni + 2 C + O2 = Ni(CO)2
H2 + Ca(CN)2 + NaAlF4 + FeSO4 + MgSiO3 + KI + H3PO4 + PbCrO4 + BrCl + CF2Cl2 + SO2 = MgCO3 + PbBr2 + CrCl3 + KAl(OH)4 + Fe(SCN)3 + PI3 + Na2SiO3 + CaF2 + H2O =>
88 H2 + 15 Ca(CN)2 + 6 NaAlF4 + 10 FeSO4 + 3 MgSiO3 + 6 KI + 2 H3PO4 + 6 PbCrO4 + 12 BrCl + 3 CF2Cl2 + 20 SO2 = 3 MgCO3 + 6 PbBr2 + 6 CrCl3 + 6 KAl(OH)4 + 10 Fe(SCN)3 + 2 PI3 + 3 Na2SiO3 + 15 CaF2 + 79 H2O
C6H8 + [O] = H2C2O4 + C2H4(COOH)2 =>
C6H8 + 8[O] = H2C2O4 + C2H4(COOH)2
Sr3N2 + CaO = SrO + Ca3N2 =>
Sr3N2 + 3 CaO = 3 SrO + Ca3N2
C5H10(g) + O2 = CO(g) + H2O(g) =>
C5H10(g) + 5 O2 = 5 CO(g) + 5 H2O(g)
(NH4)2SO4 + CaCl2 = (NH4)2Cl + Ca(SO4)2 =>
2(NH4)2SO4 + CaCl2 = 2(NH4)2Cl + Ca(SO4)2
HCl + BaCrO4 = BaCl + Cr2Cl3 + Cl2 + H2O =>
32 HCl + 4 BaCrO4 = 4 BaCl + 2 Cr2Cl3 + 11 Cl2 + 16 H2O
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| Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/20/25
Equations balanced on 03/22/24
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