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Chemical Equations Balanced on 12/03/24

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Balance the equation of any chemical reaction
Mg + HCl = MgCl2 + H2 =>
Mg + 2 HCl = MgCl2 + H2

K2Cr2O7 + Na2S + NaOH + H2O = K3[Cr(OH)6] + Na2CrO4 + S =>
3 K2Cr2O7 + 3 Na2S + 2 NaOH + 5 H2O = 2 K3[Cr(OH)6] + 4 Na2CrO4 + 3 S

Cl2O5 + H2O = HClO3 =>
Cl2O5 + H2O = 2 HClO3

S + NaOH = Na2S3 + Na2S4O6 + H2O =>
19 S + 12 NaOH = 5 Na2S3 + Na2S4O6 + 6 H2O

Ca3(PO4)2(s) + H2SO4(aq) = CaHPO4(s) + CaSO4(s) =>
Ca3(PO4)2(s) + H2SO4(aq) = 2 CaHPO4(s) + CaSO4(s)

MgSO4 + NaNo3 = MgNo3 + NaSO4 =>
MgSO4 + NaNo3 = MgNo3 + NaSO4

Mg(OH)2 + CdCl2 = MgCl2 + Cd(OH)2 =>
Mg(OH)2 + CdCl2 = MgCl2 + Cd(OH)2

Pb(NO3)2(aq) + KI(aq) = PbI2(s) + KNO3(aw) =>
Pb(NO3)2(aq) + 2 KI(aq) = PbI2(s) + 2 KNO3(aw)

Cu(ii)SO4 + KI = CuI + I2 + K2SO4 =>
2 Cu(ii)SO4 + 4 KI = 2 CuI + I2 + 2 K2SO4

C1H22O11 + O2 = CO2 + H2O =>
C1H22O11 + O2 = CO2 + 11 H2O

CH3NH3PbI3 = CH3NH2 + HI + PbI2 =>
CH3NH3PbI3 = CH3NH2 + HI + PbI2

Nb(NO3)5 + Mg(NO3)2 + C2H6N4O2 + Dy(NO3)3 = Mg097Nb2O6Dy003 + CO2 + N2 + H2O =>
20 Nb(NO3)5 + 970 Mg(NO3)2 + 1266 C2H6N4O2 + 30 Dy(NO3)3 = 10 Mg097Nb2O6Dy003 + 2532 CO2 + 3597 N2 + 3798 H2O

Pb(NO3)2(aq) + KI(aq) = PbI2(s) + KNO3(aw) =>
Pb(NO3)2(aq) + 2 KI(aq) = PbI2(s) + 2 KNO3(aw)

CH3COOH(s) + NaOH(aq) = CH3COONa(aq) + H2O(l) =>
CH3COOH(s) + NaOH(aq) = CH3COONa(aq) + H2O(l)

Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2

Pb + H3PO4 + PbO2 = Pb3(PO4)2 + H2O =>
3 Pb + 4 H3PO4 + 3 PbO2 = 2 Pb3(PO4)2 + 6 H2O

Cu(OH)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + KOH =>
2 Cu(OH)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 4 KOH

HCl + CCaO3 = CaCl2 + H2O + CO2 =>
2 HCl + CCaO3 = CaCl2 + H2O + CO2

AuCl4{-} + SbH3 + OH{-} = Au + Cl{-} + SbO3{-} + H2O =>
8 AuCl4{-} + 3 SbH3 + 27 OH{-} = 8 Au + 32 Cl{-} + 3 SbO3{-} + 18 H2O

HKHF2 = KF + H2 + F2 =>
2 HKHF2 = 2 KF + 2 H2 + F2

AgCl + HNo3 = AgNo3 + HCl =>
AgCl + HNo3 = AgNo3 + HCl

NaOH(aq) + CuBr2(aq) = Cu(OH)2(s) + NaBr(aq) =>
2 NaOH(aq) + CuBr2(aq) = Cu(OH)2(s) + 2 NaBr(aq)

Ni(OH)2 + NH4OH = [Ni(NH3)6] + OH + H =>
Ni(OH)2 + 6 NH4OH = [Ni(NH3)6] + 8 OH + 6 H

Pb(NO3)2 + (NH4)3PO4 = Pb(PO4) + (NH4)3(NO3)2 =>
Pb(NO3)2 + (NH4)3PO4 = Pb(PO4) + (NH4)3(NO3)2

Ba3P2 + HBr = BaBr2 + PH3 =>
Ba3P2 + 6 HBr = 3 BaBr2 + 2 PH3

Zn(NO3)2 + Ba(OH)2 = Ba[Zn(OH)4] + Ba(NO3)2 =>
Zn(NO3)2 + 2 Ba(OH)2 = Ba[Zn(OH)4] + Ba(NO3)2

Hg + HNO3 = Hg2(NO3)2 + H2O + NO =>
6 Hg + 8 HNO3 = 3 Hg2(NO3)2 + 4 H2O + 2 NO

Pr6O11 + HCl + H2 = PrCl3 + H2O =>
Pr6O11 + 18 HCl + 2 H2 = 6 PrCl3 + 11 H2O

Cu(s) + AgC2H3O2(aq) = Cu(C2H3O2)2(s) + Ag(s) =>
Cu(s) + 2 AgC2H3O2(aq) = Cu(C2H3O2)2(s) + 2 Ag(s)

(NH4)2PtCl4 + NH3 = NH4Cl + Pt(NH3)Cl2 =>
(NH4)2PtCl4 + NH3 = 2 NH4Cl + Pt(NH3)Cl2

Cl2 + MgI2 = ClI2 + Mg =>
Cl2 + 2 MgI2 = 2 ClI2 + 2 Mg

MgO + KBr = MgBr2 + K2O =>
MgO + 2 KBr = MgBr2 + K2O

H2O + NH4OH = OH + HNH4OH =>
H2O + NH4OH = OH + HNH4OH

Zn + Hg(NO3)2 = Zn(NO3)2 + Hg =>
Zn + Hg(NO3)2 = Zn(NO3)2 + Hg

Ag(S2O3)2 + I = AgI + S2O3 =>
Ag(S2O3)2 + I = AgI + 2 S2O3

Na + Cl2 = NaCl =>
2 Na + Cl2 = 2 NaCl

Cl2 + CsI = ClI + Cs =>
Cl2 + 2 CsI = 2 ClI + 2 Cs

Na + Cl2 = NaCl =>
2 Na + Cl2 = 2 NaCl

Fe + Pb(SO4)2 = Pb + Fe2(SO4)3 =>
4 Fe + 3 Pb(SO4)2 = 3 Pb + 2 Fe2(SO4)3

NaHCO3 + CH3CO2H = CO2 + CH3CO2Na + H2O =>
NaHCO3 + CH3CO2H = CO2 + CH3CO2Na + H2O

Zn + K4Fe(CN)6 = Zn2Fe(CN)6 + K =>
2 Zn + K4Fe(CN)6 = Zn2Fe(CN)6 + 4 K

HClO4 + P4O10 = H3PO4 + Cl2O7 =>
12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7

BaS2O3 + K3PO4 = Ba3(PO4)2 + K2S2O3 =>
3 BaS2O3 + 2 K3PO4 = Ba3(PO4)2 + 3 K2S2O3

BeCl2 + NaOH = Be(OH)2 + NaCl =>
BeCl2 + 2 NaOH = Be(OH)2 + 2 NaCl

H3PO4 + NaBr = HBr + Na3PO4 =>
H3PO4 + 3 NaBr = 3 HBr + Na3PO4

NaAlH + H2O = Al(OH)3 + NaOH + H2 =>
2 NaAlH + 8 H2O = 2 Al(OH)3 + 2 NaOH + 5 H2

[Cu(H2O)5OH]2SO4 + NH4OH = [Cu(NH3)4OH]2SO4 + H2O =>
[Cu(H2O)5OH]2SO4 + 8 NH4OH = [Cu(NH3)4OH]2SO4 + 18 H2O

CH3COOH + RbOH = CH3COORb + H2O =>
CH3COOH + RbOH = CH3COORb + H2O

Mg + N2 = Mg3N2 =>
3 Mg + N2 = Mg3N2

CS2 + O2 = CO2 + SO4 =>
CS2 + 5 O2 = CO2 + 2 SO4

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Balance the equation of any chemical reaction
 Equations balanced on the previous day Equations balanced on the next day
Equations balanced on 11/26/24
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Equations balanced on 12/03/23
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