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Chemical Equations Balanced on 03/18/25

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Balance the equation of any chemical reaction
H2C2O4(aq) + NaOH(aq) = H2O + Na2C2O4(aq) =>
H2C2O4(aq) + 2 NaOH(aq) = 2 H2O + Na2C2O4(aq)

NaH + HNO3 = NaNO2 + H2O =>
NaH + HNO3 = NaNO2 + H2O

H2SO4 + NH4OH = H2O + (NH4)2SO4 =>
H2SO4 + 2 NH4OH = 2 H2O + (NH4)2SO4

KIO3(aq) + AgNO3(aq) = KNO3(aq) + AgIO3(s) =>
KIO3(aq) + AgNO3(aq) = KNO3(aq) + AgIO3(s)

H2CO3 + MgO = H2 + MgOCO3 =>
H2CO3 + MgO = H2 + MgOCO3

HBr + Fe(OH)3 = FeBr3 + H2O =>
3 HBr + Fe(OH)3 = FeBr3 + 3 H2O

FeSO4 + HOH = Fe(OH)2 + H2SO4 =>
FeSO4 + 2 HOH = Fe(OH)2 + H2SO4

NH4OH + H2SO4 = (NH4)2SO4 + HOH =>
2 NH4OH + H2SO4 = (NH4)2SO4 + 2 HOH

CH3CH2COOH + CH3OH = CH3CH2COOCH3 + H2O =>
CH3CH2COOH + CH3OH = CH3CH2COOCH3 + H2O

Au + HCl = Au2Cl3 + H2 =>
4 Au + 6 HCl = 2 Au2Cl3 + 3 H2

C5H10O2 + O2(g) = CO2 + H2O =>
2 C5H10O2 + 13 O2(g) = 10 CO2 + 10 H2O

Mg2 + H2CO3 = MgCO3 + H2 =>
Mg2 + 2 H2CO3 = 2 MgCO3 + 2 H2

AuNO3 + Ba = Ba(NO3)2 + Au =>
2 AuNO3 + Ba = Ba(NO3)2 + 2 Au

Cu(CH3COO)2(aq) + NaOH(aq) = Cu(OH)2(s) + NaCH3COO(aq) =>
Cu(CH3COO)2(aq) + 2 NaOH(aq) = Cu(OH)2(s) + 2 NaCH3COO(aq)

H2SO4 + NH4OH = H2O + (NH4)2SO4 =>
H2SO4 + 2 NH4OH = 2 H2O + (NH4)2SO4

FeCO3(s) + HCl(aq) = FeCl2 + H2O + CO2 =>
FeCO3(s) + 2 HCl(aq) = FeCl2 + H2O + CO2

FeCl3 + H2O + Na2CO3 = Fe(OH)3 + CO2 + NaCl =>
2 FeCl3 + 3 H2O + 3 Na2CO3 = 2 Fe(OH)3 + 3 CO2 + 6 NaCl

Na{+}Cl{-} + Ag{+3}N{2-} = Na{2+}N{-} + Ag{+}Cl{2-} =>
2 Na{+}Cl{-} + Ag{+3}N{2-} = 2 Na{2+}N{-} + Ag{+}Cl{2-}

Al2O3 + Cl2O = AlCl3 + O2 =>
Al2O3 + 3 Cl2O = 2 AlCl3 + 3 O2

Mg2SiO4 + CO2 = SiO2 + MgCO3 =>
Mg2SiO4 + 2 CO2 = SiO2 + 2 MgCO3

Cl(g) + NaBr(aq) = NaCl(aq) + Br(l) =>
Cl(g) + NaBr(aq) = NaCl(aq) + Br(l)

Na2S + KMnO4 + H2SO4 = K2SO4 + MnSO4 + Na2SO4 + H2O =>
5 Na2S + 8 KMnO4 + 12 H2SO4 = 4 K2SO4 + 8 MnSO4 + 5 Na2SO4 + 12 H2O

FeCl2 + K3PO4 = Fe3(PO4)2 + KCl =>
3 FeCl2 + 2 K3PO4 = Fe3(PO4)2 + 6 KCl

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

PhCH3 + KMnO4 + H2SO4 = PhCOOH + K2SO4 + MnSO4 + H2O =>
5 PhCH3 + 6 KMnO4 + 9 H2SO4 = 5 PhCOOH + 3 K2SO4 + 6 MnSO4 + 14 H2O

H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

H2SO4 + K4Fe(CN)6 + KMnO4 = CO2 + Fe2(SO4)3 + H2O + HNO3 + KHSO4 + MnSO4 =>
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122 MnSO4

C6H5COOH + O2 = CO2 + H2O =>
2 C6H5COOH + 15 O2 = 14 CO2 + 6 H2O

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

Cu + HNO3 = Cu(NO3)2 + NO2 + H2O =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O

K4Fe(CN)6 + H2SO4 + H2O = K2SO4 + FeSO4 + (NH4)2SO4 + CO =>
K4Fe(CN)6 + 6 H2SO4 + 6 H2O = 2 K2SO4 + FeSO4 + 3(NH4)2SO4 + 6 CO

HCOOH + C2H5OH = HCOOC2H5 + H2O =>
HCOOH + C2H5OH = HCOOC2H5 + H2O

Zn + P2O5 = ZnP2O5 =>
Zn + P2O5 = ZnP2O5

PbCl + MgO = PbOMgCl =>
PbCl + MgO = PbOMgCl

H3PO4 + Ca = Ca3(PO4)2 + H2 =>
2 H3PO4 + 3 Ca = Ca3(PO4)2 + 3 H2

H2MnO4 = HMnO4 + MnO2 + H2O =>
3 H2MnO4 = 2 HMnO4 + MnO2 + 2 H2O

Si2Cl6 + LiAlH4 = Si2H6 + LiAlCl4 =>
2 Si2Cl6 + 3 LiAlH4 = 2 Si2H6 + 3 LiAlCl4

Al + Ni2(SO4)2 = Al2(SO4)3 + Ni =>
4 Al + 3 Ni2(SO4)2 = 2 Al2(SO4)3 + 6 Ni

Br2 + H3AsO4 = As4 + HBrO2 + H2O =>
10 Br2 + 12 H3AsO4 = 3 As4 + 20 HBrO2 + 8 H2O

FeCO3(s) = CO2(g) + FeO(s) =>
FeCO3(s) = CO2(g) + FeO(s)

PbO2 + CrCl3 + H2SO4 = PbO + Cr(SO4)3 + HCl + H2O =>
3 PbO2 + 2 CrCl3 + 6 H2SO4 = 3 PbO + 2 Cr(SO4)3 + 6 HCl + 3 H2O

C7H14 + Br2 = C7H13 + HBr =>
2 C7H14 + Br2 = 2 C7H13 + 2 HBr

NH4OH + H3PO4 = (NH4)3PO4 + H2O =>
3 NH4OH + H3PO4 = (NH4)3PO4 + 3 H2O

MeO2 = Me + O2 =>
MeO2 = Me + O2

Cr(OH)3 + IO3{-} + OH{-}{-} = CrO42{2-} + I{-} + H2O =>
6 Cr(OH)3 + 79 IO3{-} + 12 OH{-}{-} = 6 CrO42{2-} + 79 I{-} + 15 H2O

P2O5 + H2O = H3PO4 =>
P2O5 + 3 H2O = 2 H3PO4

C2H2O3 + O2 = CO2 + H2O =>
C2H2O3 + O2 = 2 CO2 + H2O

McO4 + HCl = McCl2 + Cl2 + H2O =>
McO4 + 8 HCl = McCl2 + 3 Cl2 + 4 H2O

K2SO4 + Cr2(SO4)3 + H2O = KCr(SO4)2*12H2O =>
K2SO4 + Cr2(SO4)3 + 24 H2O = 2 KCr(SO4)2*12H2O

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Balance the equation of any chemical reaction
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Equations balanced on 03/11/25
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