| Equations balanced on the previous day | Equations balanced on the next day |
Fe2(SO3)3 + HBr = H(SO3)3 + Fe2Br
C6H6 + O2 = CO2 + H2O =>
2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
Na3PO4 + AlCl3 = AlPO4 + NaCl =>
Na3PO4 + AlCl3 = AlPO4 + 3 NaCl
CH3NH3 = NH3 + CH3 =>
CH3NH3 = NH3 + CH3
KNO3 + ZnCl2 = KCl + Zn(NO3)2 =>
2 KNO3 + ZnCl2 = 2 KCl + Zn(NO3)2
Na2CO3 + KMnO4 = NaMnO4 + K2CO3 =>
Na2CO3 + 2 KMnO4 = 2 NaMnO4 + K2CO3
Fe2(SO3)3 + HBr = H(SO3)3 + Fe2Br =>
Fe2(SO3)3 + HBr = H(SO3)3 + Fe2Br
Cu2CO3 + H2SO4 = Cu2SO4 + CO2 + H2O =>
Cu2CO3 + H2SO4 = Cu2SO4 + CO2 + H2O
(NH4)2Cr2O7 + HCl = CrCl3 + NH4Cl + Cl2 + H2O =>
(NH4)2Cr2O7 + 14 HCl = 2 CrCl3 + 2 NH4Cl + 3 Cl2 + 7 H2O
K2Cr2O7 + H2SO4 + FeSO4 = K2SO4 + Fe2(SO4)3 + Cr2(SO4)3 + H2O =>
K2Cr2O7 + 7 H2SO4 + 6 FeSO4 = K2SO4 + 3 Fe2(SO4)3 + Cr2(SO4)3 + 7 H2O
P2O5 + BeO = Be3(PO4)2 =>
P2O5 + 3 BeO = Be3(PO4)2
NaHS + H2O2 = NaS + H2O =>
2 NaHS + H2O2 = 2 NaS + 2 H2O
NaB(H)4 + H2O + C2OH = H3COH + NaB(OH)4 =>
5 NaB(H)4 + 28 H2O + 8 C2OH = 16 H3COH + 5 NaB(OH)4
CH3COOH + KOH = CH4O3 + K =>
CH3COOH + 4 KOH = 2 CH4O3 + 4 K
(NH4)2SO4 + NaOH = NH3 + H2O + Na2SO4 =>
(NH4)2SO4 + 2 NaOH = 2 NH3 + 2 H2O + Na2SO4
Cu(OH)2 + NH4OH = Cu[NH4(OH)3] =>
Cu(OH)2 + NH4OH = Cu[NH4(OH)3]
AlPHCl = AlClPH =>
AlPHCl = AlClPH
CH3CH(Br)CH3 + NaOH = CH3CH(OH)CH3 + NaBr =>
CH3CH(Br)CH3 + NaOH = CH3CH(OH)CH3 + NaBr
BaCl2 + NaHCO3 = BaCO3 + CO2 + H2O + NaCl =>
BaCl2 + 2 NaHCO3 = BaCO3 + CO2 + H2O + 2 NaCl
H3BO3 + HCl = BCl3 + H2O =>
H3BO3 + 3 HCl = BCl3 + 3 H2O
Fe2(SO3)3 + HBr = H(SO3)3 + Fe2Br =>
Fe2(SO3)3 + HBr = H(SO3)3 + Fe2Br
CaSO4H2O = H2SO4CaO =>
CaSO4H2O = H2SO4CaO
HCl + Fe(OH)3 = FeCl3 + H2O =>
3 HCl + Fe(OH)3 = FeCl3 + 3 H2O
Cu + H3PO4 = P + H3CuO4 =>
Cu + H3PO4 = P + H3CuO4
Mg + Co(NO3)2 = Mg(NO3)2 + Co =>
Mg + Co(NO3)2 = Mg(NO3)2 + Co
Si + HNO3 = SiO2 + NO2 + H2O =>
Si + 4 HNO3 = SiO2 + 4 NO2 + 2 H2O
Ba(NO3)2 + Na3(PO4) = Ba3(PO4)2 + NaNO3 =>
3 Ba(NO3)2 + 2 Na3(PO4) = Ba3(PO4)2 + 6 NaNO3
K4Fe(CN)6 + MnO4 + H2SO4 = Fe(CN)6 + MnSO4 + K2O4 + H2O =>
3 K4Fe(CN)6 + 8 MnO4 + 8 H2SO4 = 3 Fe(CN)6 + 8 MnSO4 + 6 K2O4 + 8 H2O
KOH + BaCl2 = Ba(OH)2 + KCl =>
2 KOH + BaCl2 = Ba(OH)2 + 2 KCl
As2O3 + F = AsF5 + O =>
As2O3 + 10 F = 2 AsF5 + 3 O
C(g) + O2(s) = CO2(g) =>
C(g) + O2(s) = CO2(g)
CS2 + HNO3 = SO2 + CO + NO2 + H2O =>
CS2 + 10 HNO3 = 2 SO2 + CO + 10 NO2 + 5 H2O
Fe2(SO3)3 + HBr = H(SO3)3 + Fe2Br =>
Fe2(SO3)3 + HBr = H(SO3)3 + Fe2Br
KOH + BaCl2 = Ba(OH)2 + KCl =>
2 KOH + BaCl2 = Ba(OH)2 + 2 KCl
KI(aq) + FeCl3(aq) = FeI3() + KCl() =>
3 KI(aq) + FeCl3(aq) = FeI3() + 3 KCl()
C + H2O = C2H5OH + CO2 =>
3 C + 3 H2O = C2H5OH + CO2
(NH4)3PO3 + HCl = H3PO3 + NH4Cl =>
(NH4)3PO3 + 3 HCl = H3PO3 + 3 NH4Cl
NaCl + NH2CH2COOH = CH2COH + NH2NaOCl =>
NaCl + NH2CH2COOH = CH2COH + NH2NaOCl
H2SO4 + KCr = Cr + SO2 + H2O + K2SO4 =>
2 H2SO4 + 2 KCr = 2 Cr + SO2 + 2 H2O + K2SO4
CuS + HNO3 = Cu(NO3)2 + NO2 + H2O + SO2 =>
CuS + 8 HNO3 = Cu(NO3)2 + 6 NO2 + 4 H2O + SO2
C2H2 + O2 = CO2 + H2O =>
2 C2H2 + 5 O2 = 4 CO2 + 2 H2O
H{+} + CrO4{-2} + NO2{-} = Cr{+3} + H2O + NO3{-} =>
10 H{+} + 2 CrO4{-2} + 3 NO2{-} = 2 Cr{+3} + 5 H2O + 3 NO3{-}
KOH + BaCl2 = Ba(OH)2 + KCl =>
2 KOH + BaCl2 = Ba(OH)2 + 2 KCl
Cl2*H2 = HCl =>
Cl2*H2 = 2 HCl
Zn(NO3)2(aq) + K3PO4(aq) = Zn3(PO4)2(s) + KNO3(aq) =>
3 Zn(NO3)2(aq) + 2 K3PO4(aq) = Zn3(PO4)2(s) + 6 KNO3(aq)
CH3(CH2)4COOH + Ca(OH)2 = CH3(CH2)4COOCa + H2O + OH =>
CH3(CH2)4COOH + Ca(OH)2 = CH3(CH2)4COOCa + H2O + OH
Mg + Co(NO3)3 = Mg(NO3)2 + Co =>
3 Mg + 2 Co(NO3)3 = 3 Mg(NO3)2 + 2 Co
Ca(NO3)2 + NH4H2PO4 + NH4OH = Ca10(PO4)6(OH)2 + NH4NO3 + H2O =>
10 Ca(NO3)2 + 6 NH4H2PO4 + 14 NH4OH = Ca10(PO4)6(OH)2 + 20 NH4NO3 + 12 H2O
CuO + N2 + CaCl2 + H2O = Ca(NO3)2 + HCl + Cu =>
5 CuO + N2 + CaCl2 + H2O = Ca(NO3)2 + 2 HCl + 5 Cu
Ag(NH3)2{+} + KI = AgI + NH3 + K{+} =>
Ag(NH3)2{+} + KI = AgI + 2 NH3 + K{+}
| 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 |
| Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/13/25
Equations balanced on 02/12/24
Please let us know how we can improve this web app.
