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Chemical Equations Balanced on 03/19/25

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PHCH3 + KMnO4 + H2SO4 = H2O + PHCOOH + K2SO4 + MnSO4 =>
5 PHCH3 + 6 KMnO4 + 9 H2SO4 = 14 H2O + 5 PHCOOH + 3 K2SO4 + 6 MnSO4

C(CH2ONO2)4 + O2 = CO2 + N2 + H2O =>
C(CH2ONO2)4 + O2 = 5 CO2 + 2 N2 + 4 H2O

FeSO4(NH4)2SO4*6H2O + KMnO4 + H2SO4 = Fe2(SO4)3 + MnSO4 + (NH4)2SO4 + K2SO4 + H2O =>
10 FeSO4(NH4)2SO4*6H2O + 2 KMnO4 + 8 H2SO4 = 5 Fe2(SO4)3 + 2 MnSO4 + 10(NH4)2SO4 + K2SO4 + 68 H2O

MgSO4*7H2O + Na2CO3*10H2O = MgCO3 + Na2SO4*10H2O + H2O =>
MgSO4*7H2O + Na2CO3*10H2O = MgCO3 + Na2SO4*10H2O + 7 H2O

H2CO3(s) = H2O(l) + CO2(g) =>
H2CO3(s) = H2O(l) + CO2(g)

H2CrO4 + C2H5OH = Cr(OH)3 + CH3COOH + H2O =>
4 H2CrO4 + 3 C2H5OH = 4 Cr(OH)3 + 3 CH3COOH + H2O

KClO3 + NaI + HCl = KCl + I2 + NaCl + H2O =>
KClO3 + 6 NaI + 6 HCl = KCl + 3 I2 + 6 NaCl + 3 H2O

CH4 + CO2 = C2H2 + O2 =>
CH4 + 3 CO2 = 2 C2H2 + 3 O2

BaCO3 + SrCO3 + ZrO2 + TiO2 = Sr50Ba950Zr95Ti905O3000 + CO2 =>
950 BaCO3 + 50 SrCO3 + 95 ZrO2 + 905 TiO2 = Sr50Ba950Zr95Ti905O3000 + 1000 CO2

Bi2 + Se270 + S30 = Bi200Se270S30 =>
100 Bi2 + Se270 + S30 = Bi200Se270S30

Cd(OH)2 + HCl = Cd2(OH)Cl3 + H2O =>
2 Cd(OH)2 + 3 HCl = Cd2(OH)Cl3 + 3 H2O

Ag + HCl = AgCl + H2 =>
2 Ag + 2 HCl = 2 AgCl + H2

C6H6 + Br2 + Fe = C6H6Br2Fe =>
C6H6 + Br2 + Fe = C6H6Br2Fe

C10H22(l) + O2(g) = CO2(g) + H2O(g) =>
2 C10H22(l) + 31 O2(g) = 20 CO2(g) + 22 H2O(g)

Li2O + MnO2 = LiMn2O4 + O =>
Li2O + 4 MnO2 = 2 LiMn2O4 + O

Ba(NO3)2 + Mg(NO3)2 + Al(NO3)3 + NH2CONH2 = BaMgAl10O17 + CO2 + N2 + H2O =>
3 Ba(NO3)2 + 3 Mg(NO3)2 + 30 Al(NO3)3 + 85 NH2CONH2 = 3 BaMgAl10O17 + 85 CO2 + 136 N2 + 170 H2O

V{2+} + Mn{7+} = V{5} + Mn{2+} =>
5 V{2+} + 3 Mn{7+} = 5 V{5} + 3 Mn{2+}

Ca + C20H14O4 = CaO4 + C20H14 =>
Ca + C20H14O4 = CaO4 + C20H14

F(g) + FeI(aq) = FeF(aq) + I(I) =>
2 F(g) + 2 FeI(aq) = 2 FeF(aq) + I(I)

Ca(NO3)2 + Na3PO4 = CaPO4 + Na3 + (NO3)2 =>
Ca(NO3)2 + Na3PO4 = CaPO4 + Na3 + (NO3)2

HNO3 + Mg(C2H3O2)2 = Mg(NO3)2 + H(C2H3O2) =>
2 HNO3 + Mg(C2H3O2)2 = Mg(NO3)2 + 2 H(C2H3O2)

Al + O2 = AlO3 =>
2 Al + 3 O2 = 2 AlO3

Pb + Ag(No) = Pb(No) + Ag =>
Pb + Ag(No) = Pb(No) + Ag

NaVO3 + HCl + Pt = H2[PtCl6] + VOCl2 + NaCl + H2O =>
4 NaVO3 + 18 HCl + Pt = H2[PtCl6] + 4 VOCl2 + 4 NaCl + 8 H2O

Ga + I2 + NH4OH = Ga(OH)3 + NH4I =>
2 Ga + 3 I2 + 6 NH4OH = 2 Ga(OH)3 + 6 NH4I

CH3CHO + CuSO4 + NaOH = CH3COONa + Cu3O + NaSO4 + H2O =>
CH3CHO + 6 CuSO4 + 7 NaOH = CH3COONa + 2 Cu3O + 6 NaSO4 + 4 H2O

NH2Cl = N2H3Cl + HCl =>
2 NH2Cl = N2H3Cl + HCl

C5H8 + KMnO4 + H2SO4 = K2SO4 + MnSO4 + CO2 + H2O =>
5 C5H8 + 28 KMnO4 + 42 H2SO4 = 14 K2SO4 + 28 MnSO4 + 25 CO2 + 62 H2O

Ir(NO3)4(aq) + NaOH(aq) = IrOH(aq) + Na(NO3)4(aq) =>
Ir(NO3)4(aq) + NaOH(aq) = IrOH(aq) + Na(NO3)4(aq)

MgSO4 + H2O = MgSO4H2O =>
MgSO4 + H2O = MgSO4H2O

Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 H2O

CuCO2 + NaOH = Na + CO2 + Cu(OH)2 =>
CuCO2 + 2 NaOH = 2 Na + CO2 + Cu(OH)2

NH3CO + H2O + O2 = NH2O2 + C2H3O2 =>
8 NH3CO + 2 H2O + 7 O2 = 8 NH2O2 + 4 C2H3O2

C2H4 + O2 = CO2 + H2O =>
C2H4 + 3 O2 = 2 CO2 + 2 H2O

Br + LiF = LiBr + F2 =>
2 Br + 2 LiF = 2 LiBr + F2

Ag2CO3 + NiCl2 = AgCl + (CO3)2Ni2 =>
2 Ag2CO3 + 2 NiCl2 = 4 AgCl + (CO3)2Ni2

Ar2Cl = Ar + Cl =>
Ar2Cl = 2 Ar + Cl

Mg + CO2 = MgO + C =>
2 Mg + CO2 = 2 MgO + C

Na2S2O3 + CH3COOH = CH3COONa + H2S2O3 =>
Na2S2O3 + 2 CH3COOH = 2 CH3COONa + H2S2O3

P4 + NaOH = PH3 + Na + HPO3 =>
5 P4 + 36 NaOH = 8 PH3 + 36 Na + 12 HPO3

MnO4{-} + C6H5CHO + H2O = MnO2 + C6H5COOH + OH{-} =>
2 MnO4{-} + 3 C6H5CHO + H2O = 2 MnO2 + 3 C6H5COOH + 2 OH{-}

CaCl2 + Na2CO3 = CaCO3 + NaCl =>
CaCl2 + Na2CO3 = CaCO3 + 2 NaCl

AlOHSO4 + Al(HSO4)3 = Al2(SO4)3 + H2O =>
3 AlOHSO4 + Al(HSO4)3 = 2 Al2(SO4)3 + 3 H2O

Mg + HCH3COO = Mg(CH3COO)2 + H2 =>
Mg + 2 HCH3COO = Mg(CH3COO)2 + H2

KMnO4 + KOH + H2S = K2MnO4 + H2O + H2SO4 =>
8 KMnO4 + 8 KOH + H2S = 8 K2MnO4 + 4 H2O + H2SO4

Cr2O3 + C + Cl = CrCl3 + CO =>
Cr2O3 + 3 C + 6 Cl = 2 CrCl3 + 3 CO

Hg2(aq) + NaS(aq) = HgS(s) + Na(aq) =>
Hg2(aq) + 2 NaS(aq) = 2 HgS(s) + 2 Na(aq)

K2CrO4 + Hg2(NO3)2 = Hg2CrO4 + KNO3 =>
K2CrO4 + Hg2(NO3)2 = Hg2CrO4 + 2 KNO3

(C8H7O3)I + NaOH = (C8H7O3)OH + NaI =>
(C8H7O3)I + NaOH = (C8H7O3)OH + NaI

Cr + O2 + HBr = CrBr3 + H2O =>
4 Cr + 3 O2 + 12 HBr = 4 CrBr3 + 6 H2O

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Balance the equation of any chemical reaction
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Equations balanced on 03/12/25
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