| Equations balanced on the previous day | Equations balanced on the next day |
2 SO2 + Ca(OH)2 = Ca(HSO3)2
C6H5Br + Na + C2H5Br = C6H6 + NaBr =>
9 C6H5Br + 12 Na + 3 C2H5Br = 10 C6H6 + 12 NaBr
Mn(NO3)2 + C6H8O7 = Mn2O3 + N2 + CO2 + H2O =>
2 Mn(NO3)2 + C6H8O7 = Mn2O3 + 2 N2 + 6 CO2 + 4 H2O
Na2CO3Ba = BaNa2CO3 =>
Na2CO3Ba = BaNa2CO3
CuCl2 + SO2 + H2O = CuCl + HCl + H2SO4 =>
2 CuCl2 + SO2 + 2 H2O = 2 CuCl + 2 HCl + H2SO4
H{+} + Fe{2+} + CrO4{-} = Fe{3+} + Cr{3+} + H2O =>
8 H{+} + 4 Fe{2+} + CrO4{-} = 4 Fe{3+} + Cr{3+} + 4 H2O
Na2S + H(C2H3O2) = Na(C2H3O2) + H2S =>
Na2S + 2 H(C2H3O2) = 2 Na(C2H3O2) + H2S
C6H12O6 + NH3 = C100H175N15O50 + H2O + O2 =>
100 C6H12O6 + 90 NH3 = 6 C100H175N15O50 + 210 H2O + 45 O2
CH3CH2OSO3H + Na2CO3 = CH3CH2OSO3Na + CO2 + H2O =>
2 CH3CH2OSO3H + Na2CO3 = 2 CH3CH2OSO3Na + CO2 + H2O
Cu(NO3)2 + HOH = CuOHNO3 + HNO3 =>
Cu(NO3)2 + HOH = CuOHNO3 + HNO3
Mg(s) + Cr2(SO4)3(aq) = MgSO4(aq) + Cr(s) =>
3 Mg(s) + Cr2(SO4)3(aq) = 3 MgSO4(aq) + 2 Cr(s)
KMnO4 + H2SO4 + Na2SO3 = K2SO4 + MnSO4 + Na2SO4 + H2O =>
2 KMnO4 + 3 H2SO4 + 5 Na2SO3 = K2SO4 + 2 MnSO4 + 5 Na2SO4 + 3 H2O
Ca + Mg(NO3)2 = Ca(NO3)2 + Mg =>
Ca + Mg(NO3)2 = Ca(NO3)2 + Mg
Al2(So4)3(aq) + Ca(oh)2(aq) = Al(oh)3(aq) + Ca2(So4)2(l) =>
6 Al2(So4)3(aq) + 9 Ca(oh)2(aq) = 4 Al(oh)3(aq) + 9 Ca2(So4)2(l)
O6 + HCl = HClO6 =>
O6 + HCl = HClO6
NaAlO2 + HNO3 = NaNO3 + AlO2 + H2 =>
2 NaAlO2 + 2 HNO3 = 2 NaNO3 + 2 AlO2 + H2
KMnO4 + HCl = Cl2 + H2O + KCl + MnCl2 =>
2 KMnO4 + 16 HCl = 5 Cl2 + 8 H2O + 2 KCl + 2 MnCl2
C3H6(g) + O2(g) = CO2 + H2O =>
2 C3H6(g) + 9 O2(g) = 6 CO2 + 6 H2O
BeI2(aq) + Cu2SO4(aq) = Be2SO4(aq) + CuI2(aq) =>
2 BeI2(aq) + Cu2SO4(aq) = Be2SO4(aq) + 2 CuI2(aq)
NH4Cl + CaS = (NH4)2S + CaCl2 =>
2 NH4Cl + CaS = (NH4)2S + CaCl2
SnCl4 + Fe2S3 = FeCl3 + SnS2 =>
3 SnCl4 + 2 Fe2S3 = 4 FeCl3 + 3 SnS2
FeCl3*6H2O + FeSO4*7H2O + NaOH = Fe3O4 + NaCl + (Na)2SO4 + H2O =>
2 FeCl3*6H2O + FeSO4*7H2O + 8 NaOH = Fe3O4 + 6 NaCl + (Na)2SO4 + 23 H2O
Ag2O = Ag + O2 =>
2 Ag2O = 4 Ag + O2
NaI(aq)HNO3(aq) = NaNO3(aq)HI(aq) =>
NaI(aq)HNO3(aq) = NaNO3(aq)HI(aq)
NH4Br + Ba(NO3)2 = NH4(NO3) + Ba(Br)2 =>
2 NH4Br + Ba(NO3)2 = 2 NH4(NO3) + Ba(Br)2
P4(s) + HNO3(ac) = NO2(g) + H3PO4(ac) + H20(l) =>
5 P4(s) + 80 HNO3(ac) = 80 NO2(g) + 20 H3PO4(ac) + H20(l)
Cu{2+} + H2O = O2 + H{+} + Cu{+} =>
4 Cu{2+} + 2 H2O = O2 + 4 H{+} + 4 Cu{+}
NaOH + Fe2 = FeOH + Na =>
2 NaOH + Fe2 = 2 FeOH + 2 Na
C3N12 = C + N2 =>
C3N12 = 3 C + 6 N2
Fe + CH3COOH = FeCH3COO + H2 =>
2 Fe + 2 CH3COOH = 2 FeCH3COO + H2
CrOH3 + H2O2 = Cr2O4 + H2O =>
2 CrOH3 + 5 H2O2 = Cr2O4 + 8 H2O
Ca(OH)2 + NaMnO4 = Ca(MnO4)2 + NaOH =>
Ca(OH)2 + 2 NaMnO4 = Ca(MnO4)2 + 2 NaOH
KMnO4 + HNO2 + H2SO4 = MnSO4 + H2O + K2SO4 + HNO3 =>
2 KMnO4 + 5 HNO2 + 3 H2SO4 = 2 MnSO4 + 3 H2O + K2SO4 + 5 HNO3
Ca + SiO = CaSiO =>
Ca + SiO = CaSiO
HH + OO = HOH =>
2 HH + OO = 2 HOH
Cl(aq) + KI(aq) = KCl(aq) + I2(aq) =>
2 Cl(aq) + 2 KI(aq) = 2 KCl(aq) + I2(aq)
I{-} = I2 + {-} =>
2 I{-} = I2 + 2e
CH3CHOHCH3 + KMnO4 + H2SO4 = CH3COOH + H2O + K2SO4 + MnSO4 =>
10 CH3CHOHCH3 + 12 KMnO4 + 18 H2SO4 = 15 CH3COOH + 28 H2O + 6 K2SO4 + 12 MnSO4
K2(Cr2O7) + HI + HClO4 = K(IO4) + Cr(ClO4)3 + KCl + H2O =>
8 K2(Cr2O7) + 11 HI + 53 HClO4 = 11 K(IO4) + 16 Cr(ClO4)3 + 5 KCl + 32 H2O
H3PO4 + (NH4)2MoO4 + HNO3 = (NH4)3(PO4)(MoO3)12 + NH4NO3 + H2O =>
H3PO4 + 12(NH4)2MoO4 + 21 HNO3 = (NH4)3(PO4)(MoO3)12 + 21 NH4NO3 + 12 H2O
N2O5 + KOH = N2OH + KO5 =>
N2O5 + KOH = N2OH + KO5
KMgO4 = O2 + K2O + MgO =>
4 KMgO4 = 5 O2 + 2 K2O + 4 MgO
ClO{-} + S2O3{2-} + OH{-} = Cl{-} + SO4{2-} + H =>
3 ClO{-} + S2O3{2-} + 2 OH{-} = 3 Cl{-} + 2 SO4{2-} + 2 H
Na3P + Na2Cr2O7 + HCl = CrCl3 + NaCl + Na3PO4 + H2O =>
3 Na3P + 4 Na2Cr2O7 + 32 HCl = 8 CrCl3 + 8 NaCl + 3 Na3PO4 + 16 H2O
K2CrO4 + KCl + H2SO4 = CrO2Cl2 + K2SO4 + H2O =>
K2CrO4 + 2 KCl + 2 H2SO4 = CrO2Cl2 + 2 K2SO4 + 2 H2O
Ba(NO2)2 + Na = NaNO2 + Ba =>
Ba(NO2)2 + 2 Na = 2 NaNO2 + Ba
C13N3H16 + O2 = CO2 + H2O + NO2 =>
C13N3H16 + 20 O2 = 13 CO2 + 8 H2O + 3 NO2
K2Cr2O7 + HCl + C2H5OH = KCl + Cr + CH3COOH + H2O =>
K2Cr2O7 + 2 HCl + 3 C2H5OH = 2 KCl + 2 Cr + 3 CH3COOH + 4 H2O
C14H10O2 + C2H5OH + NaBH4 = C14H14O2 + NaB(OH)4 =>
28 C14H10O2 + 28 C2H5OH + 5 NaBH4 = 32 C14H14O2 + 5 NaB(OH)4
LiCrO4 + FeCl = LiCl + FeCrO4 =>
LiCrO4 + FeCl = LiCl + FeCrO4
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| Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/23/25
Equations balanced on 02/22/24
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