| Equations balanced on the previous day |
Na2Cr2O7 + 3 Na2SO3 + 4 H2O = 2 Cr(OH)3 + 2 NaOH + 3 Na2SO4
NH4C2H3O2 + BiSO4 = BiC2H3O2 + NH4SO4 =>
NH4C2H3O2 + BiSO4 = BiC2H3O2 + NH4SO4
CO2 + H2O = C2H126O + O2 =>
2 CO2 + 63 H2O = C2H126O + 33 O2
CO + K2Cr2O7 + H2SO4 = CO2 + K2SO4 + CrSO4 + H2O =>
4 CO + K2Cr2O7 + 3 H2SO4 = 4 CO2 + K2SO4 + 2 CrSO4 + 3 H2O
KIO3 + Mg3(PO4)2 = Mg(IO3)2 + K3PO4 =>
6 KIO3 + Mg3(PO4)2 = 3 Mg(IO3)2 + 2 K3PO4
ZnCo3 + H3Po4 = Zn(Po4)2 + H2 + Co2 =>
2 ZnCo3 + 4 H3Po4 = 2 Zn(Po4)2 + 6 H2 + 3 Co2
CH3OCOOH + O2 = H2O + CO2 =>
2 CH3OCOOH + 3 O2 = 4 H2O + 4 CO2
Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2
Cu(SO4) + Cl2Ba = Ba(SO4) + Cl2Cu =>
Cu(SO4) + Cl2Ba = Ba(SO4) + Cl2Cu
Sn(CO3)2 + Ca(NO3)2 = CaCO3 + Sn(NO3)4 =>
Sn(CO3)2 + 2 Ca(NO3)2 = 2 CaCO3 + Sn(NO3)4
Zn(SO4)2 + CaCl2 = ZnCl2 + Ca(SO4)2 =>
Zn(SO4)2 + CaCl2 = ZnCl2 + Ca(SO4)2
Al2O3 + KOH + Al = KAlO2 + H2 =>
2 Al2O3 + 6 KOH + 2 Al = 6 KAlO2 + 3 H2
NaOH(s) + Al203(s) + H2O(l) = H2(g) + [Al(OH)4]{-} + Na{+} =>
406 NaOH(s) + 2 Al203(s) + 1218 H2O(l) = 609 H2(g) + 406[Al(OH)4]{-} + 406 Na{+}
HCl + Cu(s) = CuCl2(s) + H2(g) =>
2 HCl + Cu(s) = CuCl2(s) + H2(g)
CH3COOH + K = H2(g) + KCH3COO =>
2 CH3COOH + 2 K = H2(g) + 2 KCH3COO
CuSO4*5H2O + NH3 = Cu(NH3)4(SO4)*H2O + H2O =>
CuSO4*5H2O + 4 NH3 = Cu(NH3)4(SO4)*H2O + 4 H2O
NH3 + Zn(OH)2 = OH + Zn(NH3)4 =>
4 NH3 + Zn(OH)2 = 2 OH + Zn(NH3)4
CaO + Mn2O3 + Cr2O3 + ReO2 = CaMnCrReO6 =>
2 CaO + Mn2O3 + Cr2O3 + 2 ReO2 = 2 CaMnCrReO6
Fe(OH)3(s) + CH2O + H3O{+} = Fe2{+} + H2O + CO2(aq) =>
8 Fe(OH)3(s) + 5 CH2O + 4 H3O{+} = 4 Fe2{+} + 23 H2O + 5 CO2(aq)
C2H5Br + H2O = C2H5OH + HBr =>
C2H5Br + H2O = C2H5OH + HBr
V2O5 + HCl = VOCl3 + H2O =>
V2O5 + 6 HCl = 2 VOCl3 + 3 H2O
O2 + C8H16 = H2O + CO2 =>
12 O2 + C8H16 = 8 H2O + 8 CO2
Na2CO3(aq) + CuSO4(aq) = Na2SO4(aq) + Cu2(CO3)2(aq) =>
2 Na2CO3(aq) + 2 CuSO4(aq) = 2 Na2SO4(aq) + Cu2(CO3)2(aq)
Na2SO3 + Zn + H2SO3 = Na2S2O4 + ZnSO3 + H2O =>
Na2SO3 + Zn + 2 H2SO3 = Na2S2O4 + ZnSO3 + 2 H2O
Fe(OH)3 + H{+} = Fe{+3} + H2O =>
Fe(OH)3 + 3 H{+} = Fe{+3} + 3 H2O
H(CN) + CuS04 = H2S04 + Cu(CN)2 =>
2 H(CN) + CuS04 = H2S04 + Cu(CN)2
P4 + H2O = PH3 + H2PO2{-} + H{+} =>
P4 + 6 H2O = PH3 + 3 H2PO2{-} + 3 H{+}
S2O5 + Mg = MgO + S =>
S2O5 + 5 Mg = 5 MgO + 2 S
NaOH + Mg{2+} = Mg(OH){2+} + Na =>
NaOH + Mg{2+} = Mg(OH){2+} + Na
H2C2O4 + Mg = H + MgC2O4 =>
H2C2O4 + Mg = 2 H + MgC2O4
HNO3 + Fe(OH)3 = Fe(NO3)3 + H2O =>
3 HNO3 + Fe(OH)3 = Fe(NO3)3 + 3 H2O
Cu + AgNO3 = Cu(NO3)2 + Ag =>
Cu + 2 AgNO3 = Cu(NO3)2 + 2 Ag
Zn + Sn(C2H3O2)4 = Zn(C2H3O2)2 + Sn =>
2 Zn + Sn(C2H3O2)4 = 2 Zn(C2H3O2)2 + Sn
Na2Cr2O7(s) + HCl(g) = CrO2Cl2(g) + NaCl(s) + H2O(l) =>
Na2Cr2O7(s) + 6 HCl(g) = 2 CrO2Cl2(g) + 2 NaCl(s) + 3 H2O(l)
An2O3 + As2O5 = AnAsO4 =>
An2O3 + As2O5 = 2 AnAsO4
Ca3(PO4)2 + SiO2 + CO = P4 + CaSiO3 + CO2 =>
2 Ca3(PO4)2 + 6 SiO2 + 10 CO = P4 + 6 CaSiO3 + 10 CO2
Pb3N2 + HNO3 = Pb(NO3)2 + NH3 =>
Pb3N2 + 6 HNO3 = 3 Pb(NO3)2 + 2 NH3
OH + NH3 = N2H4 + H2O =>
2 OH + 2 NH3 = N2H4 + 2 H2O
Fe(SO4) + Ce = Ce(SO4)2 + Fe =>
2 Fe(SO4) + Ce = Ce(SO4)2 + 2 Fe
Br2 + NaOH = NaBr + NaBrO3 + H2O =>
3 Br2 + 6 NaOH = 5 NaBr + NaBrO3 + 3 H2O
Ca2Fe4AlOH2AlSi7O22 + H2O + O2 + H{+} = Al2Si2O5(OH)4 + Fe2O3 + Ca{2+} + H4SiO4 =>
2 Ca2Fe4AlOH2AlSi7O22 + 18 H2O + 3 O2 + 8 H{+} = 2 Al2Si2O5(OH)4 + 4 Fe2O3 + 4 Ca{2+} + 10 H4SiO4
CS(g) + O2(g) = SO3 + CO =>
CS(g) + 2 O2(g) = SO3 + CO
CO + KMnO4 + H2SO4 = K2SO4 + Mn(SO4)2 + CO2 + H2O =>
3 CO + 2 KMnO4 + 5 H2SO4 = K2SO4 + 2 Mn(SO4)2 + 3 CO2 + 5 H2O
((NH4)3PO4) = (H3PO4) + (NH3) =>
((NH4)3PO4) = (H3PO4) + 3(NH3)
CoCl2 + Cl = CoCl4 =>
CoCl2 + 2 Cl = CoCl4
Fe(s) + CuBr2(aq) = FeBr3 + Cu =>
2 Fe(s) + 3 CuBr2(aq) = 2 FeBr3 + 3 Cu
MgCl + NaCO = MgCO + NaCl =>
MgCl + NaCO = MgCO + NaCl
NH4CH3COO + KNO3 = NH4NO3 + KCH3COO =>
NH4CH3COO + KNO3 = NH4NO3 + KCH3COO
Cr(OH)2 + K2S2O8 = CrO2 + KHSO4 =>
Cr(OH)2 + K2S2O8 = CrO2 + 2 KHSO4
Fe + Pb(C2H3O2)2 = Fe(C2H3O2)3 + Pb4 =>
8 Fe + 12 Pb(C2H3O2)2 = 8 Fe(C2H3O2)3 + 3 Pb4
Balance the equation of any chemical reaction
| Equations balanced on the previous day |
Equations balanced on 01/27/25
Equations balanced on 02/26/24
Please let us know how we can improve this web app.
