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Chemical Equations Balanced on 12/03/24

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Balance the equation of any chemical reaction
NaOH + Na2C2O4 = NaC2O4 + Na2OH =>
NaOH + Na2C2O4 = NaC2O4 + Na2OH

Na2S + Na2Cr2O7 + H2SO4 = Cr2(SO4)3 + Na2SO4 + H2O =>
3 Na2S + 4 Na2Cr2O7 + 16 H2SO4 = 4 Cr2(SO4)3 + 7 Na2SO4 + 16 H2O

CaCl2(aq) + Na2CO3(aq) = CaCO3(ppt) + NaCl(aq) =>
CaCl2(aq) + Na2CO3(aq) = CaCO3(ppt) + 2 NaCl(aq)

C6H12O6 + O2 = CO2 + H2O =>
C6H12O6 + 6 O2 = 6 CO2 + 6 H2O

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

H2O + Cd + Ni2O3 = Cd(OH)2 + Ni(OH)2 =>
3 H2O + Cd + Ni2O3 = Cd(OH)2 + 2 Ni(OH)2

P2O4 + O2 + H2O = H3PO4 =>
2 P2O4 + O2 + 6 H2O = 4 H3PO4

C9H18 + O2 = CO2 + H2O =>
2 C9H18 + 27 O2 = 18 CO2 + 18 H2O

PbO2 + H2MnO3 + HNO3 = Pb(NO3)2 + HMnO4 + H2O =>
3 PbO2 + 2 H2MnO3 + 6 HNO3 = 3 Pb(NO3)2 + 2 HMnO4 + 4 H2O

C2H5Cl + CH3Cl = C3H8 + Cl2 =>
C2H5Cl + CH3Cl = C3H8 + Cl2

Al + H2O + Na2CO3 = Na[Al(OH)4] + NaHCO3 + H2 =>
2 Al + 8 H2O + 2 Na2CO3 = 2 Na[Al(OH)4] + 2 NaHCO3 + 3 H2

Al + Na2CO3 + H2O = Na[Al(OH)4] + CO2 + H2 =>
2 Al + Na2CO3 + 7 H2O = 2 Na[Al(OH)4] + CO2 + 3 H2

KMnO4 + C3H5(OH)2 = K2CO3 + Mn2O3 + CO2 + H2O =>
30 KMnO4 + 8 C3H5(OH)2 = 15 K2CO3 + 15 Mn2O3 + 9 CO2 + 28 H2O

C(s) + SnO2(s) = CO(s) + Sn(s) =>
2 C(s) + SnO2(s) = 2 CO(s) + Sn(s)

NO + H2O = HN2 + OH =>
2 NO + 3 H2O = HN2 + 5 OH

LiClO2 + H2O = LiOH + HClO2 =>
LiClO2 + H2O = LiOH + HClO2

Na3P + H2O = PH3 + Na2O =>
2 Na3P + 3 H2O = 2 PH3 + 3 Na2O

C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

Ca(NO3)2(aq) + Na2S(aq) = NaNO3(aq) + CaS(s) =>
Ca(NO3)2(aq) + Na2S(aq) = 2 NaNO3(aq) + CaS(s)

Fe + AgNO3 = (FeNO3)2 + Ag =>
2 Fe + 2 AgNO3 = (FeNO3)2 + 2 Ag

NiCO3*2Ni(OH)2*4H2O + (NH4)2SO4 + H2SO4 = (NH4)2Ni(SO4)2*6H2O + NiSO4 + (NH4)2CO3 =>
3 NiCO3*2Ni(OH)2*4H2O + 7(NH4)2SO4 + 6 H2SO4 = 4(NH4)2Ni(SO4)2*6H2O + 5 NiSO4 + 3(NH4)2CO3

Fe(CO) = Fe + CO =>
Fe(CO) = Fe + CO

LiClO2 + H2O = LiOH + HClO2 =>
LiClO2 + H2O = LiOH + HClO2

H2O + O2 = H2O2 =>
2 H2O + O2 = 2 H2O2

K2CrO4 + KI + H2SO4 = Cr2(SO4)3 + I2 + K2SO4 + H2O =>
2 K2CrO4 + 6 KI + 8 H2SO4 = Cr2(SO4)3 + 3 I2 + 5 K2SO4 + 8 H2O

Mg + Li2SO4 = Li2Mg + SO4 =>
Mg + Li2SO4 = Li2Mg + SO4

K2HPO4 + Ca(OH)2 = CaHPO4 + KOH =>
K2HPO4 + Ca(OH)2 = CaHPO4 + 2 KOH

Fe(CO) = Fe + CO =>
Fe(CO) = Fe + CO

HNO3 = H{+} + NO3{-} =>
HNO3 = H{+} + NO3{-}

AgNO3(ag) + H2SO4(ag) = Ag2SO4(s) + HNO3(ag) =>
2 AgNO3(ag) + H2SO4(ag) = Ag2SO4(s) + 2 HNO3(ag)

KCO3 + HCl = KCl + OH + CO2 =>
KCO3 + HCl = KCl + OH + CO2

NH2CH2COOH(s) + O2(g) = CO2(g) + H2O(l) + N2(g) =>
4 NH2CH2COOH(s) + 9 O2(g) = 8 CO2(g) + 10 H2O(l) + 2 N2(g)

Mg + H2O = Mg(OH)2 + H2 =>
Mg + 2 H2O = Mg(OH)2 + H2

MgSO4 + S + H2O = Mg + H2SO4 =>
3 MgSO4 + S + 4 H2O = 3 Mg + 4 H2SO4

CHO + OH = COO + H2O =>
CHO + 3 OH = COO + 2 H2O

Ba + (NH4)3PO4 = Ba3PO4 + NH4 =>
3 Ba + (NH4)3PO4 = Ba3PO4 + 3 NH4

Fe(NO3)3 + KSCN = Fe(SCN)2 + KNO3 + SCN =>
Fe(NO3)3 + 3 KSCN = Fe(SCN)2 + 3 KNO3 + SCN

(NH4)2Fe(SO4)2*6H2O + H2C2O4 = FeC2O4*2H2O + (NH4)2SO4 + H2SO4 + H2O =>
(NH4)2Fe(SO4)2*6H2O + H2C2O4 = FeC2O4*2H2O + (NH4)2SO4 + H2SO4 + 4 H2O

C7H8O + Cr2O7 = C7H6O2 + Cr + H2O =>
7 C7H8O + 2 Cr2O7 = 7 C7H6O2 + 4 Cr + 7 H2O

K{-}O{-}H{-} + H{3+}PO{4+} = K{3+}PO{4+} + H{2}O{3} =>
K{-}O{-}H{-} + 4 H{3+}PO{4+} = K{3+}PO{4+} + 4 H{2}O{3}

Fe(SCN)3(aq) + Na2S2O3(aq) = Fe(SCN)2(aq) + NaSCN(aq) + Na2S4O6(aq) =>
2 Fe(SCN)3(aq) + 2 Na2S2O3(aq) = 2 Fe(SCN)2(aq) + 2 NaSCN(aq) + Na2S4O6(aq)

Zn + Au(NO2)2 = Zn(NO2)2 + Au =>
Zn + Au(NO2)2 = Zn(NO2)2 + Au

FeCl3 + NaOH = Fe(OH)3 + NaCl =>
FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl

H[SnCl3] + H2S = SnS + HCl =>
H[SnCl3] + H2S = SnS + 3 HCl

C6H12O6 + O2 = CO2 + H2O =>
C6H12O6 + 6 O2 = 6 CO2 + 6 H2O

Al + O2 = Al2O3 =>
4 Al + 3 O2 = 2 Al2O3

C3H8O + O2 = CO2 + H2O =>
2 C3H8O + 9 O2 = 6 CO2 + 8 H2O

Ca3N2 + LiNO3 = Ca(NO3)2 + Li3N =>
Ca3N2 + 6 LiNO3 = 3 Ca(NO3)2 + 2 Li3N

HgO = Hg + O2 =>
2 HgO = 2 Hg + O2

NH4OH + H3PO4 = (NH4)3PO4 + H2O =>
3 NH4OH + H3PO4 = (NH4)3PO4 + 3 H2O

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Balance the equation of any chemical reaction
 Equations balanced on the previous day Equations balanced on the next day
Equations balanced on 11/26/24
Equations balanced on 11/03/24
Equations balanced on 12/03/23
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